Hey can anyone help I'm so confused on how to this :)

Answers

Answer 1

Answer: I believe that it is 576 inches cubed. You would do length x width x height and get 576.

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I’ll mark brainliest! Pls helpp

How can i evaluate (-7/10+0.15)÷(-0.125) please help

Answers

You can evaluate his by first converting -7/10 into a decimal which would be -0.7 From there, you add -0.7 and 0.15 and divide that by -0.125.

First change all fractions into decimals. Then you PEMDAS to solve. PEMDAS is Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction.So you add the two decimals together and divide it by the other decimal.

A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimeter of the window is 12 feet. what dimensions will produce a window of maximum area? (Round you answers to two decimal places ) what is the width x= what is the length y.?(Question2) write the function in the form f(×) = ×^3- 6×^2- 15×+9, k = -2.
f (×)=?

Answers

Let's find the perimeter of the window.

The bottom side is $x$ . The left and right sides make $2y$ .
The perimeter of a circle is $2\pi r$ , so the perimeter of a semicircle must be $\pi r$ , The radius is $\frac{1}2x$ , so that gives $\frac{1}2\pi x$ for the curve. All of that is equal to 12.

$x+2y+\frac{1}2\pi x=12$

We only want to use one variable to create the area formula, so let's solve for $y$ .

$2y=12-x-\frac{1}2\pi x$

$y=6-\frac{1}2x-\frac{1}4\pi x$

Now that we have a value for $y$ in terms of $x$ , we can find the area in terms of $x$ .

The area of the rectangle is going to be $xy$ , which then becomes

$A_r=x(6-\frac{1}2x-\frac{1}4\pi x$

$A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2$

The area of the semicircle is going to be $\frac{1}2\pi r^2$ .

Since $r=\frac{1}2x$ , $A_(sc)=\frac{1}2\pi (\frac{1}2x)^2$ .

$A_(sc)=\frac{1}2\pi \frac{1}4x^2$

$A_(sc)=\frac{1}8\pi x^2$

Now let's add the areas of the rectangle and semicircle.

$A=A_r+A_(sc)$

$A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2$

$A=6x-\frac{1}2x^2-\frac{1}8\pi x^2$

If you wanted to factor out $\frac{1}8$ like you did, this would become

$\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}$

Now what we want to do is find what $x$ is when $A$ is at its highest point, Once we have the value for $x$ we can also find the value for $y$ , of course.

Let's put our equation in the general form of a quadratic.

$A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x$

Now we can use the vertex formula $x=(-b)/(2a)$ .
( $a$ and $b$ refer to $ax^2+bx+c$ .)

$x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}$

$x=\frac{-6}{-\frac{1}4\pi -1}$

$x=(-24)/(-\pi -4)$

$\boxed{x=(24)/(\pi +4)}$

Now let's plug that in for $y=6-\frac{1}2x-\frac{1}4\pi x$ .

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use $x\approx3.36059492$ .

$y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)$

$y\approx6-(1.68029746+2.63940507809)$

$\boxed{y\approx1.68029746191}$

Let's take our answers for $x$ and $y$ and round to 2 decimal places.

$\boxed{x\approx 3.36\ ft}$

$\boxed{y\approx 1.68\ ft}$

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the wind if the pilot's speed in still air is 315 miles per hour.

Answers

Given:

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.

Pilot's speed in still air is 315 miles per hour.

To find:

The speed of the wind.

Solution:

Let the speed of wind be x miles per hour.

Speed with wind = 315+x miles per hour

Speed against wind = 315-x miles per hour

We know that,

$Time=(Distance)/(Speed)$

According to the question,

$(450)/(315+x)=(360)/(315-x)$

Divide both sides by 90.

$(5)/(315+x)=(4)/(315-x)$

By cross multiplication, we get

$5(315-x)=4(315+x)$

$5(315)-5x=4(315)+4x$

$5(315)-4(315)=4x+5x$

$(5-4)315=9x$

Divide both sides by 9.

$((1)315)/(9)=x$

$35=x$

Therefore, the speed of wind is 35 miles per hour.

Final answer:

The speed of the wind is calculated using uniform motion equations for when the pilot is traveling with the wind and against the wind is w = 45 mph,

Explanation:

This is a problem that involves uniform motion, often taught in high school algebra. Let's denote the speed of the wind as w. Since the time it takes for the pilot to travel 450 miles with the wind is the same as the time it takes for them to travel 360 miles against the wind, we can establish two equations which both equal to time (distance/speed).

With the wind: 450/(315+w) = time

Against the wind: 360/(315-w) = time

As both sides equal to 'time', we can equate them together:

450/(315+w) = 360/(315-w)

Solving this equation, we find that w = 45 mph, which is the speed of the wind.

Learn more about Speed of the wind here:

brainly.com/question/34347046

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(–2, –3) is the image produced by applying the composition T -2.4 rx to a point. What are the coordinates of the preimage?A.
(0, –1)
B.
(0, 1)
C.
(3, 4)
D.
(0, 7)

Answers

Answer:

D. (0,7)

Step-by-step explanation:

We are given that,

The point (-2,-3) is transformed by the composition $T_(-2,-4)\circ R_(x)$ .

That is, the point is first reflected across x-axis and then translated 2 units to the left and 4 units up.

So, the rule for the transformation is (x,y) → (x,-y) → (x+2,-y+4)

Thus, the image of (-2,-3) is given by,

(-2,-3) → (-2,3) → (-2+2,3+4) = (0,7)

That is, the image of (-2,-3) after transformation is (0,7).

So, option D is correct.

Find the product.

3y 2 z(2y 2 z + 4yz - y + z)

Answers

Answer: 48(y*z)^2 - 6z*y^2 - 6y*z^2

Step-by-step explanation: We want to find the product:

3y*2z*(2y*2z + 4yz - y - z)

First, distribute the product:

3y*2z*2y*2z + 3y*2z*4yz -*3y*2z*y - 3y*2z*z

now, let's simplify the equation:

(3*2*2*2)(y*z)^2 + (3*2*4)(y*z)^2 - (3*2)z*y^2 - (3*2)y*z^2

24(y*z)^2 + 24(y*z)^2 - 6z*y^2 - 6y*z^2

48(y*z)^2 - 6z*y^2 - 6y*z^2

If the equation you want to distribute is:

(3y^2z)*(2y^2z + 4yz - y - z)

the distribution is:

(3y^2z)´*(2y^2z) + (3y^2z)*4yz -(3y^2z)*y - (3y^2z)*z

6y^4z + 12y^(2z + 1)*z - 3y^(3z + 1) - (3y^2z)*z

3y^2z*(2y^4yz-y+z)

=6y^(4z)+12y^(1+2z)z-3y^(1+2z)+3zy^(2z)

HELPPPPPPPP4 Renting video games from Store S costs $2.50 per game plus a monthly fee of

$5.00. Renting video games from Store T costs $5.00 per game with no monthly
fee. The monthly cost to rent video games depends on the number of video
games, v, rented. Which equation represents the situation when the monthly cost
at Store S is equal to the monthly cost at Store T?
F 2.5v + 5 = 5v
G 2.5 + 5v = 5v
H 7.5v = 5v
J 7.5v = 10v

Answers

Answer:

it is c

Step-by-step explanation:

because I said it is

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