Find the real-number root.001O no real rootsO 0.1O 0.1 and 0.1O 0.1 I need help
Find the real-number root.001O no real rootsO 0.1O 0.1 and - 1

Answers

Answer 1
Answer: for cube roots of a positive number, it could have a real number of a negative number but has to contain 2 negatives if it does and one positive. Eg. (-)*(-)* (+) = +

0.001 can be made by multiplying 3 0.1's (0.1^3)
However, we are finding the root here so my explanation above tells us that a cuberoot of a positive number is never a negative.

So the answer is 0.1
Answer 2
Answer: 0.1

0.1^3 = 0.1*0.1*0.1 = 0.01*0.1 = 0.001

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Of the hundred and 25 invited to a wedding, 104 attended the wedding. What percent of the invited guests attended the wedding??

Answers

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Hy! (√2+1)²+(3-√3)²-(√5+1)²=???
Thank yours!:*

Answers

(\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\n2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\n20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\n14+2\sqrt2-6\sqrt3-2\sqrt5

On Tuesday Paul bought eight boxes. On Wednesday half of all the boxes that he had were destroyed. On Thursday there were only 17 left. How many did he have on Monday?

Answers

Answer:

13

Step-by-step explanation:

8/2 = 4

17 - 4 = 13

the 13 remaining must have been brought on monday

Candy is on sale for $0.75 each. you have a coupon for $0.25 off your total purchase. Write a function rule for the cost of n pieces of candy. A. C(n)0.25n-0.75
B. C(n)=0.75n-0.25
C. C(n)=1.0n
D. C(n)=0.75n

Answers

Answer:

B. C(n)=0.75n-0.25

Step-by-step explanation:

Given : Cost of one candy = $0.75

            There is a coupon of $0.25 off on total purchase .

To Find :  Write a function rule for the cost of n pieces of candy.

Solution :

Since we are given that total candies bought = n

Cost of one candy =  $0.75

Cost of n candy =  $0.75n

So, cost of total purchase  = $0.75n

Since on total purchase there is a off of $0.25

So, cost of total purchase after off will be $0.75n -$0.25

⇒C(n)= 0.75n-0.25

Where C(n) denotes the total cost after getting off

Hence Option B is correct.

A function rule for the cost of n pieces of candy is C(n)= 0.75n-0.25

Required function rule is C(n) = 0.75n - 0.25

What is the inquality

Answers

Answer:

Step-by-step explanation:

Equations and inequalities are both mathematical sentences formed by relating two expressions to each other. In an equation, the two expressions are deemed equal which is shown by the symbol =. ... An equation or an inequality that contains at least one variable is called an open sentence.

An inequality compares two values, showing if one is less than, greater than, or simply not equal to another value. a ≠ b says that a is not equal to b. a < b says that a is less than b. a > b says that a is greater than b. (those two are known as strict inequality)

Difference in size,degree,circumstances etc lack of equality.

Use synthetic division to solve (x^4 – 1) ÷ (x – 1). What is the quotienta. x^3-x^2+x-1
b. x^3
c.x^3+x^2+x+1
d. x^3-2

Answers

Answer:

Option C.

Step-by-step explanation:

We have to solve (x^(4)-1 )/(x-1) by synthetic division and tell the quotient.

First we will write the numerator in the standard form as ax^(4)+bx^(3)+cx^(2)+dx+e

Which will become as 1.x^(4)+0.x^(3)+0.x^(2)+0.x^(1)-1

Since denominator of the fraction is (x -1) therefore we take x = 1 as zero root.

Now we form the synthetic form as below

          1        0      0    0      -1

1          1        1       1      1      0

          x³      x²      x    

Here coefficient of x³ is 1, for x² is 1, for x is 1, and constant term 1.

Now the fraction will come in the form of  

(x -1) + ((1.x^(3)+1.x^(2)+1.x+1))/((x - 1))

Therefore quotient will be x^(3)+x^(2)+x+1

Option C. is the answer

Hello,

x^4-1=(x²-1)(x²+1)=(x²+1)(x-1)(x+1)
==>(x^4-1)/(x-1)=(x²+1)(x+1)=x^3+x^2+x+1
Answer C