CHEMISTRY MIDDLE SCHOOL

Which of the following is a valid mole ratio from the balanced equation 2Fe2O3 + 3C → 4Fe + 3CO2?two moles of F e two O three over four moles of F e
four moles of C over three moles of F e
two moles of F e two O three over four moles of C
three moles of C over four moles of C O two

Answers

Answer 1

Answer:

Answer:

2 moles ofFerric Oxide ( $Fe_(2)O_(3)$ ) over 4 moles of Fe

Explanation:

Firts of all I want to explain the nomenclature that is involve in the equation:

$Fe_(2)O_(3)=$ Ferric Oxide

$C=$ Carbon

$Fe=$ Iron

$CO_(2)=$ Carbon Dioxide

Now, to understand the ratio from the balanced equation its necessary read the equation with the respective coefficients, for example:

2 moles of Ferric Oxide ( $Fe_(2)O_(3)$ ) reacts to produce 4 moles of Iron ( $Fe=$ )
3 moles of Carbon ( $C$ ) reacts to produce 4 moles of Iron ( $Fe=$ )
2 moles of Ferric Oxide ( $Fe_(2)O_(3)=$ ) reacts to produce 3 moles of Carbon Dioxide ( $CO_(2)$ )

Each of the above could be represent as a ratio, but is always necessary keep the respective coefficient, then if you read each option only the first has the respective coefficient, it means:

2 moles of Ferric Oxide ( $2Fe_(2)O_(3)$ ) reacts to produce 4 moles of Iron ( $4Fe=$ ) or, in other words, 2 moles ofFerric Oxide ( $2Fe_(2)O_(3)$ ) over 4 moles of Iron 4 ( $4Fe=$ )

Regards!

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A closed container is filled with oxygen. The pressure in the container is 205 kPa
What is the pressure in millimeters of mercury?
Express the pressure numerically in millimeters of mercury.

Answers

Answer:

so pressure in millimeter Hg will be 3016.5 mm Hg

Explanation:

when you look at the ground, you seem to be at rest. Why is this? Why does someone in space see you moving in a circle?

Answers

Gravitation law is the reason to it

Explain the function of ribosomes and why cells need them

Answers

The job of ribosomes is to make protein that is used inside the cell. Your cells use proteins for structural units, as transportation mechanisms between the interior and exterior and as specialized catalysts (enzymes). Therefore, if you don't have ribosomes, the cells wouldn't live because they wouldn't have them to do the functions they need.

Final answer:

Ribosomes are essential cell components that facilitate protein synthesis by translating mRNA into proteins. These proteins play various important roles in cell and organism function and survival, making ribosomes key for growth and survival.

Explanation:

Ribosomes are essential organs within a cell that play a significant role in the protein synthesis process. They are primarily responsible for decoding an organism's DNA into RNA, specifically an mRNA (messenger RNA), which is then used as a template for constructing proteins, a process known as translation.

Proteins produced in ribosomes function in numerous ways, including as enzymes, antibodies, and cell membrane components. Without ribosomes cell would have no way of making these essential proteins.

This is why cells need ribosomes. They are indispensable for the growth and survival of cells and organisms, as they make proteins that are crucial for cell function and growth.

Learn more about Ribosomes here:

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Calcium hydroxide reacts with a substance to produce calcium carbonate
name the substance

Answers

Calcium Hydroxide (Ca(OH)2) reacts with the Carbon Dioxide (CO2) present in the Air to form Calcium Carbonate (CaCO3) and Water (H2O).

The equation looks something like this -->

Ca(OH)2 + CO2 = CaCO3 + H2O

Let the substance be p

CaOH + p = CaCO3

following the laws of chemical reactions and law of conservation of mass, p will be 1 atom of carbon dioxide and 2 atoms of oxygen. Thus, the p will be CO2.

Thus, CaOH + CO2 = CaCO3

Please note that during this process, water will also be produced.

Which element reacts spontaneously with 1.0M HCl (aq) at room temperature?(1) copper (3) silver

(2) gold (4) zinc

Answers

(4) Zinc is correct answer. Others don't react at room temperature with HCl because their reactivity (capability to react) is quite low.

(4) zinc.................

write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithium are measured?

Answers

Answer:

First ionization of lithium:

$\text{Li}\;(g)\to \text{Li}^(+) \; (g) + \text{e}^(-)$ .

Second ionization of lithium:

$\text{Li}^(+)\;(g) \to\text{Li}^(2+) \;(g) + \text{e}^(-)$ .

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol $(g)$ next to any atom or ion in the equation.
The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

The products shall contain a gaseous ion with charge +1 $\text{Li}^(+)\;(g)$ as well as an electron $\text{e}^(-)$ .
Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: $\text{Li}\;(g)$ .

Hence the equation: $\text{Li}\;(g) \to \text{Li}^(+)\;(g) + \text{e}^(-)$ .

Second Ionization Energy of Li:

The product shall contain a gaseous ion with charge +2: $\text{Li}^(2+)\;(g)$ as well as an electron $\text{e}^(-)$ .
Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?

The equation for this process is $\text{Li}^(+) \; (g) \to \text{Li}^(2+)\;(g) + \text{e}^(-)$ .

Final answer:

The first ionization energy of lithium is represented by the equation: Li(g) -> Li+(g) + e-, with an energy of +54.4 eV. The second ionization energy is represented by the equation: Li+(g) -> Li2+(g) + e-, with an energy of 30.6 eV. These equations demonstrate the process of ionization.

Explanation:

The ionization energy of an element is the energy required to remove an electron from a gaseous atom or ion. The first ionization energy of lithium is represented by the equation: Li(g) -> Li+(g) + e-, the energy required for this process is +54.4 eV.

The second ionization energy refers to the energy required to remove the second electron. For lithium, the second ionization energy is represented by the equation: Li+(g) -> Li2+(g) + e-, the energy needed for ionizing the second electron is 30.6 eV.

The equations represent the processes which occur when the first ionization and the second ionization energies of lithium are measured.