What is X divided by 2?

Answers

Answer 1

Answer: x/2 is the same thing as 1/2x

--Hope This Helps--

Related Questions

Margaritas is a very popular restaurant. Occasionally, the restaurant provides lunch and/or dinner for a local charity house. Each lunch costs $6.50. Each dinner costs $10.25. The restaurant's expenses for providing the meals cannot exceed $1,183 per trimester. If x represents the number of lunches and y represents the number of dinners, what domain best fits the situation
Question 2(Multiple Choice Worth 4 points)(02.01 LC) Figure EFGHK as shown below is to be transformed to figure E'F'G'H'K' using the rule (x, y) (x+8, y + 5):
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50% of what number is 90?
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How to estimate 518 + 372

Answers

Answer:

900

Step-by-step explanation:

518+372

We have to find the result by estimation

Estimate both the numbers to nearest hundreds

518 is estimated to nearest hundred= 500

372 is estimated to nearest hundred= 400

After adding, 500 and 400, we get

500+400=900

we get our answer 900

Hence, the correct answer is 900

It is 890 but if you estimate it would be 900

The length of the day in Lagos, Nigeria (in minutes), t days since the beginning of the year can be estimated bythis formula:
L(t) = 727+22 sin
26(t - 80.75)
365
When is the longest day of the year? Give an exact answer.
days since the beginning of the year

Answers

Answer:172 days

Step-by-step explanation:

What is the value of X in this proportion? (image of the proportion included)

Answers

X = 5
4x/50 = 2/x take 4x and multiply it by the denominator in the other fraction it = 4x^2 do the same for the 2 &50 you get 100 now you have 4x^2=100 take the 4 divide it on both sides so 4/4=0 and 4/100=25 now you have
x^2=25 find the square root of 25= (5) so X=5

u have to cross multiply. (multiply 4x by x and 50 by 2)

What does the math term pie equal

Answers

Approximately = 3.14

Hope this helps!

it is pi and it equals 3.14159265359 hope this helps hope i am brainliest

A house cost $120,000 when it was purchased. The value of the house increases by 10% each year. Find the rate of growth each month.

Answers

FIRST MODEL:

Well the model for the value of the house is:

$V={ \left( \frac { 11 }{ 10 } \right) }^( t )\cdot 120000$

V = Value

t = Years passed {t≥0}

-----------------------

When t=0, V=120000

When t=1, V=132000

When t=2, V=145200

etc... etc...

---------------------------

Now, this model is actually curved so there is no constant rate of growth each month. We can only calculate what the rate of growth is at a particular time. If we want to find out the rate of growth at a particular time, we must differentiate the formula (model) above.

--------------------------

$V={ \left( \frac { 11 }{ 10 } \right) }^( t )\cdot 120000\n \n \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^( t )\cdot 120000 \right) } }$

$\n \n \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^( t ) \right) } } +\ln { \left( 120000 \right) } \n \n \ln { V=t\ln { \left( \frac { 11 }{ 10 } \right) } } +\ln { \left( 120000 \right) }$

$\n \n \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \n \n V\cdot \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \cdot V$

$\n \n \therefore \quad \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \cdot { \left( \frac { 11 }{ 10 } \right) }^( t )\cdot 120000$

Plug any value of (t) that is greater than 0 into the formula above to find out how quickly the investment is growing. If you want to find out how quickly the investment was growing after 1 month had passed, transform t into 1/12.

The rate of growth is being measured in years, not months. So when t=1/12, the rate of growth turns out to be 11528.42 per annum.

SECOND MODEL (What you are ultimately looking for):

$V={ \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000$

V = Value of house

t = months that have gone by {t≥0}

Formula above differentiated:

$V={ \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000\n \n \ln { V } =\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000 \right) }$

$\n \n \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } } \right) } } +\ln { \left( 120000 \right) }$

$\n \n \ln { V=\frac { t }{ 12 } } \ln { \left( \frac { 11 }{ 10 } \right) } +\ln { \left( 120000 \right) }$

$\n \n \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) }$

$\n \n V\cdot \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) } \cdot V$

$\n \n \therefore \quad \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) } \cdot { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000$

When t=1, dV/dt = 960.70 (2dp)

dV/dt in this case will measure the rate of growth monthly. As more money is accumulated, this rate of growth will rise. The rate of growth is constantly increasing as the graph of V is actually a curve. You can only find out the rate at which the house value is growing monthly at a particular time.

Consider the figure shown. Classify each of the following statements as always true, sometimes true, or never true.m<1+m<4=180
m<1+m<2+m<3=180
m<2+ m<4=180
<2=<3
<2=<4
m<3=m<4

Answers

Answer:

Step-by-step explanation:

Let's analyze each statement and classify them as always true, sometimes true, or never true based on the figure provided:

1. m<1+m<4=180:

This statement is always true. In the figure, angles 1 and 4 are vertical angles, which means they are congruent. Therefore, m<1 = m<4, and their sum is always equal to 180 degrees.

2. m<1+m<2+m<3=180:

This statement is never true. In the figure, angles 1, 2, and 3 do not form a straight line. Therefore, the sum of m<1, m<2, and m<3 cannot be equal to 180 degrees.

3. m<2+ m<4=180:

This statement is sometimes true. In the figure, angles 2 and 4 are adjacent angles, and their sum can be equal to 180 degrees if they form a straight line. However, if angles 2 and 4 do not form a straight line, their sum will be less than 180 degrees.

4. <2=<3:

This statement is never true. In the figure, angles 2 and 3 are not congruent. Therefore, <2 is not equal to <3.

5. <2=<4:

This statement is sometimes true. In the figure, angles 2 and 4 can be congruent if they are vertical angles. However, if they are not vertical angles, they will not be congruent.

6. m<3=m<4:

This statement is always true. In the figure, angles 3 and 4 are vertical angles, which means they are congruent. Therefore, m<3 = m<4.

To summarize:

- Statement 1 is always true.

- Statement 2 is never true.

- Statement 3 is sometimes true.

- Statement 4 is never true.

- Statement 5 is sometimes true.

- Statement 6 is always true.

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6. The equation of line A is 3x + 6y - 1 = 0. Give the equation of a line that passes through thepoint (5,1) that is/1 a. Perpendicular to line AAnswer:/1 b. Parallel to line AAnswer: