Select the true statement about triangle ABC. Need answer asap
Select the true statement about triangle ABC. Need answer asap - 1

Answers

Answer 1
Answer:

Answer:  The correct option is

(B) \sin C=\cos A.

Step-by-step explanation:  We are given to select the true statement about the triangle ABC shown in the figure.

From the figure, we note that

triangle ABC is right-angled at angle B, where hypotenuse, AC = 13, BC = 5 and AB = 12.

From the trigonometric ratios, we have

\sin A=\frac{\textup{perpendicular}}{\textup{hypotenuse}}=(BC)/(AC)=(5)/(13),\n\n\n\cos A=\frac{\textup{base}}{\textup{hypotenuse}}=(AB)/(AC)=(12)/(13),\n\n\n\cos B=\frac{\textup{base}}{\textup{hypotenuse}}=(BC)/(AC)=(5)/(13),\n\n\n\sin C=\frac{\textup{perpendicular}}{\textup{hypotenuse}}=(AB)/(AC)=(12)/(13),\n\n\n\sin A=\frac{\textup{perpendicular}}{\textup{hypotenuse}}=(BC)/(AC)=(5)/(13),\n\n\n\tan A=\frac{\textup{perpendicular}}{\textup{base}}=(BC)/(AB)=(5)/(12).

Therefore, we get

\sin C=\cos A.

Thus, option (B) is CORRECT.

Answer 2
Answer: B. sinC= cosA
Remember SohCahToa.
The sine is equal to opposite/hypotenuse and cosine is equal to adjacent over hypotenuse.
The sine of C is 12/13 and the cosine of A is 12/13.

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Hope I helped!
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To find the difference of 7 - 3 5/12 how do you rename the 7?

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3 5/12 is a mixed number, where 3 is a whole number and 5/12 is a fraction. Now you can tansform 7 in a mixed number with a fraction that contains 12 as denominator. The easiest way is using the fraction 12/12, which means that you make 7 = 6 and 12/12. Now you can subtract 6 12/12 - 3 5/12 by subtrancting the whole and the fractions by separate. 6 - 3 = 3 and 12/12 - 5/12 = 7/12. So the answer is 3 and 7/12 = 3 7/12.
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