1380 kg car is moving due east with an initial speed of 27.0 m/s. after 8.00 s the car had showd dwn to 17.0 m/s. find the magnitude and direction of the net force that produces the deceleration

Answers

Answer 1
Answer:

Answer:

magnitude of force is 1725 N

direction is opposite to the direction of car moving  i.e west

Explanation:

Given data

car mass = 1380 kg

speed = 27.0 m/s

time = 8 s

speed = 17 m/s

to find out

magnitude and direction of the net force

solution

we find here first acceleration thats formula is

a = v(initial) - v(final) / time

a =27 - 17 / 8

acceleration = 1.25 m/s

so force is = ma

force is = 1380 ( 1.25)

force = 1725 N

so magnitude of force is 1725 N

and this is here direction is opposite to the direction of car moving  i.e west

Answer 2
Answer:

Final answer:

The net force that leads to the deceleration of the 1380 kg car from 27.0 m/s to 17.0 m/s over 8.00 seconds has a magnitude of 1725 N and is directed towards the west.

Explanation:

To solve for the magnitude and direction of the net force that produces the deceleration in the car, you first need to calculate the acceleration and then use it to find the net force using the formula f = m * a. The acceleration here represents a deceleration because the speed is decreasing.

Acceleration can be found using the formula a = (v_f - v_i) / t. Here, v_i is the initial speed (27.0 m/s), v_f is the final speed (17.0 m/s), and t is the time interval (8.00 s). This gives you a = (17.0 m/s - 27.0 m/s) / 8.00 s = -1.25 m/s^2. The negative sign represents deceleration.

Now, apply this deceleration to the formula for force, f = m * a. Here, m is the mass of the car (1380 kg) and a is the value we computed (-1.25 m/s^2). So, f = 1380 kg * -1.25 m/s^2 = -1725 N. The negative sign indicates that the force is in the direction opposite to the initial motion of the car. Therefore, the magnitude of the net force is 1725 N, and the direction is towards the west or opposite to the car's original path.

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