b. fission
c. physical
d. chemical
B. nitrogen (N), bismuth (Bi), antimony (Sb)
C. antimony (Sb), nitrogen (N), bismuth (Bi)
D. bismuth (Bi), antimony (Sb), nitrogen (N)
Answer: Option (A) is the correct answer.
Explanation:
Nitrogen is a non-metal and it is known that non-metals do not conduct electricity. Thus, it will be least conductive out of the given options.
Whereas antimony (Sb) is a metalloid. Metalloid are the substance that show properties of both metals and non-metals. Thus, antimony will conduct electricity.
On the other hand, bismuth (Bi) is a metal hence, it will conduct electricity.
Thus, we can conclude that the order from least conductive to most conductive will be nitrogen (N), antimony (Sb), bismuth (Bi).
Answer: The correct answer is Option A.
Explanation:
Conductivity of an element is defined as the tendency to conduct electricity. This property is shown mostly by metals and then by some metalloids and least by non-metals.
Metals are defined as the elements which loose electrons easily and thus can easily conduct electricity due to the presence of free electrons.
Metalloids are defined as the elements which show the properties of both metals and non-metals. Some metalloids are conductive, some are not.
Non-metals are defined as the elements which gain electrons easily and thus cannot conduct electricity easily and are considered as non-conductive.
From the given options:
All the three elements belong to same group but nitrogen is a non-metal, antimony is a metalloid and Bismuth is a metal.
Thus, the order of conductivity follows:
Hence, the correct answer is Option A.
The total number of moles of atoms in Pb(C₂H₃O₂)₂ is 66.242 x 10²³ atoms.
The total number of moles of atoms, use Avogadro's number, which is approximately 6.022 x 10²³ particles (atoms or molecules) per mole.
The molecular formula of Pb(C₂H₃O₂)₂ has one lead (Pb) atom, two carbon (C) atoms, four hydrogen (H) atoms, and four oxygen (O) atoms in one molecule of the compound.
So, the total number of moles of atoms in one mole of Pb(C₂H₃O₂)₂ can be calculated as follows:
1 Pb atom x (1 mole Pb / 1 mole Pb(C₂H₃O₂)₂ x (6.022 x 10²³ atoms / 1 mole Pb) = 6.022 x 10²³ Pb atoms
2 C atoms x (1 mole C / 1 molePb(C₂H₃O₂)₂ x (6.022 x 10²³ atoms / 1 mole C) = 12.044 x 10²³ C atoms
4 H atoms x (1 mole H / 1 mole Pb(C₂H₃O₂)₂ x (6.022 x 10²³ atoms / 1 mole H) = 24.088 x 10²³ H atoms
4 O atoms x (1 mole O / 1 mole Pb(C₂H₃O₂)₂ x (6.022 x 10²³ atoms / 1 mole O) = 24.088 x 1023 O atoms.
6.022 x 10²³ Pb atoms + 12.044 x 10² C atoms + 24.088 x 10²³ H atoms + 24.088 x 10²³ O atoms = 66.242 x 10²³ atoms
Therefore, there are approximately 66.242 x 10²³ atoms in one mole of Pb(C₂H₃O₂)₂.
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The current that is associated downslope movements of dense sediment-rich water is turbidity current.
A turbidity current is most typically termed when an underwater current of usually rapidly moving, which has high sediment-laden water which is movies down a slope.
Turbidity currents is mostly caused by earthquakes, or collapsing slopes, or any other geological disturbances.
Show, or explain, all of your work along with the final answer.