Please help me solve this question

Answers

Answer 1

Answer:

The fraction is equal 0 if the numerator is equal 0.

$(12)/(x(x+8))=0\iff12=0\ FALSE$

Therefore your answer is 1. 0

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Answers

Answer:

the answer is 01

Step-by-step explanation:

Answer:

Step-by-step explanation:

Which equation can be used to find one multiple of 16?

Answers

m(n)=16n where n is a natural number
m(n)=multipules of 16

Publishing scientific papers online is fast, and the papers can be long. Publishing in a paper journal means that the paper will live forever in libraries. The British Medical Journal combines the two; it prints short and reasonable versions, with longer versions available online. Is this OK with authors? The journal asked about a random sample of 104 of its recent authors' several questions. One question was, "Should the journal continue using this system?"
In the sample, 72 said "yes."
(a) do the data give good evidence that more than two-thirds (67%) of authors support continuing this system? carry out an appropriate test to help answer this question.
(b) interpret the p-values from your test in the context of the problem.

Answers

Answer:

There is no significant evidence that more than two-thirds (67%) of authors support continuing this system.

Step-by-step explanation:

Let p be the proportion of authors who support continuing the system

Then hypotheses are:

$H_(0)$ : p=0.67

$H_(a)$ : p>0.67

To calculate the test statistic:

z= $\frac{p(s)-p}{\sqrt{(p*(1-p))/(N) } }$ where

p(s) is the sample proportion of authors who support the publishing system ( $(72)/(104)$ ≈0.692)

p is the proportion assumed under null hypothesis. (0.67)

N is the sample size (104)

Then z= $\frac{0.692-0.67}{\sqrt{(0.67*0.33)/(104) } }$ ≈ 0.477

p-value of test statistic is ≈0.317

Assuming a significance level 0.05, since 0.317>0.05 we fail to reject the null hypothesis.

p-value 0.317 is the probability that the sample is drawn from the distribution assumed under null hypothesis, that is where the proportion of authors supporting the new publishing system is at most 0.67

Final answer:

A hypothesis test for a proportion is used to determine whether more than two-thirds of authors support continuing the system. The p-value associated with the test is less than 0.0001, indicating that the data provide good evidence in favor of the alternative hypothesis. Therefore, the majority of authors support continuing the system.

Explanation:

To determine whether the data provides evidence that more than two-thirds (67%) of authors support continuing the system, we can use a hypothesis test for a proportion. We will use a significance level of 0.05.

Let's set up our hypotheses:

Null hypothesis (H0): p ≤ 0.67 (less than or equal to two-thirds support)
Alternative hypothesis (Ha): p > 0.67 (more than two-thirds support)

Using the normal approximation to the binomial, we can calculate the test statistic and p-value. With a sample size of 104 and 72 authors in favor, the test statistic is:

z = (72 - 0.67 * 104) / sqrt(0.67 * (1 - 0.67) * 104) ≈ 3.79

The p-value associated with a z-score of 3.79 is less than 0.0001. Since this p-value is less than 0.05, we reject the null hypothesis.

Therefore, the data provide good evidence that more than two-thirds of authors support continuing the system.

Learn more about Hypothesis testing here:

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What is the domain (in interval notation) of the following functions?1. g(x)=3/(5x-4)
2. h(x)=√(x)/(x-5)
3. f(x)=√(x)/(x^2-5x)
4. g(x)=(√(x)+5)/(x^2-x-20)
5. h(x)=3/(x^2+1)
6. f(x)=(√(x-2))/(x+1)
7. g(x)= x^2/(3x^2-x-2
8. h(x)=3(x-4)^2-7
Number sets in parenthesis are either on top of or beneath the fraction bar and ^2 here represents a number squared.

Answers

$1.\ng(x)=(3)/(5x-4)\n\nD:5x-4\neq0\to5x\neq4\ \ \ /:5\to x\neq(4)/(5)\to x\in\mathbb{R}\ \backslash\ \{(4)/(5)\}\n\n2.\nh(x)=(√(x))/(x-5)\n\nD:x\geq0\ \wedge\ x-5\neq0\to x\geq0\ \wedge\ x\neq5\to x\in\left<0;\ \infty\right)\ \backslash\ \{5\}$

$3.\nf(x)=(√(x))/(x^2-5x)\n\nD:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\n\n\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\n\n4.\ng(x)=(√(x)+5)/(x^2-x-20)\n\nD:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\n\n\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left<0;\ \infty\right)\ \backslash\ \{-4;\ 5\}$

$5.\nh(x)=(3)/(x^2+1)\n\nD:x^2+1\neq0\to x^2\neq-1\to x\in\mathbb{R}\n\n6.\nf(x)=(√(x-2))/(x+1)\n\nD:x-2\geq0\ \wedge\ x+1\neq0\to x\geq2\ \wedge\ x\neq-1\to x\in\left<2;\ \infty\right)$

$7.\ng(x)=(x^2)/(3x^2-x-2)\n\nD:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-(2)/(3)\ \wedge\ x\neq1\n\n\to x\in\mathbb{R}\ \backslash\ \{-(2)/(3);\ 1\}\n\n8.\nh(x)=3(x-4)^2-7\n\nD:x\in\mathbb{R}$

What's the value of log2 (1/8) ?

Answers

$log_aa^p=p\n------\n\nlog_2 ( (1)/(8) ) =log_28^(-1)=log_2(2^3)^(-1)=log_22^(-3)=-3\n\nAns.\ -3$

The correct answer for the value $log_(2)(1)/(8)$ is equal to -3.

What is Logarithm?

In mathematics, Logarithms are defined a way of expressing exponents. A logarithm is defined as the power to which a number must be raised to get some other values.

The expression for logarithm of a number is written as ㏒ₓb = y.

Properties of Logarithm:

$log_(x) (x^n) = n$

The value of $log_(2)(1)/(8)$ can be calculated by recognizing that $(1)/(8)$ is equal to 2 raised to the power of -3.

$log_(2)(1)/(8)$ = $log_(2)(2^(-3))$

From the property of logarithm:

$log_(2)(2^(-3))$

= -3

The value of $log_(2)(1)/(8)$ is -3.

Learn more about Logarithm here:

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Two standard number cubes are thrown simultaneously. What is the probability that the combined result of the two cubes is exactly 7, or that it is less than (but not equal to) 6? Round answer to the nearest thousandth. A. 0.444. B. 0.556. C. 0.667. D. 0.853

Answers

Probability = Desired outcomes ( m ) / Possible outcomes ( n )
Desired outcomes:
1 + 1, 1 + 2, 1 + 3, 1 + 4, 1 + 6,
2 + 1 , 2 + 2, 2 + 3, 2 + 5,
3 + 1, 3 + 2, 3 + 4,
4 + 1, 4 + 3
5 + 2,
6 + 1.
m = 16
Possible outcomes : 6² = 36, n = 36
P ( A ) = 16/ 36 = 0.4444...≈ 0.444
Answer: A ) 0.444

1 + 1, 1 + 2, 1 + 3, 1 + 4, 1 + 6,

2 + 1 , 2 + 2, 2 + 3, 2 + 5,

3 + 1, 3 + 2, 3 + 4,

4 + 1, 4 + 3

5 + 2,

6 + 1.

m = 16

Possible outcomes : 6² = 36, n = 36

P ( A ) = 16/ 36 = 0.4444...≈ 0.444

Answer: A ) 0.444

Hope I helped!