The required equation of a line is y = 2x - 11
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The given line,
y = 2x + 1
The slope of the equation is m = 2
Now the point is required,
3x-2y=10 - - - - - -(1)
x+y=5
x = 5 - y - - - - -(2)
putting x in equation 1
3(5 - y) - 2y = 10
15 - 3y - 2y = 10
-5y = -5
y = 1
Now
x = 5 - y
x = 5 + 1
x = 6
Points are (6, 1)
Equation of line is given by,
y - 1 = m (x - 6 )
y - 1 = 2 (x - 6 )
y = 2x -12 + 1
y = 2x - 11
Thus, the required equation of line is y = 2x - 11
Learn more about slopes here:
brainly.com/question/3605446
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well, keeping in mind that parallel lines have the same exact slope, hmmmmm
alrite, so we know the slope has to be 2 then hmmm let's check the point it runs through
so, we're really looking for the equation of a line whose slope is 2 and runs through (4,1)