Given: ME=6.0x1024 kg and RE=6.4x106m
Answer:
3.8 m/s²
Explanation:
g = GM / R²
g = G (0.11 ME) / (0.53 RE)²
g = 0.39 G ME / RE²
g = 0.39 (9.8 m/s²)
g = 3.8 m/s²
Answer:
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simple put is 3.8 m/s²
took it on edge 2020
The birds can glide in the air without moving their wings by maintaining the thrust of the air by their weight and move downward at a very slower rate.
Further Explanation:
The birds have a capability of flying high in the air without flapping their wings and still not falling down rather they glide downwards due to the up thrust of the air. This technique of the birds to keep them in the air without flapping their wings is termed as soaring.
The soaring birds make use of the air current and its thrust on their primary wings so that there is no turbulence experienced by them due to the pointed tips of their primary wings.
The birds should possess some mass in order to maintain a balance between the thrust and the weight of their body. That’s why the small birds are not able to maintain their flight but the bigger birds like vulture, eagle etc. experience sufficient air drag in order tio maintain their flight.
Thus, the birds can glide in the air without moving their wings by maintaining the thrust of the air by their weight and move downward at a very slower rate.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Up thrust
Keywords: Airborne, flapping wings, birds, soaring, vultures, weight, maintain flight, gliding, move downward, turbulence, primary wings.
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