Determine if the ordered pair (6, 4) is a solution to the inequality y is greater than negative one half times x plus 7. Yes, because (6, 4) is above the line No, because (6, 4) is below the line Yes, because (6, 4) is on the line No, because (6, 4) is on the line

Answers

Answer 1
Answer:

Answer:

No,because (6,4) is on the line.

Step-by-step explanation:

We are given that an inequality equation

y>-(1)/(2)x+7

We have to find that the ordered pair (6,4) is a solution of given inequality or not.

y>-(x)/(2)+7

Substitute x=6

y>-(6)/(2)+7

y>-3+7

y>4

The value of y is greater than 4 not equal to 4.

Therefore, (6,4) is not a solution of given inequality.

No,because (6,4) is on the line.

Answer 2
Answer:

Answer:

(6,4) is not a solution of y > -x/2 + 7 because (6,4) is on the line

The answer is D.

Hope this helps!


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Answers

Answer:

1.0625

Step-by-step explanation:

Because if you multiply 4 1/4 and 1/4 then it'll be 1.0625 and that is haw many cubes you'll need to fill the rectangular prism.

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Answers

there is none because least common denominator

The radius of a basketball is about 3.6 times greater than the radius of a tennis ball. How many times greater is the volume of a basketball than the volume of a tennis ball. (note: the volume of a sphere is v= 4/3 pi r cubed

Answers

let's take radius of the basket ball as b
let's take radius of the tennis ball as t
b = 3.6 t

volume of the basket ball vb = 4/3 pi b^3
volume of the tennis ball vt = 4/3 pi t^3

therefore
vb / vt = b^3 / t^3
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           = 3.6^3
           = 46.656

so the volume of the basketball is 46.656 times greater than the volume of the tennis ball.

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Answers

a vertex is a corner
notice, #vertices=#sides
we cannot use a circle since it is 1 side but 0 vertices

square,trapezoid, triangle, pentagon, hexagon, octogon

square+triangle is 4+3=7
next is trapezoid which is 4 sides

the shapes can be
trapezoid, square, triangle or
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trapezoid, rectangle, triangle or
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Answers

Answer:Choose last option

Step-by-step explanation:

Last one would be easier

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b) If the area was flooded, how high could the water level rise before the bridge was no longer safe to use?

I have answered a) but I don't know how to do b). The book says the answer is 24m if that helps. Any suggestions are appreciated.

Answers

Sure. The function is a parabola. Because the coefficient of the x^2 term is positive, it opens upward. that means that it vertex is a minimum point.

You can verify that the vertex is (0,24). That means that at the point x=0, the height of the bridge is 24m. So if the level water rises below 24 m, the bridge is safe to use.