Answer:
540 nm
Explanation:
According to the question,
The refractive index of the soap bubble, .
The thickness of the soap bubble wall is, .
Now, for constructive interference of soap bubble.
.
Now for first order m=1.
Therfore,
Substitute all the variables in the above equation.
.
Therefore,
.
Therefore the visible light wavelength which is strongly reflected is 540 nm.
Answer:
electric flux is 280 Nm²/C
so correct option is D 280 Nm²/C
Explanation:
radius r = 0.50 m
angle = 30 degree
field strength = 713 N/C
to find out
the electric flux through the surface
solution
we find here electric flux by given formula that is
electric flux = field strength × area× cos∅ .......1
here area = πr² = π(0.50)²
put here all value in equation 1
electric flux = field strength × area× cos∅
electric flux = 713 × π(0.50)² × cos60
we consider the cosine of the angle between the direction of the field and the normal to the surface of the disk
so we use cos60
electric flux = 280 Nm²/C
so correct option is D 280 Nm²/C
The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s is 720 J/s.
Power is the workdone by a body in one second.
To calculate the work done by the horse in one seconds, we use the formula below
Formula:
Where:
From the question,
Given:
Substitute these values into equation 1
Hence, the amount of work done per second by the horse is 720 J/s.
Learn more about power here: brainly.com/question/25864308
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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.
Answer:
Explanation:
The mass balance is an application of conservation of mass, to the analysis of physical system. This is given in an equation form as
Input = Output + Accumulation
The conservation law that is used in this analysis of the system actually depends on the context of the problem. Nevertheless, they all revolve around conservation of mass. By conservation of mass, I mean that the fact that matter cannot disappear or be created spontaneously.
Calculate BE/A, the binding energy per nucleon, for 2H in megaelecton volts per nucleon
Answer:
0.88 MeV/nucleon
Explanation:
The binding energy (B) per nucleon of deuterium can be calculated using the following equation:
Where:
Z: is the number of protons = 1
N: is the number of neutrons = 1
: is the proton's mass = 1.00730 u
: is the neutron's mass = 1.00869 u
M: is the nucleu's mass = 2.01410
A = Z + N = 1 + 1 = 2
Now, the binding energy per nucleon for ²H is:
Therefore, the binding energy per nucleon for ²H is 0.88 MeV/nucleon.
I hope it helps you!
The binding energy per nucleon for 2H (deuterium) is 1.1125 MeV per nucleon.
The binding energy per nucleon, or BE/A, can be calculated by dividing the total binding energy of the nucleus by the number of nucleons. To calculate the BE/A for 2H (deuterium), we need to know the total binding energy and the number of nucleons in deuterium. The total binding energy of deuterium is approximately 2.225 MeV (megaelectron volts) and the number of nucleons is 2. Therefore, the BE/A for 2H is 2.225 MeV / 2 = 1.1125 MeV per nucleon.
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Answer:
n = 1.22 10⁴ turns/m
Explanation:
The magnetic field in a solenoid is proportional to the intensity of the current, the number of turns per unit length (n) and the magnetic permeability (myo), is described by the equation
B = μ₀ n I
Let's clear the density of turns
n = B / (μ₀ I)
Let's replace and calculate
n = 5.81 / (4pi 10-7 3.79 102)
n = 5.81 105 / 47.63
n = 1.22 10⁴ turns / m
Answer:
The near point of an eye with power of +2 dopters, u' = - 50 cm
Given:
Power of a contact lens, P = +2.0 diopters
Solution:
To calculate the near point, we need to find the focal length of the lens which is given by:
Power, P =
where
f = focal length
Thus
f =
f = = + 0.5 m
The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.
Now, by using lens maker formula:
where
u = object distance = 25 cm = 0.25 m = near point of a normal eye
u' = image distance
Now,
Solving the above eqn, we get:
u' = - 0.5 m = - 50 cm