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Answer 1

Answer:

Answer:

$1000 at 1.03%p/a

Step-by-step explanation:

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Trent Linda and Pam were will work together to paint a poster that is 4 feet long each student will paint and equal length of the poster how many feet of posterior Lane will each student paint
Find the sum or difference. Write your answer in simplest form. 1. + 2. PLEASE SHOW WORK and these codes actually fractions if u press to answer:)
An online store sells DVDs for $10 each. The shipping charge for an entire order is $5.50. Frank orders d DVDs. Write an expression that represents he total cost of Frank's DVDs.
Standard form: y=-3x^2-6x+1Vertex form: y=-3(x-1)^2+4Factored form: ?
At 5:00 p.m., Antonio turned on the oven. While the oven preheated, the temperature in the oven increased from 72°F to 400°F over a 10-minute period. The oven remained at 400°F for 45 minutes until Antonio turned it off. It took 60 minutes for the temperature in the oven to cool, returning to 72°F at 6:55 p.m. Which statement best explains whether or not the temperature in the oven is a function of the time?A. It is a function because at any given time the oven was exactly one temperature.B. It is a function because the oven temperature was the same at different times.C. It is not a function because at any given time the oven was exactly one temperature.D. It is not a function because the oven temperature was the same at different times.

What are the roots of the equation x^2+6x-9=0

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Answer:

The roots of the quadratic equation are

$x=-3+3√(2)$

$x=-3-3√(2)$

Step-by-step explanation:

we have

$x^(2) +6x-9=0$

we know that

The formula to solve a quadratic equation of the form $ax^(2) +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

$x^(2) +6x-9=0$

$a=1\nb=6\nc=-9$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^(2)-4(1)(-9)}} {2(1)}$

$x=\frac{-6(+/-)√(72)} {2}$

$x=\frac{-6(+/-)6√(2)} {2}$

$x=-3(+/-)3√(2)$

$x=-3(+)3√(2)$

$x=-3(-)3√(2)$

Given equation is :

$x^(2)+6x-9=0$

We will solve this quadratic equation, using the formula:

$x1,2=\frac{-b+\sqrt{b^(2)-4ac}}{2a}$ and

$x1,2=\frac{-b-\sqrt{b^(2)-4ac}}{2a}$

Now, putting a=1 , b=6 and c =-9 we get

$x=\frac{-6+\sqrt{6^(2)-4*1(-9)}}{2*1}$ and

$x=\frac{-6-\sqrt{6^(2)-4*1(-9)}}{2*1}$

Final solutions are: $x=3(√(2)-1)$ and

$x=-3(√(2)+1)$

45 out of 50 what wa sthe percent of his grade

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45/50×100%
=45/1×2
=90%

45/50 is 90% hope that helps you

Find all the powers of 4 in the range 4 through 1000

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4 raised to power 1 = 4¹ = 4

4 raised to power 2 = 4² = 16

4 raised to power 3 = 4³ = 64

4 raised to power 4 = 4⁴ = 256

4 raised to power 2 = 4⁵ = 1024. This is outside the range, so it is excluded.

All the powers are 4, 16, 64 and 256

I don't understand fractions. Please help me.

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Fractions are one number over another number

As someone already said, fractions are one number over another number. But for this particular problem you would do 5 3/4 times 4 (since she jogged that many miles each day for four days) and then add that to the product of 2 3/5 times 7 (since she walked that many miles each day for seven days). You add them because it says what is the total number of miles Rachel walked and jogged last week. I then got 41 1/5 miles. So Rachel walked and jogged last week for 41 1/5 mikes.

In a group of 75 fourth graders, 20% do not like hot chocolate. How many students like hot chocolate

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$20\%\ do\ not\ like\ hot\ chocolate,\ therefore\n100\%-20\%=80\%\ like\ hot\ chocolate\n\np\%=(p)/(100)\to80\%=(80)/(100)=(8)/(10)=(4)/(5)\n\n80\%\ of\ 75=(4)/(5)\cdot75=4\cdot15=\boxed{60}\leftarrow answer$

Let find how many do not like hot chocolate.

.20*75 = 15 fourth graders don't like hot chocolate.

Now lets see how many like hot chocolate

75 -15 = 60 kids like hot chocolate.

Another way to do this is you know that 20% of kids don't like hot chocolate then that means 80% must like hot chocolate.

So now you just have to do .8*75 and you get 60

A telephone company charges a fixed monthly rate plus a rate per megabyte of data used. The company charges $135 for 100 megabytes of data and $375 for 500 megabytes of data. An equation can be written to show the relationship between the total megabytes used (x) and the total monthly charges (y). Which of the following best describes the steps to draw the graph? Draw a graph that joins the points (135, 100) and (375, 500) and has a slope = 0.6 Draw a graph that joins the points (100, 135) and (500, 375) and has a slope = 0.6 Draw a graph that joins the points (100, 135) and (500, 375) and has a slope = 1.67 Draw a graph that joins the points (135, 100) and (375, 500) and has a slope = 1.67

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Answer:

Second option: Draw a graph that joins the points $(100, 135)$ and $(500, 375)$ and has a $slope=0.6$

Step-by-step explanation:

We know that the company charges $135 for 100 megabytes of data and $375 for 500 megabytes of data.

This gives us two points:

$(100,135)\n\n(500,375)$

Then, we can find the slope of the line with this formula:

$m=(y_2-y_1)/(x_2-x_1)$

In this case we can identify that:

$y_2=135\ny_1=375\n\nx_2=100\nx_1=500$

Substituting these values into the formula, we get that the slope is:

$m=(135-375)/(100-500)=0.6$

Therefore the best description for the steps to draw the graph is:

Draw a graph that joins the points $(100, 135)$ and $(500, 375)$ and has a slope of 0.6

Draw a graph that joins the points (100, 135) and (500, 375) and has a slope = 0.6 is correct.

To represent the relationship between total megabytes used (x) and total monthly charges (y).

We need to create a linear equation in the form of y = mx + b, where m is the slope and b is the y-intercept.

Given that the telephone company charges $135 for 100 megabytes of data and $375 for 500 megabytes of data, we have two points: (100, 135) and (500, 375).

The slope (m) can be calculated using the formula:

m=y₂-y₁/x₂-x₁

m=375-135/500-100

=240/400

=0.6

So, the correct option is Draw a graph that joins the points (100, 135) and (500, 375) and has a slope = 0.6.

To learn more on slope intercept form click:

brainly.com/question/9682526

#SPJ3

Someone help meeeeee!!!​

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Someone help meeeeee!!!