Help pls! ill mark brainliest if correct

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Answer 1

Answer:

I can help you can count on me! you can trust me!

22.6 is an outlier for the second data set. The reason for this is that 22.6 is nowhere near the rest of the data points. Outliers are numbers that are either a lot bigger or a lot smaller than the rest of the other numbers in the set. In this case, 22.6 is a lot bigger.

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Name the polar coordinates for the point below.

Answers

Each division in the angle measures 15 degrees and the point is in the second line so it has an angle of 30 degrees. Assuming that the graduation from the origin represents 1 radius unit, then the point is 3 units from the origin. The polar coordinates are
(3, 30°) or (3, π/3)

A pizzeria makes brick-oven pizzas that are shaped like long rectangles with semi-circles at two ends. The pizzas come in three different sizes, which are measured by the longer side of each rectangle: 14 inches, 18 inches, and 29 inches. All of the pizzas are 10 inches wide, so the semi-circles at the ends have diameters of 10 inches, too. What is the area of each pizza? Use 3.14 for ? , and round your answers to the nearest tenth if necessary.

Answers

Answer:

Area of pizza whose longer side is of length is 14 inches = 218.5 $inches^(2)$

Area of pizza whose longer side of rectangle is 18 inches=258.5 $inches^(2)$

Area of pizza whose longer side is of length is 29 inches = 368.5 $inches^(2)$

Step-by-step explanation:

Given A pizzeria makes brick-oven pizzas that are shaped like long rectangles with semi-circles at two ends. The pizzas come in three different sizes, which are measured by the longer side of each rectangle: 14 inches, 18 inches, and 29 inches. All of the pizzas are 10 inches wide, so the semi-circles at the ends have diameters of 10 inches. we have to find the area of each pizza.

First, let us find the area of pizza whose longer side of rectangle is 14 inches

Area of 2 semicircles whose diameter is 10 inches

$=2((1)/(2)\pi r^(2))=\pi r^(2)=3.14* 5 * 5 = 78.5 inches^(2)$

Length = 14 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $14* 10=140 inches^(2)$

∴ Area of pizza whose longer side is of length is 14 inches = Area of rectangle + area of 2 semicircles

=140+78.5=218.5 $inches^(2)$

Now, let us find the area of pizza whose longer side of rectangle is 18 inches

Length = 18 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $18* 10=180 inches^(2)$

∴ Area of pizza whose longer side is of length is 18 inches = Area of rectangle + area of 2 semicircles

=180+78.5=258.5 $inches^(2)$

Now, let us find the area of pizza whose longer side of rectangle is 29 inches

Length =29 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $29* 10=290 inches^(2)$

∴ Area of pizza whose longer side is of length is 29 inches = Area of rectangle + area of 2 semicircles

=290+78.5=368.5 $inches^(2)$

Final answer:

To calculate the area of pizzas shaped like rectangles with semi-circular ends, we calculate the area of the rectangle and adjacent semi-circles separately then sum both. The rectangle's area is calculated as length times width while the semi-circle area is calculated as half of (pi*radius^2).

Explanation:

The area of a pizza that's shaped like a long rectangle with semi-circles at the ends can be calculated by first looking at the rectangle and then the semi-circles. For the rectangles, we use the formula for the area of a rectangle that is, length multiplied by width.

For the 14 inch pizza, the rectangle part:
Area = Length x Width = 14 x 10 = 140 square inches

The area of the semi-circle can be calculated as Area=1/2πr². The diameter is given as 10. So, the radius (r) will be half of the diameter, which is 5. Therefore, Area of each semi-circle = 1/2 x π x 5² = 1/2 x 3.14 x 25 = 39.25 square inches. The combined area of two such semi-circles will be = 39.25 x 2 = 78.5 square inches.

Adding the area for the rectangle and the semi-circles, the total area of each pizza will be 140 + 78.5 = 218.5 square inches.

Following these same steps, we can calculate the areas for the 18 inch and 29 inch pizzas.

Learn more about Area of a pizza here:

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Simplify (6x2 − 3 + 5x3) − (4x3 − 2x2 − 16).2x3 − x2 + 21
−2x3 + x2 − 21
x3 + 8x2 + 13
−x3 − 8x2 + 13

Answers

If you would like to simplify (6x^2 − 3 + 5x^3) − (4x^3 − 2x^2 − 16), you can calculate this using the following steps:

(6x^2 − 3 + 5x^3) − (4x^3 − 2x^2 − 16) = 6x^2 − 3 + 5x^3 − 4x^3 + 2x^2 + 16 = x^3 + 8x^2 + 13

The correct result would be x^3 + 8x^2 + 13.

Answer:

Simplified form of $(6x^(2)-3+5x^(3))-(4x^(3)-2x^(2)-16)$ is $1x^(3)+8x^(2)+13$ .

Step-by-step explanation:

As given the expression

$= (6x^(2)-3+5x^(3))-(4x^(3)-2x^(2)-16)$

Now open the bracket

$= 6x^(2)-3+5x^(3)-4x^(3)+2x^(2)+16$

$= 1x^(3)+8x^(2)+13$

Therefore the simplified form of $(6x^(2)-3+5x^(3))-(4x^(3)-2x^(2)-16)$ is $1x^(3)+8x^(2)+13$ .

An engineer on the ground is looking at the top of a building the angle of elevation to the top of the building is 22 degrees the engineer knows the building is 450 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

Answers

Answer:

1114 foot

Step-by-step explanation:

Let the engineer is at a distance of x feet from the base of the building.

Please see the attached image.

In the triangle, we have

$\tan22^(\circ)=(450)/(x)$

Solving the equation for x, we get

$x=(450)/(\tan22^(\circ))\n\nx\approx1114$

Thus, the engineer is 1114 foot from the base of the building.

Hello,

tan 22°=450/d
==>d=450/tan 22°=1113.7890... ≈1114 (ft)

Draw the line AB and AC. Are the lines the same? Explain Draw the line segment AC and BD are the segments the same? Explain

Draw the rays CA and CB. Are the rays the same? Explain

Answers

Answer:

No they are not the same because.....

Step-by-step explanation:

-7(1+7n)=36-6n this is a very hard solving equations question I don't get HELP!!!

Answers

n=-1 distribute then isolate your variable and divide

-7(1 + 7n) = 36 - 6n
-7(1) - 7(7n) = 36 - 6n
-7 - 49n = 36 - 6n
   +49n    +49n
   -7 = 36 + 43n
   -36   -36
      -43 = 43n
   43    43
      -1 = n

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