Which is an IUPAC name for a covalent compound
Answers
1. The first element of the formula will use the normal name of the given element. for example: CO2 ( Carbon Dioxide), Carbon is the element name of the first element of the formula.
2. The second element is named as if they are treated like an anion but put in mind that these are no ions in a covalent compound but we put -ide on the second element as if it is an anion.
3. Prefixes are used to indicate the number of atom of the elements in the compound. for example: mono- 1 atom, di- 2atoms, tri- 3 atoms and etc
4. Prefix "mono"is never used in naming the first element. For example: Carbon dioxide, there should be no monocarbon dioxide.
An IUPAC name for a covalent compound is ethane. For covalent compounds, IUPAC names are based on the composition and structure of the molecules. Covalent compounds typically consist of nonmetals or a combination of nonmetals and metalloids.
Ethane (C₂H₆) is a covalent compound that consists of two carbon atoms bonded to each other with single bonds, and each carbon atom is also bonded to three hydrogen atoms.
Other examples of IUPAC names for covalent compounds include:
Methane (CH₄)
Propane (C₃H₈)
Ethene (C₂H₄)
Nitrogen dioxide (NO₂)
These names are derived based on the IUPAC rules for naming covalent compounds, which consider the number and types of atoms present in the molecule.
To know more about covalent compounds:
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b. It is a theory which is not supported by data.
c. It is an observation which cannot be explained.
d. It is a description which does not work under similar conditions.
Answers
Answer:
D. It is a description which does not work under similar conditions.
Explanation:
I not very sure, but I don't think the other are correct...
Answer:
D
Explanation:
This is one of the answers that remains on this question while the others get switched around if that makes sense
2.water vapor
3.blue sky
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Answer:
3. blue sky
Explanation:
I answered blue sky on my quiz and got it correct.
Answer:
Blue Sky
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I also took the test :)
B. relative humidity.
C. runoff.
D. evaporation.
Answers
i hope i helped
the answer to this question is B relative humidity!
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Density is defined as mass per unit volume. its SI unit is: kg/m³
Explanation:
Answer:
Density is defined as mass per unit volume. its SI unit is: kg/m³
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from answer above
(Choice A) A Eukaryotic cells are more structurally complex than prokaryotic cells.
(Choice B) B Eukaryotic cells have less DNA than prokaryotic cells.
(Choice C) C Eukaryotic cells have more cell walls than prokaryotic cells.
(Choice D) D Eukaryotic cells are smaller than prokaryotic cells.
Answers
Prokaryotic cells reproduce more quickly than eukaryotic cells because the latter are more structurally complex. The correct option is A.
Structural complexity of cells
Eukaryotic cells have nuclei and membrane-bound organelles such as mitochondrion. This is unlike prokaryotic cells whose DNA lies freely in the cytoplasm and lacks membrane-bound organelles.
In order words, eukaryotic cells are structurally more complex than prokaryotic cells. Thus, reproductive times in prokaryotes are usually quicker than in eukaryotes.
More on the structural complexity of cells can be found here: brainly.com/question/3502696
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Answers
Where,
First we convert height into meters.
1 km = 1000 meters
3 km = 1000 * 3 meters = 3000 meters
So, putting the values in the above formula, and by taking 'g' = 9.8 m/s², we get-
relative to the bottom of the hill is 58,800 Joules.
To address the second part of the question:
In order to get ahold of that energy, the ball must be returned to the bottom
of the hill. The most efficient way would be to drop it, so that it wouldn't have to
scrape along the grass on the way down. But that can only work if there's a sheer
cliff on one side of the hill. Otherwise, you just have to roll it down, and accept the
fact that it loses some of its energy to friction on the way.
However the ball gets to the bottom, the energy it has left shows up in the form
of kinetic energy, and 58,800 joules is a lot of kinetic energy. If somehow the ball
could arrive at the bottom with ALL the energy it had at the top, it would be moving
at something like 540 miles per hour !