DESCRIBE USING ROSTER METHOD MONTHS WITH 31 DAYS

Answers

Answer 1
Answer: We must put the months of the year with 31 days in a "bag".
This "bag" will be called M (like months).

M= {Januray, March, May, July, August, October, December}
Answer 2
Answer: Let M be the collection of months with 31 days.

By applying roster method ;

M = {Januray, March, May, July, August, October, December}

We know that earth takes 365 days for one revolution. To make an equitible distribution in accordance to months, ( for international reference) this calender was created.

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XWhich polynomial function has a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1?a. f(x) = (x + 7) (x – i) (x + 5) (x + i)
b. f(x) = (x – 7) (x – i) (x – 5) (x + i)
c. f(x) = (x – (7 – i)) (x – (5 + i)) (x – (7 + i)) (x – (5 – i))
d. f(x) = (x + (7 – i)) (x + (5 + i)) (x + (7 + i)) (x + (5 – i))

Answers

Hello,

If ALL coefficients of x are reals!, (question is wrong)
if z_(0)\ is\ a\ root\ \overline{z_(0)}\ is\ also\ a\ root

Thus ANSWER C f(x) = (x – (7 – i)) (x – (5 + i)) (x – (7 + i)) (x – (5 – i))

Final answer:

The polynomial function with a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1 is f(x) = (x + 7) (x – i) (x + 5) (x + i).

Explanation:

The polynomial function with a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1 is option a. f(x) = (x + 7) (x – i) (x + 5) (x + i). To understand why this is the correct answer, we first need to know that complex roots always appear in conjugate pairs, which means that if a + bi is a root, then a - bi is also a root. The given roots are (7 + i) and (5 – i), so the conjugate pairs are (7 – i) and (5 + i).

Therefore, the correct polynomial is obtained by multiplying the factors (x – (7 + i)), (x – (7 – i)), (x – (5 + i)), and (x – (5 – i)). This gives us f(x) = (x + 7) (x – i) (x + 5) (x + i), which is option a.

Learn more about Polynomial Functions here:

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4) Jamie is 5 years older than Ella. Jamie's age is 11 years less than three times Ella's age. Write a system of equations to model the relationship between Jamie's age and Ella's age. Let j = Jamie’s age Let e = Ella’s age
HINT: You should have TWO equations; create one for each sentence description above.
Equation 1: j =
Equation 2: j =

Answers

The system of equations is j  = e + 5 and j = 3e - 11 we can solve it using the substitution method.

What is linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

Jamie is 5 yearsolder than Ella. Jamie's age is 11 years, less than three times Ella's age.

The system of equation can be written as:

j  = e + 5

j = 3e - 11

Thus, the system of equations are j  = e + 5 and j = 3e - 11 we can solve it using the substitution method.

Learn more about the linear equation here:

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j  = e + 5
j = 3e - 11 equations

there are different ways of expressing the same value examlpe . 10 = 4 + 6 and 10 = 8 + 2 and 10= 7 + 3 4 + 6 = 8 + 2 =7 + 3 all = 10
using the concept same applies to varibles j = j so, e + 5 = 3e - 1 so, the possible answer would be  e + 5 = 3e - 11 to find the value of e .


 i Truly hope that this helpss IF NT CMMT BELOWW ↓↓ . PLz ThANKsZ !

Help me please again

Answers

The answer is C.
x=2
y=-30
(2;-30)

A bag had 3 pink marbles and 4 purple marbles find the probability of selecting 3 pink marbles without replacement

Answers

There are 7 marbles in the bag.
The probability of drawing a  pink one is (3/7) .

Then you have 1 pink one, and there are 6 marbles in the bag.
The probability of drawing a pink one is (2/6) .

Then you have 2 pink ones, and there are 5 marbles in the bag.
The probability of drawing a pink one is (1/5) .

The probability of all 3 draws being successful is

           (3/7) (2/6) (1/5)  =  6/210  =  1/35  =  about  2.86%  (rounded)

what would be an outlier if added to the data set below? 507, 586, 499, 542, 615, 600, 561, 519 A.487 B.535 C.610 D.380

Answers

I am pretty sure the answer is F

Which graph correctly solves the system of equations below?x2 + y2 = 9
y = x + 3

Linear graph and circle. They intersect at negative 3, 0 and 0, 3
Linear and a quadratic graph. They intersect at negative 3, negative 5 and 2, 0.
Linear and a quadratic graph. They intersect at negative 2, 0 and 1, 3.
Linear graph and circle. They intersect at negative 2, 0 and 0, 2.

Answers

x^2 + y^2 = 9 . . . . . . . .  circle
y = x + 3 . . . . . . . (linear graph)

They intersect at (-3, 0) and (0, 3)

Answer:

They intersect at (-3, 0) and (0, 3)

Step-by-step explanation:

took the test hope it helps