Answers
Answer:
8
Explanation:
7 is neutral any anything above it is basic and anything below is acidic which means 8 would be the lowest base
Answer:
The pH of a weak base falls somewhere between 7 and 10.
Explanation:
Like weak acids, weak bases do not undergo complete dissociation; instead, their ionization is a two-way reaction with a definite equilibrium point
Related Questions
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.
Ammonium nitrate dissociates in water according to the following equation:43() = 4+()+03−()When a student mixes 5.00 g of NH4NO3 with 50.0 mL of water in a coffee-cup calorimeter, the temperature of the resultant solution decreases from 22.0 °C to 16.5 °C. Assume the density of water is 1.00 g/ml and the specific heat capacity of the resultant solution is 4.18 J/g·°C.1) Calculate q for the reaction. You must show your work.2) Calculate the number of moles of NH4NO3(s) which reacted. You must show your work.3) Calculate ΔH for the reaction in kJ/mol. You must show your work.
Develop expressions for the mole fraction of reacting species functions of the reaction coordinate for: A system initially containing 2 mol NH3 and 5 mol O2 and undergoing the reaction: 4NH3 (g) + 5O2 (g) ® 4NO (g) + 6 H20 (g) A system initially containing 3 mol NO2, 4 mol NH3, and 1 mol N2 and undergoing the reaction: 6NO2 (g) + 8NH3 (g) ® 7N2 (g) +12H2O (g)
Show the conversion factor from Patolbf/ft2is 0.02089.
b. Is colorless in the presence of water
c. Does not exist as a hydrate
d. Forms different hydrates which have different colors
Answers
Answer:Forms different hydrates which have different colors
Explanation:
CoCl2 in its anhydrous form is blue in colour. This anhydrous compound could absorb moisture, first forming the purple dihydrate and absorbs more water molecules to form the hexahydrate. Hence various hydrates of cobalt II chloride have different colours as stated above. Equations of reaction for the formation of the two hydrates are attached.
Answers
Answer : The mass of sucrose added to 375 mL of water must be, 10.6 grams.
Explanation :
As we are given that 2.75 m/m percent solution of sucrose. That means, 2.75 grams of sucrose present in 100 grams of solution.
Mass of solution = 100 g
Mass of sucrose = 2.75 g
Mass of water = Mass of solution - Mass of sucrose
Mass of water = 100 g - 2.75 g
Mass of water = 97.25 g
First we have to calculate the mass of water.
Density of water = 1.00 g/mL
Volume of water = 375 mL
Now we have to calculate the mass of sucrose in 375 g of water.
As, 97.25 grams of water contain 2.75 grams of sucrose
So, 375 grams of water contain grams of sucrose
Therefore, the mass of sucrose added to 375 mL of water must be, 10.6 grams.
To make a 2.75% m/m sucrose solution, you need to add approximately 1062 grams of sucrose to 375 mL of water, considering the density of water as 1 g/mL.
To prepare a mass/mass (m/m) percent solution of sucrose, you need to calculate the mass of sucrose (in grams) that needs to be added to 375 mL of water to achieve a 2.75% concentration.
Here's how you can calculate it:
1. Convert the volume of water to grams, considering the density of water:
Density of water ≈ 1 g/mL
Mass of water = Volume of water × Density of water
Mass of water = 375 mL × 1 g/mL = 375 g
2. Determine the desired mass of sucrose as a percentage of the total mass:
Desired m/m percent = 2.75%
3. Calculate the mass of sucrose needed:
Mass of sucrose = (Desired m/m percent / 100) × Total mass
Mass of sucrose = (2.75 / 100) × (375 g + Mass of sucrose)
4. Rearrange the equation to solve for the mass of sucrose:
Mass of sucrose = (2.75 / 100) × (375 g) / (1 - (2.75 / 100))
Now, calculate:
Mass of sucrose = (2.75 / 100) × (375 g) / (1 - 0.0275)
Mass of sucrose ≈ (2.75 / 100) × (375 g) / 0.9725
Mass of sucrose ≈ (2.75 × 375 g) / 100 / 0.9725
Mass of sucrose ≈ (1031.25 g) / 0.9725
Mass of sucrose ≈ 1061.98 g
So, approximately 1062 grams of sucrose must be added to 375 mL of water to prepare a 2.75 m/m percent solution of sucrose.
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Answers
B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group
D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
Answers
Answer:
C
Explanation:
A-T G-C
Answers
Answer:
The most likely reason is that spent fuel bars can infect the community with radiation causing numerous health problems.
Explanation:
A spent fuel is a fuel that has been exposed to irradiation in a nuclear reactor. This fuel expels radiation and this is one of the main reasons why a group of people oppose the storage of spent fuel bars in their community. This is because through this fuel can occur a leak of radiation contaminating the community and generating major health problems.
Answers
Answer:
1.7 × 10⁴ J
Explanation:
Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C
We will use the following expression.
Q₁ = c(ice) × m × ΔT
Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J
Step 2: Calculate the heat required to melt 25 g of ice
We will use the following expression.
Q₂ = C(fusion) × m
Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C
We will use the following expression.
Q₃ = c(water) × m × ΔT
Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J
Step 4: Calculate the total heat required
Q = Q₁ + Q₂ + Q₃
Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J