Hey!
---------------------------------------------------------
Question #1:
= 6n^2 - 2n - 3 + 5n^2 - 9n - 6
= 6n^2 + (-2n) + (-3) + 5n^2 + (-9n) + (-6)
= (6n^2 + 5n^2) + (-2n + -9n) + (-3 + -6)
= (11n^2) + (-11n) + (-9)
Answer: 11n² + (-11n) + (-9)
---------------------------------------------------------
Question #2:
= 8c^2 - c + 3 + 2c^2 - c + 2
= 8c^2 + (-c) + 3 + 2c^2 + (-c) + 2
= (8c^2 + 2c^2) + (-c + -c) + (3 + 2)
= (10c^2) + (-2c) + (5)
Answer: 10c² + (-2c) + 5
---------------------------------------------------------
Hope This Helped! Good Luck!
Answer:
1. 11n^2-11n-9
2. 10c^2-2c+5
Step-by-step explanation:
1. 6n^2+5n^2 = 11n^2
-2n-9n = -11n
-3-6=-9
2. 8c^2+2c^2 = 10c^2
-c-c= -2c
3+2=5
What is (75 x 2) + (6-3)
Answer:
(75x2)+(6-3)
These equations are in parentesis so they happen first.
75x2=150. If we take 70 and multiply it by 2 we get 140. If we multiply 5 by 2 we get 10. So 140+10=150.
6-3 is next. That is common knowledge and we know its 3.
No we add 150+3=153 to get our answer.
Parenthesis first
Exponets after parenthesis
Multiplying going left to right
Divinding left to right
Adding left to right
Subtracting left to right
Step-by-step explanation:
I hope this helped and if so plz give brainliest.
Answer:
153
Step-by-step explanation:
(75 x 2) + (6-3)
150+(6-3)
150+3
153
The fourth term of the sequence will be 110
The given expression forms a sequence 5, 10, 30 ...
First term = 5
Second term = 10
Third term = 30
Let the fourth term be x
Taking their common difference
10 - 5 = 5
30 - 10 = 20
Since the multiplicity of the common difference is 4
Then T4 = 20(4) + 330
T4 = 80 + 30
T4 = 110
Hence the fourth term of the sequence will be 110
Learn more here: brainly.com/question/19102890
cot (–270°) = 1
cot (–270°) = –1
cot (–270°) = 0
undefined
Answer:
cot(-270) = 0
Step-by-step explanation:
given cot ( -270)
In trigonometry function we will use cot ( -x) = -cotx
so cot (-270) = - cot270
trigonometry table
II quadrant I quadrant ( All positive)
sin θ 90+θ 90 -θ
cosec θ 180-θ 360+θ
third quadrant fourth quadrant
tan θ 180+θ cos θ 270+θ
cot θ 270 - θ sec θ 360-θ
Given
cot (-270) = -cot ( 270)
= - cot ( 180 + 90) (third quadrant above table)
= -cot 90 =0 ( cot θ positive in third quadrant
Final answer:-
cot(-270) =0
The value of cot(−270°) is undefined because it involves a division by zero, as its calculation is based on the cosine and sine values at −270° on the unit circle, which are 0 and 1, respectively.
To find the value of cot (−270°), we need to understand where −270° places us on the unit circle. A full circle is 360°, so starting at the positive x-axis and moving clockwise (since the angle is negative), we move 270° to end up at the positive y-axis. The cotangent function is the ratio of the adjacent side to the opposite side in a right triangle, or the cosine divided by the sine.
At −270° (or 270° in the positive, counter-clockwise direction), the coordinate on the unit circle is (0, 1). The sine of −270° is the y-coordinate (which is 1), and the cosine of −270° is the x-coordinate (which is 0). Therefore, cot (−270°) = cos (−270°) / sin (−270°) = 0/1. Since division by zero is undefined, cot (−270°) is undefined.
#SPJ12
(1 + cot A + tan A) (sin A - cos A) = sin A tan A - cot A cos A
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
tan A = , cot A =
Consider the left side
(1 + cotA + tanA)(sinA - cosA)
each term in the second factor is multiplied by each term in the first factor.
1(sinA - cosA) + cotA(sinA - cosA) + tanA(sinA - cosA)
= sinA - cosA + cosA - + - sinA ( collect like terms )
= -
= ( sinA × ) - ( × cosA )
= sinAtanA - cotAcosA
= right side ⇒ proven