If all angles are 108 degrees how many sides is there for a regular polygon

Answers

Answer 1

Answer: Sum of interior angles = 180(n-2)
Where n= the number of sides in the polygon

A polygon is called a regular polygon when all of its sides are the same length and all of its angles are the same measure.A regular polygon is both equilateral and equiangular. To find the sum of its interior angles, substitute n = 5 into the formula 180(n - 2) and get 180(5 - 2) = 180(3) = 540°

Since the pentagon is a regular pentagon, the measure of each interior angle will be the same.
To find the size of each angle, divide the sum, 540º, by the number of angles in the pentagon.
(which is the same as the number of sides).
540° 5 = 108°

There are 108° in each interior angle of a regular pentagon. N=8

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Factor -3bk 2 + 9bk - 6b

Answers

First you do -3bk+9bk and that equals 6bk then since there are no more like terms the experssion would be simplified into 6bk+2-6b
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your family takes a taxi from the airport to your hotel. The total charge for the ride is $38.55. How much should you give the cab driver as a tip if you want the tip to be about 15%

Answers

% = of 100
38.55 / 100 = 0.3855
0.3855 x 15 is 5.7825 dollars of tip or 5.80 estimate
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Please help me solve this question

Answers

The fraction is equal 0 if the numerator is equal 0.

$(12)/(x(x+8))=0\iff12=0\ FALSE$

Therefore your answer is 1. 0

Multiply (x + 3)(x – 3). A. x2 + 6x + 9
B. x2 – 9
C. x2 + 6x – 9
D. x2 – 6x + 9

I can't focus.

Answers

Answer:

The answer is B. $x^2-9$

Step-by-step explanation:

This problem represents a "the Sum and Difference of the same two terms".

If you encounter the same two terms and just the sign between them changes, rest assured that the result is the square of those two terms. Also, the second term will always be negative.

For example:

$(a-b)*(a+b)=a^2-b^2$

So, in this case:

$(x+3)*(x-3)\nx^2-3*x+3*x-9\nx^2-9$

Therefore, the answer is B. $x^2-9$

B would be correct the -3 x and 3 x cancel out

Which angle measure below is not a possible measure of an exterior angle of a regular polygon?45°
36°
40°
54°

Answers

All exterior angles of a regular polygon would equal 360 degrees. SO... based on that, one exterior angle would have to multiplied by whatever sum (whole number) to equal 360 degrees to find the number of sides. Here you divide 360 by one of the exterior angles, if it does not equal a whole number then it would be inaccurate.
In this case only 54 degrees would not fit into one of the exterior angles.

Find the area of a triangle given that
c=40m
b=20m
a=48°

Answers

$Area= (1)/(2)\cdot c\cdot b\cdot sin \alpha \n\n------------------\n\nA= (1)/(2)\cdot 40\cdot20\cdot sin48^0\approx400\cdot0.7431=297.24\ [m^2]\n\nAns.\ Area\ is\ about\ 297.24\ [m^2]$

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