PHYSICS HIGH SCHOOL

The force between two charges is 1000 N. One has a charge of 2 × 10-5 C, and the other has a charge of 5 × 10-6 C. What is the distance between them?

Answers

Answer 1
Answer: Use the Coulomb Law:

F=k.(q_1.q_2)/(d^2)\n \n 1000=9.10^9.(2.10^(-5).5.10^(-6))/(d^2)\n \n 1000d^2=9.10^9.2.10^(-5).5.10^(-6)\n \n d^2=(9.10^9.2.10^(-5).5.10^(-6))/(10^3)\n \n d^2=(9)/(10^4)\n \n d=\sqrt{(9)/(10^4)}=(3)/(100)=0,03 \ m
Answer 2
Answer:

Final answer:

The distance between the charges is calculated using Coulomb's Law and found to be 0.134m or 13.4 cm.

Explanation:

This problem can be solved using Coulomb's Law. The formula for Coulomb's Law is: F = k*(|q1*q2|)/r², where F is the force between the charges, q1 and q2 are the amounts of charge, r is the distance between the charges, and k is Coulomb's constant (approximately 9.00 x 10^9 N*(m²/C²)).

Giving the values, we have, 1000 N = 9.00 x 10^9 N*(m²/C²)*((2 x 10^-5 C) * (5 x 10^-6 C))/r².

Solving for r (the distance between the charges) in this equation, we first divide both sides of the equation by the values on the right, excluding r, which gives us: r² = ((2 x 10^-5 C) * (5 x 10^-6 C) * 9.00 x 10^9 N*(m²/C²))/1000N.

Calculating the values in this equation and then taking the square root of the result gives r = 0.134 m or 13.4 cm which is the distance between the two charges.

Learn more about Coulomb's Law here:

brainly.com/question/506926

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Which statement is true concerning the evidence for black holes?Scientists can see black holes with powerful telescopes.

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How to do this problem

Answers

Answer:

v = 12,4 m/s

Explanation:

frictionless means all gravitational Energie (Eg) will be converted to kinetic Energie (Ek)

Ek = 0.5 * m * v^2

Ez = m * g * h

Ek = Ez

0.5 * m * v^2 = m * g * h

divide left and right of the = sign by m.

(This means that the final velocity is independent of the mass of both children !)

0.5 * v^2 = g * h

v^2 = 2 * g * h

v = +- SQRT (2 * g * h)

with

g = 9.8 m/s^2

h = 7,8 m/s

v = +- SQRT (2 * 9.8 * 7.8)

v = +- SQRT (152.88)

(v = - 12,4 m/s has no meaning in this case)

The velocity 7,8 m below the starting point, will be

v = 12,4 m/s

Answer:

the answer is 336.96 mph

Explanation:

hope this helps ^_~

An object traveling in a straight line accelerates. What will definitely happen due to the acceleration?The distance traveled in a certain time will increase.
The displacement covered in a certain time will decrease.
The speed of the object will stay constant.
The velocity of the object will change.

Answers


"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning.  So . . .

-- The distance traveled in a certain time may increase or decrease.

-- The displacement covered in a certain time may increase or decrease.

-- The speed of the object may increase or decrease.

-- The velocity of the object (speed/direction) will change.

Simon draws a diagram to illustrate the law of reflection.Which best explains how Simon can correct the error in his diagram?

Draw the incident ray so it is longer than the reflected ray.
Make the angle of reflection and the angle of incidence equal.
Switch the labels for incident ray and reflected ray.
Make the angle of incidence larger than the angle of reflection.

Answers

Answer:

Make the angle of reflection and the angle of incidence equal.

Explanation:

The law of reflection states that at the point of incidence on a smooth surface, the angle of incidence is equal to the angle  of reflection, The incident ray, the normal and the reflected ray lie on the same plane.

Answer:

B.  Make the angle of reflection and the angle of incidence equal

Explanation:

The rate at which light energy flows through a given area of space is referred to as its

Answers

intensity is the word you are looking for!

An automobile covered the distance of 240 km between A and B with a certain speed. On its way back, the automobile covered half of the distance at the same speed and for the rest of the trip he increased his speed by 10 km/hour. As a result, the drive back took him 2 5 of an hour less than the drive from A to B. What was the automobile’s speed when it was driving from A to B?

Answers

Answer:

Therefore the speed of automobile when it was driving from A to B was 50 km/ h.

Explanation:

Given that,

An automobile covered the distance of 240 km between A and B with a certain speed.

Let the speed of the automobile be x km/hour.

We know that,

Time =(distance)/(speed)

Time taken to travel from A to B point is =(240)/(x) hours.

On its back, the automobile covered half of distance= 120 km at the same speed and for the trip he increased his speed 10 km/hour.

Time taken to complete the trip is

=((120)/(x)+(120)/(x+10)) hours

The driver took \frac25 of an hour less when he come back.

According to problem,

(240)/(x)-((120)/(x)+(120)/(x+10))=\frac25

\Rightarrow(240)/(x)- (120)/(x)-(120)/(x+10)=\frac25

\Rightarrow(240-120)/(x)-(120)/(x+10)=\frac25

\Rightarrow(120)/(x)-(120)/(x+10)=\frac25

\Rightarrow(120(x+10)-120x)/(x(x+10))=\frac25

\Rightarrow(120x+1200-120x)/(x^2+10x)=\frac25

\Rightarrow(1200)/(x^2+10x)=\frac25

\Rightarrow 2(x^2+10x)=1200* 5

\Rightarrow (x^2+10x)=(1200* 5)/(2)

\Rightarrow (x^2+10x)=3000

\Rightarrow x^2+10x-3000=0

\Rightarrow x^2+60x-50x-3000=0

⇒x(x+60)-50(x+60)=0

⇒(x+60)(x-50)=0

⇒x= -60, 50

The speed could not negative.

So, x=50

Therefore the speed of automobile when it was driving from A to B was 50 km/ h.
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