B. Wave A has the higher frequency. It's frequency is 25 Hz
C. Wave B has the higher frequency. It's frequency is 42 Hz
D. Wave B has the higher frequency. It's frequency is 7 Hz
Answer:
B
Explanation:
Answer:
480 mph
Explanation:
speed = 60 mph
time = 8 hours
distance = speed*time
= 60*8
= 480 mph
Answer:
x = v₀ cos θ t, y = y₀ + v₀ sin θ t - ½ g t2
Explanation:
This is a projectile launch exercise, in this case we will write the equations for the x and y axes
Let's use trigonometry to find the components of the initial velocity
sin θ = / v₀
cos θ = v₀ₓ / v₀
v_{y} = v_{oy} sin θ
v₀ₓ = vo cos θ
now let's write the equations of motion
X axis
x = v₀ₓ t
x = v₀ cos θ t
vₓ = v₀ cos θ
Y axis
y = y₀ + t - ½ g t2
y = y₀ + v₀ sin θ t - ½ g t2
v_{y} = v₀ - g t
v_{y} = v₀ sin θ - gt
= v_{oy}^2 sin² θ - 2 g y
As we can see the fundamental change is that between the horizontal launch and the inclined launch, the velocity has components
If a projectile is thrown at an angle above the horizontal, this introduces an additional vertical velocity component. This would affect the equations of Parts C and E by changing the values substituted into them, thereby altering the results for time of flight, highest point, and distance traveled.
If the projectile is thrown from a cliff at an angle above the horizontal, it would introduce a vertical component to the initial velocity in the equations. The equations of motion in Parts C and E would therefore need to incorporate this changed initial velocity.
In the equations, the initial vertical velocity is usually denoted by Vi*sin(θ), where θ is the angle at which the projectile is launched. Similarly, the horizontal velocity is expressed as Vi*cos(θ).
This additional vertical component would affect the time of flight, the height reached by the projectile, and the horizontal distance traveled before it hits the ground. Thus, while the form of the equations might not change, the values substituted into them would.
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Answer:
The initial velocity of the skater is 13.22 m/s.
Explanation:
Given that,
Acceleration of the skater,
Distance covered, d = 50 m
The skater's final velocity was, v = 20 m/s
We need to find the initial velocity of the skater. It can be calculated using third equation of motion as :
So, the initial velocity of the skater is 13.22 m/s. Hence, this is the required solution.
Learn more,
Kinematics
https://brainly.in/question/10299229
Answer:
Vi = Vf - (a * t) just plug this in.
Vi stands for “initial velocity”
Vf stands for “final velocity”
a stands for “acceleration”
t stands for “time”