Question 8 of 20 Select the best answer for the question.8. Simplify 2a2b (4a2 3ab2 ab)4654 32a bBackNextReview Answer Selections
Question 8 of 20 Select the best answer for the - 1

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Answer 1
Answer: Simplify 2a2b (4a2 3ab2 ab)4654 32a b. Your answer is C

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Help pls! ill mark brainliest if correct

a football is selling for 35% off the original price. the original price was $60. what is the sale price of the football.

Answers

The percentage is calculated by dividing the required value by the totalvalue and multiplying by 100.

Example:

Requiredpercentage value = a

totalvalue = b

Percentage = a/b x 100

100% = $60

35% = $21

The saleprice of the football is $21

What is a percentage?

The percentage is calculated by dividing the required value by the totalvalue and multiplying by 100.

Requiredpercentage value = a

totalvalue = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Originalprice = $60

Sellingprice.

= 35% of $60

= 35/100 x 60

= 7 x 3

= $21

We can also find this way.

100% = $60

35% = 35/100 x $60

35% = $21

Thus,

100% = $60

35% = $21

The saleprice of the football is $21

Learn more about percentages here:

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35% is the same as 0.35
The word "of" in math basically means multiply.
So if 0.35 of 60 is how much is off the original price, then you multiply 0.35 by 60.
=21. So 21 is how much you save. Take 60 and subtract 21 is the answer.
ANSWER: 39
Hope this helped!!

What is 39/40 simplified

Answers

It cannot be simplified,
but in decimal it is
0.975

Simplify the expression

Answers

Answer:

The simplified form of given expression\frac{15xy}{5x^{(1)/(2)}y^2} is \frac{3x^{(1)/(2)}}{y}

Step-by-step explanation:

Given: Expression \frac{15xy}{5x^{(1)/(2)}y^2}

We have to write the given expression in simplified form,

Consider the given expression \frac{15xy}{5x^{(1)/(2)}y^2}

Divide the numbers (15)/(5)=3

we get,

=\frac{3xy}{y^2x^{(1)/(2)}}

Apply exponent rule , (x^a)/(x^b)\:=\:x^(a-b)

\frac{x}{x^{(1)/(2)}}=x^{1-(1)/(2)}=x^{(1)/(2)}

we get,

=\frac{3yx^{(1)/(2)}}{y^2}

Cancel y term, we have,

=\frac{3x^{(1)/(2)}}{y}

Thus, The simplified form of given expression\frac{15xy}{5x^{(1)/(2)}y^2} is \frac{3x^{(1)/(2)}}{y}

Answer:

3x^{(1)/(2)}y^(-1)

Step-by-step explanation:

The given expression is:

\frac{15xy}{5x^{(1)/(2)}y^2}

We have to simplify the above given expression.Thus,

Firstly, divide the constant terms, we get

(15)/(5)=3

Now, applying the exponent law, that is (x^a)/(x^b)=x^(a-b), we have

\frac{xy}{x^{(1)/(2)}y^2}=x^{1-(1)/(2)}y^(1-2)=x^{(1)/(2)}y^(-1)

Thus, the simplified form of the above given equation is:

3x^{(1)/(2)}y^(-1)

(9 – 6i) × m = 9 – 6i What is m?

a. 0

b. 1

c. 9 + 6i

d. -9 + 6i

Answers

An equation is formed of two equal expressions. In the given equation (9–6i)×m = 9–6i, the value of m is 1.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

In the given equation (9–6i)×m = 9–6i, the value of m can be found as,

(9–6i)×m = 9–6i

Divide both the sides of the equation by (9–6i),

((9-6i)* m )/((9-6i))= ((9-6i))/((9-6i))\n

m = 1

Hence, In the given equation (9–6i)×m = 9–6i, the value of m is 1.

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B) 1 because anything times one equals that same number and so 9-6ix1=9-6i
I hope this helped

3 times 7 plus 4 to the second power minus 14 divided by 2

Answers

3 times 7 plus 4 to the second power minus 14 divided by 2
=> 3 x 7 + 4^2 - 14 / 2
Let's group this one.
=> (
3 x 7) + 4^2 - (14 / 2)
=> 21 + 16 - 7
=> 30
The answer is 30.
It's 29 not thirty some thing was done wrong to get 30

A plane, parallel to the base of a cone intersects the cone at the midpoint between points A and B. Determine the area of the cross-section formed by the intersection of the plane and the cone. Leave your answer in terms of pi. 2o height 6 radiusA) 1.5π in2
Eliminate
B) 3π in2
C) 9π in2
D) 36π in2

Answers

Answer:

Area of cross-section is9\pi in^(2)

Step-by-step explanation:

Given a cone and a plane parallel to base intersect the cone at the mid point of points between A and B.

We have to find the area of cross-section formed by intersection of the plane and the cone which is a new circle formed.

Given,   height=20 in

             radius=6 in

By mid point theorem i.e the line segment formed by joining the mid points of two side of triangle is parallel to third equal to half of the third side.

therefore new circle formed is of radius 3 in

Hence, area of cross-section formed by intersection of the plane and the cone which is a new circle formed= \pir^(2)

                                                        = 3^(2)\pi

                                                        =9\piin^(2)