Which of these statements best describes a similarity between asteroids and comets? A) Both consist of gases
B) Both are dwarf planets
C) Both liquefy due to heat
D) Both orbit around the sun

There are several potential sources of error that could explain differences between a predicted sound speed and the experimentally measured value. Some common sources of error include:

1. Instrumental Errors: Inaccuracies or limitations in the measurement instruments used to determine the sound speed. This could include issues with the calibration of the instruments, sensitivity limitations, or errors in reading the measurements.

2. Environmental Factors: Variations in temperature, humidity, and atmospheric conditions can affect the speed of sound. If these factors are not accounted for or if they fluctuate during the experiment, they can introduce errors in the measured value.

3. Experimental Setup: Mistakes or inaccuracies in the experimental setup can lead to discrepancies between predicted and measured values. This could involve errors in the positioning of the sound source and receiver, incorrect timing measurements, or improper alignment of the equipment.

4. Assumptions and Models: Simplifications or assumptions made in the theoretical prediction of sound speed can introduce errors. If the underlying physics or properties of the medium are not accurately accounted for, the predicted value may deviate from the experimental measurement.

5. Human Error: Errors or biases introduced by the experimenter during the measurement process, such as misinterpretation of data, incorrect calculations, or systematic errors in data collection or analysis.

It is important to identify and minimize these sources of error through careful experimental design, calibration, and repeated measurements. Additionally, conducting experiments in controlled conditions and using precise measurement techniques can help reduce uncertainties and improve the accuracy of the measured sound speed.

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6 ... A

9 ... A

10 ... ok

12 ... A

23 ... ok

24 ... A

Answer:

Electro-negativity is the tendency of an atom to attract the shared pair of electron in a covalent bonding while forming a molecule.

Explanation:

In a covalent bonding the atoms share the electrons mutually without actually transferring it to one of the atom to gain a stable configuration. In such a case when one atom is more electro-negative than the other then the shared pair of electron gets slightly shifted towards the more electro-negative developing a denser cloud of electrons near the nucleus of that atom which we denote as partial negative () in the superscript.

In water molecules we have a similar case where the oxygen atom is more eletro-negative (value=3.44) than the hydrogen atom (value=2.2). This leads to a higher electron density near the oxygen atom.  A part from the shared pairs, the oxygen atom also possesses 2 lone pairs of electrons which tend tp makethe shape a tetrahedron in a 3D structure. This results in molecular shape being bent with an H-O-H angle of 104.5°.

A) The temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W is; T_i = 38.52°C

B) The thickness of the layer contained within the fur so that the bear loses heat at a rate of 51.4 W is; t = 13.41 cm

We are given;

Diameter of sphere; d = 1.6 m

Radius of sphere; r = d/2

r = 1.6/2

r = 0.8 m

Thickness of bear; t = 3.9 cm cm = 0.039 m

Outer surface Temperature of fur; T_h = 2.8 ∘C

Inner surface Temperature of fat;T_f = 30.9 ∘C

Thermal conductivity of fat; K_f = 0.2 W/m⋅k

Thermal conductivity of air; K_a = 0.024 W/m⋅k

A) To find the temperature at the fat-inner fur boundary when heat loss is 51.4 W, we will use the heat current formula;

H = K_f•A(T_f - T_i)/t

Where;

A is area = 4πr²

A = 4π × 0.8²

A = 8.04 m²

T_i is the temperature we are looking for

H is heat loss = 51.4

t is thickness

Making T_i the subject gives;

T_i = (T_f × H × t)/(K_f × A)

T_i = (30.9 × 51.4 × 0.039)/(0.2 × 8.04)

T_i = 38.52°C

B) We want to find the thickness of the layer contained within the fur. Thus, we will use K_a instead of K_f. Let us make t the subject in the heat current formula to get;

t = (K_a•A(T_i - T_h)/H

t = (0.024 × 8.04 × (38.52 - 2.8))/51.4

t = 0.1341 m

t = 13.41 cm

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Answer:

Explanation:

Using the equation

H = Q/t = k A ( T hot - T cold) / L

where H is the rate of heat loss = 51.4 W, T cold be temperature of the outer surface, A is the surface area of the fat layer which is a model of sphere ( surface area of a sphere ) = 4πr² where diameter = 1.60 m

radius = 1.60 m / 2 = 0.80 m

A = 4 × 3.142 × ( 0.8²) = 8.04352 m²

making T cold subject of the formula

T cold =  T hot -    = 30.9° C - ( 51.4 W × 3.9 × 10⁻² m) / ( 0.2 W/mK × 8.04352 m² ) =  30.9° C - 1.25 ° C = 29.65° C

b) The thickness of air layer for the bear to lose heat t a rate of 51.4 W

thermal conductivity of air is 0.024 W/mK and rearranging the earlier formula

L = = (0.024 W/ m K × 8.04352 m²) ( 29.65° C - 2.8°C) / 51.4 W = 0.101 m = 10.1 m

The voltage is presented by the equation V = IR where V is voltage in V, I is current in amperes ad R is resistance in ohms. If a platinum wire has a resistance of 15 Ω and is connected across the terminals of a 3.0 V flashlight battery, the current can be solved through V= IR, 3.0 V = I (15 Ω), and the current is 0.2 A.