Answer: D) Use a vacuum cleaner equipped with a HEPA filter while wearing your PPE
Explanation:
Laser tone particle takes approximately 15 minutes for settle down as it is finely grounded particle. To avoid the inhaling of laser tone particles try to keep the air stable and leave the printer sometime after cleaning its area.
HEPA filter is the high efficiency filter which basically particulate air and improve the quality of air. It made up of variety of materials like glass filters, vegetable fiber etc.
The main application of HEPA filter that it is using as vacuum cleaner equipment and must wear personal protective equipment (PPE) while using this types of equipment.
The correct answer is:
Cloud storage refers to the storage of data on a server on the internet.
Every organization relies on data, In our daily job, we all make use of a huge amount of data(either in gigabytes or terabytes). And if you have a lot of files on your computer, it's probable that your computer may lose momentum and slow down, resulting in bad performance. While there are several external storage options available for storing and backing up your data, these devices are not infallible. Any incident, such as theft, or damage, might result in the loss of vital data.
This is where Cloud Storage comes into play. Cloud storage is a handy and dependable method of storing and retrieving information on the internet.
It is a cloud computing system in which data is stored on the server-side of the Internet and is managed and operated by a cloud computing provider.
Therefore, from the above explanation, we can conclude that the correct Option is D
Learn more about Cloud Storage here:
Answer:
D. server on the internet
Explanation:
b. Surge suppressor
c. CRT
d. UPS
Answer: A) Battery backup
Explanation:
A battery backup are used to provide the source of power backup to various hardware components and desktop computers. In many cases, the devices are plugged into UPS ( uninterruptible power supply) for backup power and it is also depend upon the size of the UPS.
All the battery backups are located inside so that is why, the devices are heavy in weight. Usually, the battery backup front required additional button for performing various functions.
And the battery backup devices are manufacture by using the varying degree of backup abilities.
Answer:
Expected CPU time: 1.875 seconds.
Input a String:
code
Input an integer:
3
eeedddoooccc
import java.util.*;
public class myClass {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.print("Input a String: ");
String str = scan.nextLine();
System.out.print("Input an integer: ");
int num = scan.nextInt();
for(int i=str.length()-1; i>=0; i--) {
for(int j=0; j<num; j++) {
System.out.print(str.charAt(i));
}
}
}
}
b. 24 = 16 subnets, 228 - 2 = 268E6 hosts per subnetwork
c. 24 - 2 = 14 subnets, 24 = 16 hosts per subnetwork
d. 24 = 16 subnets, 24 - 2 = 14 hosts per subnetwork
Answer:
d. 24 = 16 subnets, 24 - 2 = 14 hosts per subnetwork
Explanation:
When four bits are borrowed from the fourth octet of class C IP address 200.245.10.150, the IP address is subnetted to 16 subnets, where the number of subnets is equal to two raised to the number of borrowed bits (ie, 2^ number of borrowed bits), and 14 assignable host IP address gotten from the formula;
= 2^(number of host bits in the fourth octet) - 2
= (2^4) - 2
= 16 - 2 = 14 host addresses
Answer:
import java.util.Scanner;
public class num12 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the first String");
String word1 = in.nextLine();
System.out.println("Enter the second String");
String word2 = in.nextLine();
System.out.println("Enter the third String");
String word3 = in.nextLine();
//Remove all white spaces
String cword1 = word1.replace(" ","");
String cword2 = word2.replace(" ","");
String cword3 = word3.replace(" ","");
//Comparing the string by their lengths
if(cword1.length()>cword2.length()&&cword1.length()>cword3.length()){
System.out.println(word1+" Is the longest");
}
else if(cword2.length()>cword1.length()&&cword2.length()>cword3.length()){
System.out.println(word2+" Is the longest");
}
else{
System.out.println(cword3+" Is the longest");
}
}
}
Explanation:
Using Java Programming Language
Use the Scanner Class to obtain the String values from the user
Save them in different variables
Use the replace() method in java to remove white space from any of the string entered
Using if and else statements compare the lengths of the strings (word.length()) returns the length of the word.
Print out the word that is longest
NOTE I have compared three Strings, comparing two would have been more straigth forward