The angle between the central bright band and the first order bright band is 0.78⁰, hence option A is correct.
According to the question:
A light with a wavelength of 410 nm falls on two slits separated by 0.03 mm,
So, the angle between the central bright band and the first order bright band is,
The angle will be, θ = λ/d radian
λ = 410 nm (410 × 10 ⁻⁹ m)
d = separation of slits (0.03 mm) or 0.03 × 10 ⁻³ m
θ =
= 0.01367 radian
= 0.01367 × (180/π)⁰
= 0.78⁰
Thus, the angle between the central bright band and the first order bright band is 0.78⁰, hence option A is correct.
Learn more about light, here:
#SPJ2
Answer:
B
Explanation:
The only way to increase the time of flight is to increase the height traveled by the projectile to 2h.
The given parameters;
The time of flight of the projectile is calculated as follows;
where;
is the initial vertical velocity of the projectile = 0
Thus, the only way to increase the time of flight is to increase the height traveled by the projectile to 2h.
Learn more here:brainly.com/question/20427663
Answer:
d)
Explanation:
a) decreasing the mass to m/2. FALSE. Mass doesn't influence the equations of accelerated motion.
b) decreasing the height to h/2. FALSE. From a lower initial height the projectile will reach the ground faster.
c) increasing the initial horizontal velocity to 2vx. FALSE. The horizontal and vertical components are independent, and time of flight is dependent only on vertical conditions in this case.
d) increasing the height to 2h. TRUE. From a higher initial height the projectile will reach the ground later.
Answer:
0.432kg or 432g
Explanation:
Copper block is removed from 310C oven.
Mass of water = 1.10kg
Initial temperature of water (θ1) = 23.0C
Final temperature of water (θ2 ) = 33.0C
Specific heat of copper= 385
Specific heat of water = 4190
Let M (copper) be the mass of copper
The amount of heat lost will be absorbed by water
Q (net) = Q(water) + Q(copper) = 0 …………………(1)
Q = MCθ
For water,
Q(water) = M(water) * C(water) * (θ2-θ1)...........(2)
= 1.1 * 4190 * (33.0 -23.0)
= 1.1 *4190 * 10
= 46090J
For copper,
Q(copper) = M(copper) * C(copper) * (33.0 - 310)...........(3)
from equation 1,
Q(copper) = -Q(water)
M(copper) * C(copper) * (33.0 - 310) = - 46090
M(copper) * 385 * (-277) = -46090
M(copper) * 106645 = -46090
M(copper) = -46090 / -106645
M(copper) = 0.432kg
M(copper) = 432g
The mass of copper =432g
The mass of the copper block is 3.69kg.
To find the mass of the copper block, we can use the equation q1 = q2. The heat gained by the water is given by q1 = mcΔT, where m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature. The heat lost by the copper block is given by q2 = mcΔT, where m is the mass of the copper block, c is the specific heat of copper, and ΔT is the change in temperature. Since the water reaches a final temperature of 33.0°C, the change in temperature is ΔT = 33.0°C - 23.0°C = 10.0°C.
Using the equation q1 = q2, we have mcΔT = mcΔT. Rearranging the equation to solve for the mass of the copper block, we get m = (m1c1ΔT2) / (c2ΔT1), where m1 is the mass of the water, c1 is the specific heat of water, ΔT2 is the change in temperature of the copper block, c2 is the specific heat of copper, and ΔT1 is the change in temperature of the water. Substituting the given values, we have m = (1.10kg * 4190 J/(kg?K) * 10.0°C) / (385 J/(kg?K) * 10.0°C), which simplifies to m = 3.69kg.
#SPJ11
B) The alpha particle will reverse its direction.
C) The alpha particle will be deflected in a curve path.
Eliminate
D) The alpha particle will continue to travel in a straight line.
Answer: C) The alpha particle will be deflected in a curve path.
Explanation:
Alpha particle carries +2 charge. It is a Helium ion: He⁺²
When any charged particle enters a magnetic field, it experiences a magnetic force perpendicular to direction of the velocity of the particle and the direction of the magnetic field. Thus, the alpha particle moves in a circular path.
Hence, the correct answer is: The result of an alpha particle coming into a magnetic field is C) The alpha particle will be deflected in a curve path.
b. chronology.
c. discovery.
d. use and applications.
b.) how long will it take for the swimmer to cross the river, if the distance from the starting point to the dock is 300 m?
Please show all your work, thanks
a)The direction that she must aim herself through the water to arrive at the dock will be 73.7°.
b)The time it takes for the swimmer to cross the river will be 240 seconds.
Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
Given data;
The maximum speed of the swimmer In still water,v=1.25m/s.
Speed of river = 0.35m/s [E]
α is the direction that she must aim herself through the water to arrive at the dock.
t is the time it takes for the swimmer to cross the river
The distance from the starting point to the dock is,s = 300 m
If the swimmer were to swim straight, the water's speed along the x-axis would have to match that of the swimmer.
α is the angle between vx and v
The value of the
The time that the swimmer will use for reaching the dock;
s = V×t
t = s/(v)
t=300 m / 1.25 m/sec
t = 240 seconds
Hence, the direction that she must aim herself through the water to arrive at the dock. and it takes for the swimmer to cross the river will be 73.7° and 240 seconds respectively.
To learn more about the speed refer to the link;
#SPJ2
Explanation:
As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).
I'll let you do all the calculations, you just have to plug in values.