Two different pairs of negative integers, x and y, that make the statement x − y = −1 true

Answers

Answer 1

Answer: one way is
solve for x
add y to both sides
x=y-1

sub negative values for y and get negative values for x
if y=-1, x=-2
if y=-3, x=-4
and so on

some points
(-2,-1)
(-3,-2)
(-4,-3)
(-5,-4)
(-6,-5)
etc

Answer 2

Answer: No, X+Y (both of them being negative integers) equal -1. Just a small miscalculation.

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What is the solution set of {x | x < -3} ∪ {x | x > 5}

Answers

The union of two sets is defined as all elements that are members of both sets.

The first set evaluuates to (...,...,...-7,-6,-5,-4) and the second eveluates to (6,7,8,9,...,...).

There are no elements that belong to both sets so the solution is the empty set. {∅}

Another way is to think about it in words: "What number(s) are less than -3 and also greater than 5?" There are no numbers that fit both of these.

This math my life depends on it

Answers

A geometric sequence is one in which consecutive terms form a fixed ratio r. In other words, if aₙ is the nth term in the sequence, then

$a_n = a_(n-1)r$

For example, if a₁ = a is the 1st term, then

2nd term = a₂ = a₁r

3rd term = a₃ = a₂r = a₁r²

4th term = a₄ = a₃r = a₁r³

and so on. It's fairly easy to infer that

nth term = $a_n = a_(n-1)r = a_(n-2)r^2 = a_(n-3)r^3 = \cdots = a_1r^(n-1)$

14. We're given the 2nd and 5th terms, a₂ = -243 and a₅ = -9, and we use them to find the ratio r.

a₅ = a₄r = a₃r² = a₂r³

-9 = -243 r³

r³ = 1/27

⇒ r = 1/3

Then the 1st term is

a₁ = a₂/r = -243/(1/3) = -729

and the nth term is recursively given by

$a_n = \frac13a_(n-1)$

and explicitly by

$a_n = \left(\frac13\right)^(n-1) a_1 = -(729)/(3^(n-1)) = -(3^6)/(3^(n-1)) = -3^(7-n)$

15. Now we have a₄ = 1/72 and a₃ = -1/12. Using what we know about geometric sequences, we have

a₄ / a₃ = (a₃r) / a₃ = r

so that

r = (1/72) / (-1/12) = -1/6

Then the 1st term is

a₁ = a₂/r = a₃/r² = (-1/12) / (-1/6)² = -3

and the nth term is recursively given by

$a_n = -\frac16a_(n-1)$

and explicitly by

$a_n = \left(-\frac16\right)^(n-1) (-3) = -3\cdot(-6)^(1-n) = 3\cdot(-1)^n\cdot6^(1-n)$

A is the point with coordinates (4,6)b is the point with coordinates (d,21)
the graident of line AB is 3
what is the value of d

Answers

Answer:

d = 9

Step-by-step explanation:

Calculate the slope of ab then equate to 3.

Calculate the slope m using the slope formula

m = $(y_(2)-y_(1) )/(x_(2)-x_(1) )$

with (x₁, y₁ ) = (4, 6) and (x₂, y₂ ) = (d, 21)

m = $(21-6)/(d-4)$ = $(15)/(d-4)$ = 3 ( multiply both sides by d - 4 )

3(d - 4) = 15 ( divide both sides by 3 )

d - 4 = 5 ( add 4 to both sides )

d = 9

Jackie's broker charges her a commission of $8.25 per ten of stocks she buys or sells. If Jackie buys 69 shares of Alesia Insurance at $10.34 per share, how much will Jackie spend in commission?

Answers

69 = (6 × 10) + 9

6 × $8.25 = $49.50

Jackie will spend $49.50 in commission.

Solve - 2x - 8> 3x + 12.
Please help!

Answers

Answer:

B. X < -4

Step-by-step explanation:

-2x - 8 > 3x + 12

Subtract 3x from both sides

-5x -8 > 12

Add 8 both sides

-5x > 20

Divide -5 both sides

X < -4

Answer: x < -4

Step-by-step explanation:

Subtract 3x from both sides

-5x - 8 > 12

Add 8 to both sides

-5x > 20

Divide both sides by -5

x < -4

Find the vertex of a function f(x)=-3x^2+9x-15 by completing the square

Answers

The vertex will be (3/2, - 33/4)

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