How does an increase in cold working effect Modulus of Elasticity and why?

Answers

Answer 1

Answer:

Answer:

There is a decrease in modulus of elasticity

Explanation:

Young's Modulus of elasticity also known as elastic modulus is the deformation of a body along a particular axis under the action of opposing forces along that axis. at atomic levels, it depends on bond energy or strength.

In cold working processes, plastic deformation a metal occurs below its re-crystallization temperature due to which crystal structure of metal gets distorted and as a result of dislocations fractures also occur resulting in hardening of metal but bonds at atomic levels defining elasticity are temporarily affected.

Thus an increase in cold working results in a decrease in modulus of elasticity.

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n Section 12.3 it was mentioned that temperatures are often measured with electrical resistance thermometers made of platinum wire. Suppose that the resistance of a platinum resistance thermometer is 125 Ω when its temperature is 20.0°C. The wire is then immersed in boiling chlorine, and the resistance drops to 99.6 Ω. The temperature coefficient of resistivity of platinum is α = 3.72 × 10−3(C°)−1. What is the temperature of the boiling chlorine?

Answers

Answer:

- 48.55 degree

Explanation:

Resistance increases when temperature increases. This increase is linear and which is defined by the following relation between resistance and temperature

$R_t=R_0(1-\alpha* t)$

$R_t$ is resistance at temperature t , R₀ is resistance at temperature t₀ , t is rise in temperature and α is temperature coefficient of resistance .

Putting the values we get

125 = 99.6 ( 1 + 3.72x 10⁻³ x t )

t = 68.55

Therefore temperature of boiling chlorine is 20-68.55 = - 48.55 degree celsius .

A 4,667 kHz AM radio station broadcasts with a power of 84 kW. How many photons does the transmitting antenna emit each second.

Answers

Answer:

Explanation:

Frequency( ν ) 4667 x 10³ Hz = 4.667 x 10⁶ Hz

Energy of one photon = hν [ h is plank's constant ]

= 6.6 x 10⁻³⁴ x 4.667 x 10⁶ = 30.8 x 10⁻²⁸ J

Power = 84 x 10³ J/s

No of photons emitted = Power / energy of one photon

= 84 x 10³ / 30.8 x 10⁻²⁸ =2.727 x 10³¹ per second .

A rabbit is moving in the negative x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 13.9 m/s along the negative y-axis, all in 1.20 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.) HINT

Answers

Answer:

Explanation:

Initial velocity u = -1.1 i m /s ( along - ve direction )

final velocity = - 13.9 j

change in velocity = -13.9 j + 1.1 i

rate of change of velocity

acceleration

= (-13.9 j + 1.1 i) / 1.2

= -11.58 j + 0.916 i

x component

= 0.916 m /s²

y component

= - 11.58 m / s²

Select the correct answer.If the coefficient of static friction is 0.35 and the normal force is 80 newtons, what is the maximum frictional force of the surface acting on the object?
O A.
B.
C.
OD.
OE
9.8 newtons
28 newtons
80 newtons
23 newtons
35 newtons

Answers

Final answer:

The maximum frictional force acting on the object is 28 newtons.

Explanation:

The maximum frictional force acting on an object can be calculated using the formula:

Frictional force = coefficient of static friction x normal force

Given that the coefficient of static friction is 0.35 and the normal force is 80 newtons, we can calculate the maximum frictional force as follows:

Maximum frictional force = 0.35 x 80 = 28 newtons

Learn more about Calculating maximum frictional force here:

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A truck traveling with an initial velocity of 44.1 m/s comes to a stop in 15.91 secs. What is theacceleration of the truck?

Answers

Answer:

a=-2.77 m/s^2

Explanation:

Assuming constant acceleration,

v=at + v_0

where v_0 is the initial velocity.

At rest, v=0, so

0=at+v_0

So solving the equation for a:

a=(-v_0)/t

Inserting the numbers yields

a=-2.77 m/s^2

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