Answer:
6Ω
Explanation:
The 6Ω resistor and the 3Ω resistor are in parallel.
R = 1 / (1/6 + 1/3)
R = 1 / (1/6 + 2/6)
R = 1 / (3/6)
R = 6/3
R = 2
The 8Ω resistor and the other 8Ω resistor are also in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
This 4Ω resistance is in series with the 4Ω resistor.
R = 4 + 4
R = 8
The 2Ω resistor and the 6Ω resistor are also in series.
R = 2 + 6
R = 8
These two 8Ω resistances are in parallel.
R = 1 / (1/8 + 1/8)
R = 1 / (2/8)
R = 8/2
R = 4
Finally, this 4Ω resistance is in series with the 2Ω resistance we found earlier.
R = 4 + 2
R = 6
The total equivalent resistance is 6Ω.
B.the great distance between the sun and the planets
C.
force of gravity the galaxy exerts on all objects in it
D.the gravitational force between the sun and each object in the solar system
The 3 blocks north and the 3 blocks south cancel each other, and contribute nothing to the displacement. The total displacement is 3 blocks east.
Answer:
O
Explanation:
OB. 25 g
OC. 75 g
OD. 100 g
Answer:
B. 25 g
Explanation:
Given:
The initial mass of radioactive isotope is,
There is exponential decay of the isotope with time.
Half life means the time in which the given mass reduces by half. For every half life, the mass reduces by half of the previous mass.
So, for the first half life, the mass that remains is given as:
Now, for the second half life, the mass 50 g is again reduced to half.
So, the mass that remains after 2 half-lives is given as:
Therefore, the radioactive isotope that will remain in the sample after 2 half-lives is 25 g.
Answer:
its 12.5 g for anyone else who had different options
Explanation: