Tram leaves Piccadilly to Eccles every 9 minutes and to didsbury every 12 minutes. A tram to Eccles and a tram to didsbury both leave Piccadilly at 9am. At what time will a tram to Eccles and a train to didsbury next leave picadilly at the same time?

Answers

Answer 1
Answer: See, the lowest common multiple of 9 and 12 is 36.
So the trams will leave together 36 minutes after they have left together the first time.
So it will be 36 minutes after 9 am.
So the time is 9:36 am. 
Hope I helped!!! You can contact me via messaging if you have any further doubts!

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What is the answer to 1 plus 8

Answers

Answer:

9

Step-by-step explanation:

;-;

Answer:

the answer to your question is 9

Step-by-step explanation:

1+(1+1+1+1+1+1+1+1)=9

Order from least to greatest with decimals

Answers

1) 1.037
2) 1.073
3) 1.37
4) 1.703

Harrison mows lawns and rakes leaves for his summer and fall weekend jobs. He gets $10 an hour to mow lawns and $8 an hour to rake leaves. If, during September, Harrison mows for m hours and rakes for 12 hours, which expression represents the amount of money he makes

Answers

The expression which represents the amount of money he makes is 10m + 96

How to be write mathematical expression?

  • Amount earned per hour for lawns = $10
  • Amount earned per hour to rake leaves = $8
  • Number of hours mowed = m
  • Number of hours raked = 12 hours

Total amount of money earned = (10 × m) + (8 × 12)

= 10m + 96

Therefore, the expression which represents the amount of money he makes is 10m + 96

Learn more about mathematical expression:

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10m+8(12)

Harrison mowes lawns for 11 hours, so m=11. How Much money does he make in September? He makes 206 $.

A sporting goods store sells triangular team pennants in two sizes. The base of one pennant is 18 in. and the length of the side is 9 in. The other pennant is similar to the larger pennant and has a base that is 6 in.What is the length of the side of the smaller pennant?

Answers

This is a proportion problem because the problem stated that the two team pennants are similar.

Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base =   6 in ; length = x ?

9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x

The length of the  side of the smaller pennant is 3 inches.

Answer:the answer is 3inches

Step-by-step explanation:

What is an equation of the line that passes through the point (-2, -3) and isparallel to the line 4x - y = 12

Answers

Answer: y = 4x + 5

Step-by-step explanation:

Find the slope of the second line.

4x - y = 12

-y = -4x + 12

y = 4x - 12

slope = 4

Therefore, the slope of the second line must also be 4.

Use point-slope form to write the equation.

y + 3 = 4(x + 2)

y = 4x + 5

The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard deviation 4 inches. Which of the following represents the middle 80 percent of the heights ? A. 2.5% B. 5% C. 16% D. 1%

Answers

The interval that represent the middle 80% of the heights (inches) is [64.88, 75.12].

Step-by-step explanation:

Given :

Mean -- \rm \mu = 70 \; inches

Standard Deviation -- \rm \sigma = 4 \; inches

Calculation :

We want to know an interval in which the probability that a height falls there is 0.8.  

In such interval, the probability that a value is higher than the right end of the interval is

\rm P(x>z)  = \frac {1-0.8}{2} = 0.1  

If x is the distribuition of heights, then we want y such that P(x > y) = 0.1.

Z =  (x-\mu)/(\sigma)

 

Now, let

U = (y-70)/(4)  

We have

\rm 0.1 = P(x>y)= P((x-70)/(4) > (y-70)/(4))=P(Z>U)=1-\phi(U)

\phi (U) = 1-0.1=0.9      

by looking at the table, we find that U = 1.28, therefore

(y-70)/(4)=1.28

1.28* 4 + 70 = y

y=75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is

70- (75.12-70) = 64.88.  

The interval that represent the middle 80% of the heights (inches) is [64.88, 75.12].

For more information, refer the link given below

brainly.com/question/10729938?referrer=searchResults

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = (X-\mu)/(\sigma) = (X-70)/(4)

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = (z-70)/(4) . We have

0.1 = P(X > z) = P((X-70)/(4) > (z-70)/(4)) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

(z-70)/(4) = 1.28\nz = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .