MATHEMATICS HIGH SCHOOL

Find the area of the region bounded by the graphs of the equations
2y^2 = x + 4 and x = y^2

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

$2y^2 = x + 4 \rightarrow x = 2y^2 -4$

$x=y^2$

intersection points

$2y^2 - 4 = y^2$

$y^2 =4$

$y = \pm 2 \rightarrow (4, -2)~ and~ (4, 2)$

$\int\limits^2_(-2) (y^2-(2y^2-4)} \, dy$

You finish it by yourself

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What is the value of (6a-2)

Answers

It totally depends on the value of 'a', and if 'a' changes, then (6a-2) immediately changes too. Whatever 'a' is at the moment, (6a-2) is 2 less than 6 times 'a'.

You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much should you charge for the bunch of bananas?

Answers

Cost per pound: 50 ¢.
Weight: 3 pounds

Total cost: 3x50 = 150 ¢

You should charge $1.50 because 1lb = 50cents. 3lb = $1.50.

can someone help me with this and maybe help answer my other questions bc literally nun of my questions being answered

Answers

Answer:

x-5+10 = 2x-7

the 2 lengths are equal

x+5 = 2x-7

x-2x=-7-5

-x=-12

x= 12

What is the volume, in cubic cm, of a cylinder with the height of 16cm and a base radius of 3 cm, to the nearest tenths place?

Answers

452.16 cm³ is the volume of a cylinder with the height of 16cm and a base radius of 3 cm

Volume of cylinder based problem:

Height of cylinder = 16 cm

Radius of cylinder = 3 cm

Volume of cylinder = πr²h

Volume of cylinder = (3.14)(3)²(16)

Volume of cylinder = (3.14)(9)(16)

Volume of cylinder = 452.16 cm³

Find out more information about 'Cylinder'.

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How do you do...
cos2x-sin2x=1-2sin2x

Answers

$sin (2 \alpha) =2\cdot sin \alpha \cdot cos \alpha \ncos(2 \alpha )=1-2sin^2 \alpha \n-------------------- \ncos2x-sin2x=1-2sin2x\ncos2x+sin2x=1\n1-2sin^2x+2sinx\cdot cosx=1\n-2sinx(sin x-cosx)=0\n -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\n\n1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\n2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \ cos x \neq 0\ntanx=1\ \ \Leftrightarrow\ \ x_2= ( \pi )/(4) +k \pi \ \ and\ \ k\in I$