Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann’s constant is 1.38066 × 10−23 J/K. Determine the most probable speed of a helium atom. Answer in units of m/s.

Answers

Answer 1
Answer:

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_(mp)=\sqrt{(2K_bT)/(m)}

K_b= Boltzmann’s constant =1.38066* 10^(-23) J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65* 10^(-27) kg

T = 6.4 K

Substituting all the given values :

v_(mp)=\sqrt{(2* 1.38066* 10^(-23) J/K* 6.4 K)/(6.65* 10^(-27) kg)}

v_(mp)=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.


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Answers

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