CHEMISTRY COLLEGE

A well-insulated tank contains concentrated HCl solution in water. If more water is added to this tank the temperature of the system will __________.Select one:

a. increase

b. decrease

c. no change

d. cannot tell

Answers

Answer 1
Answer:

Answer: Option (a) is the correct answer.

Explanation:

As the given situation shows that water is being added to water. This will liberate heat into the surround as the reaction will be exothermic in nature.

It is known that chemical reactions in which heat is released are known as exothermic reactions.

Hence, when more water is added to this tank the temperature of the system will increase due to release of heat.

Thus, we can conclude that if more water is added to this tank the temperature of the system will increase.

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Calculate the volume of 8.87×10-2 M calcium hydroxide required to neutralize 15.0 mL of a 0.389 M hydrobromic acid solution. mL

Answers

Answer : The volume of calcium hydroxide is, 32.89 ml

Explanation :

Using neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 2

M_1 = concentration of hydrobromic acid = 0.389 M

M_2 = concentration of calcium hydroxide = 0.0887 M

V_1 = volume of hydrobromic acid = 15 ml

V_2 = volume of calcium hydroxide = ?

Now put all the given values in the above law, we get the volume of calcium hydroxide.

1* 0.389M* 15ml=2* 0.0887M* V_2

V_2=32.89ml

Therefore, the volume of calcium hydroxide is, 32.89 ml

Using the following equation how many grams of water you would get from 886 g of glucose:C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

Answers

Answer:

531.6g

Explanation:

Total moles of glucose in this case is: 886/180= 4.922 (mole)

For every 1 mole glucose we get 6 mole water

-> Mole of water is: 4.922 * 6= 29.533 (mole)

weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g

Final answer:

The stoichiometric amount of water produced by reacting 886g of glucose in the given reaction is approximately 532g.

Explanation:

This is a question of stoichiometry, the part of chemistry that deals with the relationships between reactants and products in chemical reactions. In this reaction, 1 molecule of glucose (C6H12O6) produces 6 molecules of water (H2O). Looking at the molar mass of glucose, which is approximately 180.16 g/mol, and of water, which is about 18.015 g/mol, we can determine the produced water mass.  886 grams of glucose is approximately 4.92 moles. Because the reaction produces 6 moles of water for every mole of glucose, the reaction of 4.92 moles of glucose will produce approximately 29.52 moles of water. Turning that back into grams, we find that 29.52 moles of water is approximately 532 grams of water. So, the reaction of 886 g of glucose would produce about 532 g of water.

Learn more about Stoichiometry here:

brainly.com/question/34828728

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10 POINTS : What are 4 things created from Big Bang?

Answers

Answer:

:0

Explanation:

One second after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.Jun 17, 2017

Ammonia is produced by the reaction of nitrogen and hydrogen: N2(g) + H2(g)  NH3(g)(a) Balance the chemical equation.
(b) Calculate the mass of ammonia produced when 35.0g of nitrogen reacts with hydrogen.

Answers

Answer:

a) N2 (g) + H2 = 2 NH3

b) You have to state the mass of hydrogen

If 35.2 g of magnesium react with excess hydrochloric acid, how many grams of magnesium chloride are produced? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(aq)

Answers

Answer:

139.33 g of magnesium chloride, MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(aq)

Next, we shall determine the mass of Mg that reacted and the mass of MgCl2 from the balanced equation.

This is illustrated below:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 x 24 = 24 g

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Finally, we shall determine the mass of MgCl2 produced by reacting 35.2 g of Mg.

This can be obtained as follow:

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Therefore, 35.2 g of Mg will react to produce = (35.2 x 95)/24 = 139.33 g of MgCl2.

From the calculations made above, 139.33 g of magnesium chloride, MgCl2 were produced.

Calculate the wavelength of A 75 kg athlete running a 7.0-minute mile

Answers

Answer:

\lambda =2.31x10^(-36)m

Explanation:

Hello,

In this case, since the Broglie's wavelength for bodies is defined via:

\lambda =(h)/(mv)

Whereas h accounts for the Planck's constant, m the mass and v the velocity, which is:

v=(1mile)/(7.0min)*(1609.34m)/(1mile)*(1min)/(60s)=3.83(m)/(s)

Thus, the wavelength turns out:

\lambda =(6.63x10^(-34)kg(m^2)/(s) )/(75kg*3.83(m)/(s) ) \n\n\lambda =2.31x10^(-36)m

Best regards.
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