MATHEMATICS COLLEGE

The Schuller family has five members. Dad is 6ft 2in tall. Mom is 3 inches shorter than Dad, but 2 inches taller than Ivan. Marcia is 5 inches shorter than Ivan, but twice as tall as Sally-Jo. What is the mean height of the Schuller family?

Answers

Answer 1

Answer:

Answer:

Mean = 5 feet 2 inches.

Step-by-step explanation:

1 feet = 12 inches

Height of Dad = 6 feet 2 inches = {(6 × 12)+2} = 74 inches

Mom is 3 inches shorter than dad = 74 - 3 = 71 inches (5 ft 11 in)

Since mom is 2 inches taller than Ivan,

Height of Ivan = 71 - 2 = 69 inches (5 ft 9 in)

Marica is 5 inches shorter than Ivan,

Height of Marica = 69 - 5 = 64 inches (5 ft 4 in)

Marica is twice as tall as Sally-Jo.

Height of Sally-Jo = 64 ÷ 2 = 32 inches (2 ft 8 in)

Hence the mean height of the Schuller family

= $(74+71+69+64+32)/(5)$

= 62 inches

converting 62 inches to feet = $(62)/(12)$ = 5 feet 2 inches

Mean height of the Schuller family is 5 feet 2 inches.

Related Questions

James Priya and Siobhan work in a grocery store James makes 9.00!per hour Priya makes 40% more than James and Siobhan makes 15% less than priya how much does Siobhan make per hour
At the end of the day of teaching the skill of cutting and sewing to make capes, Ms. Ironperson and Mr. Thoro decided to go to the Shawarma Mediterranean Grill. Ms. Ironperson ordered 3 chicken shawarma wraps and 2 orders of spiced potatoes for a total bill of $42.95. Mr. Thoro ordered 5 chicken shawarma wraps and 4 orders of spiced potatoes for a total bill of $74.91. What is the cost of a chicken shawarma wrap? What is the cost of one order of spiced potatoes? If x denotes the cost of a chicken shawarma wrap and y denotes the cost of an order of spiced potatoes, what are the equations needed to solve this problem?
Kenny has a jar full of nickels and dimes. If he counted the money in his jar, how much does he have ?
Ramona went to a theme park during spring break. She was there for 7 hours and rode 14 rides. At what rate did Ramona ride rides in rides per hour?
3/4x = 1/5 .x = Pls help I will give brainliest

Ashley, Milan, and Carlos sent a total of 131 text messages over their cell phones during the weekend. Carlos sent 7 times as many messages as Ashley. Ashley sent 4 more messages than Milan. How many messages did they each send?

Answers

Answer:

Ashley= 15

Milan= 11

Carlos= 105

Step-by-step explanation:

Let, A, M and C denotes Ashley, Milan and Carlos respectively.

A+M+C= 131 (according to the question)

Here,

C= 7A

A= M+ 4

So, M= A - 4

Now,

A+M+C = 131

or, A+ A-4+ 7A = 131 (putting the values)

or, 9A - 4 = 131 (adding like terms i.e. A + A + 7A)

or, 9A = 131 + 4

or, 9A = 135

or, A = 135 / 9

So, A = 15

C= 7A = 7×15= 105

M= A-4 = 15 - 4 = 11

Find the square root of 6.4 upto two decimal place

Answers

Answer:

2.53

Step-by-step explanation:

Consider the following function. f ( x ) = 1 − x 2 / 3 Find f ( − 1 ) and f ( 1 ) . f ( − 1 ) = f ( 1 ) = Find all values c in ( − 1 , 1 ) such that f ' ( c ) = 0 . (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) c = Based off of this information, what conclusions can be made about Rolle's Theorem? This contradicts Rolle's Theorem, since f ( − 1 ) = f ( 1 ) , there should exist a number c in ( − 1 , 1 ) such that f ' ( c ) = 0 . This does not contradict Rolle's Theorem, since f ' ( 0 ) = 0 , and 0 is in the interval ( − 1 , 1 ) . This does not contradict Rolle's Theorem, since f ' ( 0 ) does not exist, and so f is not differentiable on ( − 1 , 1 ) . This contradicts Rolle's Theorem, since f is differentiable, f ( − 1 ) = f ( 1 ) , and f ' ( c ) = 0 exists, but c is not in ( − 1 , 1 ) . Nothing can be concluded.

Answers

Answer:

(E)Nothing can be concluded.

Step-by-step explanation:

Given the function $f(x)=1-x^{(2)/(3)}$

$f(-1)=1-(-1)^{(2)/(3)}=1.5-0.86603i\nf(1)=1-1^{(2)/(3)}=1-1=0$

$f'(x)=-(2)/(3)x^{-(1)/(3)}\nf'(x)=-\frac{2}{3\sqrt[3]{x} }$

If the derivative is set equal to zero, the function is undefined.

Nothing can be concluded since $f(1)\neq f(-1)$ and no such c in (-1,1) exists such that $f'(c)=0$

THEOREM

Rolle's theorem states that any real-valued differentiable function that attains equal values at two distinct points must have at least one stationary point somewhere between them—that is, a point where the first derivative is zero.

Final answer:

The function f(x) = 1 - x^2/3 has f(-1) = f(1) = 2/3. The derivative f'(x) = -2x/3 equals zero at x=0, which is in the interval (-1, 1). Therefore, this does not contradict Rolle's Theorem.

Explanation:

The function given is f ( x ) = 1 - x ^ 2 /3. To find the values f(-1) and f(1), we simply substitute these values into the function. Therefore, f(-1) = 1 - (-1) ^ 2 /3 = 1 - 1/3 = 2/3 and f(1) = 1 - 1^2/3 = 2/3. As you can see, f(-1) = f(1).

Now, to find the value 'c' such that f'(c) = 0, first we need to determine the derivative of the function, f'(x) = -2x/3. Setting this equal to zero gives the equation 0 = -2x/3, which has the solution x = 0. Therefore, f'(c) = 0 at c = 0, which is within the interval (-1, 1).

Finally, regarding Rolle's Theorem which states that if a function is continuous on the closed interval [a, b], differentiable on the open interval (a, b), and f(a) = f(b), then there exists at least one c in the interval (a, b) such that f'(c) = 0, our results are consistent with Rolle's Theorem, since f is differentiable, f(-1) = f(1), and a 'c' value exists in the interval (-1, 1) such that f'(c) = 0.