MATHEMATICS HIGH SCHOOL

Algebra II
15 points

Answers

Answer 1

Answer:

Answer:

B. The axis of symmetry is x=1.

F. The vertex is (1, 7).

G. The y-intercept is (0, 10).

Step-by-step explanation:

A graph of the function is helpful sorting this out.

_____

For quadratic ax² +bx +c, the axis of symmetry is x=-b/(2a). Here, that is ...

x = -(-6)/(2·3)

x = 1 . . . . axis of symmetry

This is also the x-coordinate of the vertex. The y-coordinate of the vertex can be found by evaluating the expression for this value of x:

3·1² -6·1 +10 = 7

so the vertex is (1, 7).

The y-intercept is the constant, the value of the function when x=0. Here, that is 10, so the coordinates of the y-intercept are (0, 10).

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Prove that sin(x) + tan(x) = 1 + sec(x)/csc(x) by using trigonometric identities.

Answers

Answer:

Step-by-step explanation:

sin(x) + tan(x) =sin(X) + sin(x)/cos(x)

=sinx(1+1/cosx)

=Sinx(1+secx)

=1+secx/cosecx. (Since sinx=1/cosecx)

Hence LHS=RHS proved

Which value of x makes the following equation true?4(x - 1) = -4x + 60

A. 8
B. 12
C. 11
D. 9

Answers

The easiest way is to just solve the equation.
4x - 4 = -4x + 60
4x + 4x = 4 + 60
8x = 64
x = 8

A slower way to do this is to plug each of the numbers into the equation to see which makes the equation is true.
So for A.
4(8 - 1) = -4(8) + 60
4(7) = -32 + 60
28 = 28
Fortunately, this is true, so A is the answer and you don't have to try the other options.

It would be A because if you plug in 8 for x on each side you get 28 which makes the equation true

Find the zeros of the function g(x) = 4x^2 - 484

Answers

There are two zeros of the function g(x) that is 11 , -11

What are zeros of the function?

The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.

According to the question

g(x) = $4x^(2)$ - 484

To find the zeros of a function, find the values of x where g(x) = 0.

Therefore,

0 = $4x^(2)$ - 484

0 = $x^(2) - 121$

0= $(x-11)(x+11)$

i.e ,

$x = 11 ,-11$

Hence , there are 2 zeros of the function g(x) that is 11 , -11 .

To know more about zeros of the function here :

brainly.com/question/22101211

# SPJ2

Answer:

Step-by-step explanation:

3n-5=-8(6+5n) SOLVE

Answers

It's gonna be a long problem: Remember PEMDAS
3n-5=8(6+5n)
3n-5= 48 + 40n Distribute 8 into parenthesis
3n-3n-5=48+40n-3n Put variable on one side.
-5-48=48-48+37n Isolate the variable
-43/37=37n/37 Isolate variable more
-1.162=n Simplify
The answer is repeating; that is a shortened version.

t's gonna be a long problem: Remember PEMDAS

3n-5=8(6+5n)

3n-5= 48 + 40n Distribute 8 into parenthesis

3n-3n-5=48+40n-3n Put variable on one side.

-5-48=48-48+37n Isolate the variable

-43/37=37n/37 Isolate variable more

-1.162=n Simplify

The answer is repeating; that is a shortened version.

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