Answer:
It is actually all of these
Explanation:
Several factors could account for the variance seen in the third trial's melting time. This could be due to using a larger quantity of compound, starting at a lower temperature, or the burner not being directly under the compound.
The radical difference in melting time for trial 3 in Michelle's experiment could be explained by several variables. Given the information present, Michelle could have used a larger quantity of compound in trial 3, thus taking longer to melt. Secondly, the compound may have started at a lower temperature, requiring additional time to reach its melting point. Finally, if the burner was not directly under the compound, this could also explain the longer time as the heat wouldn't be as concentrated on the compound. In other words, the answer could be 'all of these' as they are all potential reasons as to why the third trial had a heavier melting time.
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Some vehicles, like trailers, have different rules for registration and renewal
Before registering a trailer, you will generally need to submit a signed title to verify your ownership. Alternately, you might be able to use a manufacturer’s statement of origin.
You will also need to sign and submit an application for the license and title of the trailer, along with receipts of applicable property taxes. Finally, you will need to pay the registration fees.
Before you make a trip to the DMV, make sure to have two forms of photo ID on hand to verify your identity when you speak with an agent. For example, your driver’s license might serve as the primary form of ID, and a passport could serve as the second.
If you do not have a passport, you could use a military identification card instead. If your only form of photo ID is your driver’s license, be sure to have other forms of identification on hand, such as your birth certificate and the card with your Social Security number.
Hence Some vehicles, like trailers, have different rules for registration and renewal.
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Answer:
trailers
Explanation:
B. crankshaft.
C. piston.
D. spark plug.
C. piston.
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Explanation:
Consider a mass of 10 kg, so m = 10
Let's say we apply a net force of 20 newtons, so F = 20
The acceleration 'a' is...
F = ma
20 = 10a
20/10 = a
2 = a
a = 2
The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.
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Now let's double the net force on the object
F = 20 goes to F = 40
m = 10 stays the same
F = ma
40 = 10a
10a = 40
a = 40/10
a = 4
The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.
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In summary, if you double the net force applied to the object, then the acceleration doubles as well.
Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.
So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.
We don't know anything about the "trials". This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.
We also don't know anything about "question 1".
b. periodic condensations and rarefactions.
c. high- and low-pressure regions.
d. all of the above E. none of the above
Sound waves in air are a series of periodic condensations and rarefactions.
Sound waves in air are a series of periodic condensations and rarefactions. When a sound is produced, it creates compression regions (areas of high pressure) and rarefaction regions (areas of low pressure) that propagate through the air. These alternating regions of high and low pressure create the characteristic waveform of the sound wave.
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Part A: The enmeshed cars were moving at a velocity of approximately 8.66 m/s just after the collision.
Part B: Car A was traveling at a velocity of approximately 8.55 m/s just before the collision.
To find the speed of car A just before the collision in Part B, you can use the principle of conservation of momentum.
The total momentum of the system before the collision should equal the total momentum after the collision. You already know the total momentum after the collision from Part A, and now you want to find the velocity of car A just before the collision.
Let's denote:
- v_A as the initial velocity of car A before the collision.
- v_B as the initial velocity of car B before the collision.
In Part A, you found that the enmeshed cars were moving at a velocity of 8.66 m/s at an angle of 60 degrees south of east. You can split this velocity into its eastward and southward components. The eastward component of this velocity is:
v_east = 8.66 m/s * cos(60 degrees)
Now, you can use the conservation of momentum to set up an equation:
Total initial momentum = Total final momentum
(mass_A * v_A) + (mass_B * v_B) = (mass_A + mass_B) * 8.66 m/s (the final velocity you found in Part A)
Plug in the known values:
(1900 kg * v_A) + (1500 kg * v_B) = (1900 kg + 1500 kg) * 8.66 m/s
Now, you can solve for v_A:
(1900 kg * v_A) + (1500 kg * v_B) = 3400 kg * 8.66 m/s
1900 kg * v_A = 3400 kg * 8.66 m/s - 1500 kg * v_B
v_A = (3400 kg * 8.66 m/s - 1500 kg * v_B) / 1900 kg
Now, plug in the values from Part A to find v_A:
v_A = (3400 kg * 8.66 m/s - 1500 kg * 8.66 m/s) / 1900 kg
v_A = (29244 kg*m/s - 12990 kg*m/s) / 1900 kg
v_A = 16254 kg*m/s / 1900 kg
v_A ≈ 8.55 m/s
So, car A was going at approximately 8.55 m/s just before the collision in Part B.
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