Answer:
A bool can hold only true or false values.
A char can hold maximum 65535 characters.
An int can hold maximum positive value of 2,147,483,647.
A float can hold maximum positive value of 3.4 x 10^{38}.
Explanation:
Primitive data types in Java language can be categorized into boolean and numeric data types.
Numeric can be divided further into floating point and integral type. Floating data type includes float and double values while and integral data type which consists of char, int, short, long and byte data types.
Every data type has a range of values it can hold, i.e., every data type has a minimum and maximum predefined value which it is allowed to hold. The intermediate values fall in the range of that particular data type.
Any value outside the range of that particular data type will not compile and an error message will be displayed.
The data types commonly used in programming are boolean, char, int and float.
A boolean variable can have only two values, true or false.
A char variable can hold from 0 to 65535 characters. Maximum, 65535 characters are allowed in a character variable. At the minimum, a char variable will have no characters or it will be a null char variable, having no value.
An int variable has the range from minimum -2^{31} to maximum 2^{31} – 1. Hence, the maximum positive value an int variable can hold is (2^{31}) – 1.
A float variable can hold minimum value of 1.4 x 10^{-45} and maximum positive value of 3.4 x 10^{38}.
The above description relates to the data types and their respective range of values in Java language.
The values for boolean variable remain the same across all programming languages.
The range of values for char, int and float data types are different in other languages.
The program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit can be implemented in Python using regular expressions. The regular expression pattern for the SSN format can be used to validate the input.
Pythons code:
```python
import re
ssn_pattern = re.compile(r'^\d{3}-\d{2}-\d{4}$')
ssn = input("Enter your Social Security Number (format: ddd-dd-dddd): ")
if ssn_pattern.match(ssn):
print("Valid SSN")
else:
print("Invalid SSN")
```
In the above code, we first import the `re` module to work with regular expressions.
We then define the regular expression pattern for the SSN format as `^\d{3}-\d{2}-\d{4}$`. This pattern matches any string that starts with three digits, followed by a hyphen, then two digits, another hyphen, and finally, four digits.
We then prompt the user to enter their SSN using the `input()` function. We then check if the entered SSN matches the pattern using the `match()` function of the regular expression object `ssn_pattern`.
If the SSN matches the pattern, we print "Valid SSN". Otherwise, we print "Invalid SSN".
Know more about SSN,
#SPJ4
ssn = input("Enter a valid Social Security number: ")
dashes = 0
nums = 0
message = "Invalid SSN"
if len(ssn) == 11:
for x in ssn:
if x.isdigit():
nums += 1
elif x == "-":
dashes += 1
if nums == 9 and dashes == 2:
message = "Valid SSN"
print(message)
I wrote my code in python 3.8. I hope this helps!
Create a pane using FlowPane in each stage
Add three buttons to each pane
Directions
Create a class named FlowPaneDemo extends Application
Create user interface using FlowPane
Add the instances of 3 Buttons to pane1 created by FlowPane and other 3 instances of Buttons using FlowPane to pane2
Create scene1 for pane1 with a specific size and scene2 for pane2 with a different size
Set different titles to two stages and display two stages
The output should look like the screen below
Provide appropriate Java comments
Answer:
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.layout.FlowPane;
import javafx.stage.Stage;
import javafx.scene.control.Button;
public class FlowPaneDemo extends Application {
public void start(Stage primaryStage) {
// TODO Auto-generated method stub
//Creates a FlowPane for each stage.
FlowPane paneOne = new FlowPane();
FlowPane paneTwo = new FlowPane();
//Creates six Buttons, three for each Flow Pane.
Button buttonOne = new Button("Button One");
Button buttonTwo = new Button("Button Two");
Button buttonThree = new Button("Button Three");
Button buttonFour = new Button("Button Four");
Button buttonFive = new Button("Button Five");
Button buttonSix = new Button("Button Six");
//Adds the Buttons to the two FlowPanes.
paneOne.getChildren().add(buttonOne);
paneOne.getChildren().add(buttonTwo);
paneOne.getChildren().add(buttonThree);
paneTwo.getChildren().add(buttonFour);
paneTwo.getChildren().add(buttonFive);
paneTwo.getChildren().add(buttonSix);
//Creates two Scenes, using each of the FlowPanes.
Scene sceneOne = new Scene(paneOne, 250, 600);
Scene sceneTwo = new Scene(paneTwo, 320, 400);
//Makes a second Stage.
Stage secondaryStage = new Stage();
//Set the title and Scenes for the two Stages.
primaryStage.setTitle("First Stage");
primaryStage.setScene(sceneOne);
secondaryStage.setTitle("Second Stage");
secondaryStage.setScene(sceneTwo);
//Runs the show methods for the two Stages.
primaryStage.show();
secondaryStage.show();
}
public static void main(String[] args){
//Runs the launch method to start a stand-alone JavaFX application; only needed
//as I am running this in Eclipse.
Application.launch(args);
}
}
The statement which gives the sum of nickel and dime is written below :
total_coins = nickel_count + dime_count
The statement required is written using Python 3 :
deftotal(nickel_count, dime_count) :
total_coins =dime_count+nickel_count
print(total_coins)
total(100, 200)
#the function total takes in two arguments(number of nickels and number of dimes)
#assigns the varibale total_coins to the sum of nickel_count and dime_count
nickel_count = int(input('Enter count of nickel : '))
# User is prompted to enter number of nickels
dime_count = int(input('Enter count of dime : '))
# User is prompted to enter number of dimes
total_coins = nickel_count + dime_count
#assigns the varibale total_coins to the sum of nickel_count and dime_count
print(total_coins)
#outputs the value of total_coins
Learn more : brainly.com/question/17615351
Answer:
total_coins = nickel_count + dime_count
Explanation:
The statement that performs the operation in the question is total_coins = nickel_count + dime_count
Full Program (Written in Python)
nickel_count = int(input("Nickel Count: "))
dime_count = int(input("Dime Count: "))
total_coins = nickel_count + dime_count
print("Total coins: ",total_coins)
The first two lines prompt user for nickel and dime count respectively
The third line adds the two coins categories together
The last line prints the total count of coins
Answer:
input number
calculate modulus of the number and 5
compare outcome to 0
if 0 then output "divisible by 5"
else output "not divisible by 5"
Explanation:
The modulo operator is key here. It returns the remainder after integer division. So 8 mod 5 for example is 3, since 5x1+3 = 8. Only if the outcome is 0, you know the number you divided is a multiple of 5.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
My laptop's current screen resolution is (1366 by 768 recommended). When you change your screen resolution, your pc automatically suggests the recommended screen resolution that helps you to view more information on your screen and enable you to fit the most information on the screen while still being able to read the display.
To change the screen resolution, you need to go through from the following steps:
Answer:
It's pie chart because it shows the percentage of multiple things.
Explanation:
And I did an exam aced it and got this question right.