Isotopes called what are used to diagnose disease and to study environmental conditions

Answers

Answer 1

Answer: A radioactive tracer, I believe. Someone check that lol.

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What parts are different between plant and animal cells? How does this affect what the cells can do? Please help me ASAP!!!!

Answers

Plant cells have a cell wall, so it can't pinch in and separate like an animal cell does. So, a plant cell forms a cell plate in the middle, then that becomes a cell wall and new membrane. That's why plant cells are so close together.

The cells of most plants do not have centrioles, although a spindle of fibers is present. Cytokinesis usually, but not always occurs during telophase. The rigid cell wall prevents the formation of cleavage furrow during cytokinesis; instead, a cell plate forms to separate the parent cell into two daughter cells, and a new cell wall forms along the cell plate.

Now see plant cells have a cell wall as animal cells do not. A plant cell also has a cytoplasm. A plant also has a vacuole. And parts of a cell are in different places then each other. I hope this helped!

What can you infer about copper and silver based on their position relative to each other?

Answers

Electronegativity decreases as you go down a colum in the periodic table.

Please help!!!The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation below. Suppose
0.06 L of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.20 M
H2504 is dripped into the KOH solution. After exactly 0.017 L of H2SO4 is added, the Indicator changes from blue to
yellow. What is the concentration of the KOH? You must show all of your work to earn credit. (4 points)
H2SO4 + 2KOH → K2SO4 + 2H20

Answers

Answer:

$\large\boxed{\large\boxed{1M}}$

Explanation:

1. Reaction

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

2. Mole ratio

$(2molKOH)/(1molH_2SO_4)$

3. Sulfuric acid

$Molarity=(moles)/(volume(liters))$

$Moles=Molarity* Volume(liters)$

$Moles=0.20M* 0.017liter=0.034molH_2SO_4$

4. Potassium hydroxide

$(2molKOH)/(1molH_2SO_4)* 0.034molH_2SO_4=0.068molKOH$

$Molarity=(0.068mol)/(0.06liter)=1.13M\approx 1M$

Which element would most likely have a chemical reactivity similar to bromine?A) Chlorine

B) Sulfur

C) Selenium

D) Phosphorus

Plz hurry up!!

Answers

Answer:

I would say C)Selenium because it has a closer amount of valence electrons in the atom but I could be wrong as well no one is perfect. If that's not the answer then ask for some help by the teacher it's likely that you'll get the most help there

A(n) Blank is an abbreviation for the name of an element ans usully has either one or to letters

Answers

symbol (elemental symbol)

Which is the solubility product expression for Na3PO4(s)?A. [Na] +3(PO4)3-

B. [Na +3] / [PO43-]

C. [Na +] }[PO43-)

D. [Na] +3/[PO4) 3 -

Answers

Final answer:

The solubility product expression for Na3PO4(s) is [Na+]^3[PO4^3-], which denotes the ion concentration in the solution after the dissolution of sodium phosphate. therefore, option A is correct

Explanation:

The solubility product expression for Na3PO4(s) would be written as [Na+]^3[PO4^3-]. The solubility product, Ksp, is the equilibrium constant for the dissolution of a sparingly soluble substance. The solubility product expression depends on the stoichiometry of the dissolution reaction. Sodium phosphate, Na3PO4, dissociates in water into 3 sodium ions, Na+, and 1 phosphate ion, PO4^3-. Therefore, the solubility product expression is [Na+]^3[PO4^3-], where [Na+] and [PO4^3-] represent the molar concentration of these ions in the solution.

Learn more about Solubility Product here:

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Final answer:

The solubility product expression of Na3PO4 is not among the given options because Na3PO4 is soluble in water and for soluble compounds, we don't write a solubility expression.

Explanation:

The solubility product expression is typically written for an ionic compound that is sparingly soluble in water. The solubility product expression of Na3PO4 is not among the options you've provided because every ionic compound has its own specific solubility product expression. Na3PO4 is soluble, so we don't write a solubility expression for it. In general, for a reaction where a solid dissolves in water such as A3B (s) ↔ 3A+ (aq) + B3- (aq), the solubility product expression would be [A+]^3 [B3-].

Learn more about Solubility Product Expression here:

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