Answer:
Establishing Tight deadlines for a rush job.
Explanation:
The time taken for a rush job has nothing to do with the art director because it has nothing to do with art. Also rush jobs already call for tight deadlines so technically the deadline is already established.
Answer: cropping a photograph for the sake of space
Explanation: edge 22
Answer:
(III) machines don't strike or file grievances.
(IV) machines are always less expensive than human labor.
Explanation:
The advantage of automation among the option is:
(III) machines don't strike or file grievances - Machine has the advantage of not going on strike or filing grievances. It just obey instruction. Strike are human way of showing grievances. With automation, there is no issue of strike or filing for grievance.
(IV) machines are always less expensive than human labor - Machines as a means of automation are very cheap when compared to human labor. The only added cost for machine is the added cost after the cost of purchase. For human labor, the cost is not fixed or predictable.
Answer:
The single greatest physical threat to information systems is:
Sabotage
Explanation:
Sabotage describes the efforts of internal persons to ensure that a system does not operate as intended or is destroyed. Among the threats to information systems, this is the greatest. The problem with sabotage is that the operators are internal, they know the system very well. They understand the weak points and the strengths of the system. They are internal terrorists to any information system. These internal saboteurs are capable of using any means to achieve their purpose. Therefore, it is necessary to scrutinize employees from time to time to discover internal risks.
Answer:
Given Data:
Clock rate of P1 = 4 GHz
Clock rate of P2 = 3 GHz
Average CPI of P1 = 0.9
Number of Instructions = 5.0E9 = 5 × 10^9
Clock rate of P2 = 3 GHz
Average CPI of P2 = 0.75
Number of Instructions = 1.0E9 = 10^9
To find: If the computer with largest clock rate has the largest performance?
Explanation:
Solution:
As given in the question, clock rate of P1 = 4 GHz which is greater than clock rate of P2 = 3 GHz
According to the performance equation:
CPU Time = instruction count * average cycles per instruction/ clock rate
CPU Time = I * CPI / clock rate
Where instruction count refers to the number of instructions.
Performance of P1:
CPU Time (P1) = 5 * 10^9 * 0.9 / (4 * 10^9)
= 5000000000 * 0.9 / 4000000000
= 4500000000 / 4000000000
= 1.125s
Performance of P2:
CPU Time (P2) = 10^9 * 0.75/ (3 * 10^9)
= 750000000 / 3000000000
= 0.25s
So the Performance of P2 is larger than that of P1,
performance (P2) > performance (P1)
0.25 is better than 1.125
But clock rate of P1 was larger than P2
clock rate of P1 > clock rate of P2
4 GHz > 3 GHz
So this is a misconception about P1 and P2.
It is not true that computer with the largest clock rate as having the largest performance.
Answer:
import java.util.Scanner;
public class num12 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the first String");
String word1 = in.nextLine();
System.out.println("Enter the second String");
String word2 = in.nextLine();
System.out.println("Enter the third String");
String word3 = in.nextLine();
//Remove all white spaces
String cword1 = word1.replace(" ","");
String cword2 = word2.replace(" ","");
String cword3 = word3.replace(" ","");
//Comparing the string by their lengths
if(cword1.length()>cword2.length()&&cword1.length()>cword3.length()){
System.out.println(word1+" Is the longest");
}
else if(cword2.length()>cword1.length()&&cword2.length()>cword3.length()){
System.out.println(word2+" Is the longest");
}
else{
System.out.println(cword3+" Is the longest");
}
}
}
Explanation:
Using Java Programming Language
Use the Scanner Class to obtain the String values from the user
Save them in different variables
Use the replace() method in java to remove white space from any of the string entered
Using if and else statements compare the lengths of the strings (word.length()) returns the length of the word.
Print out the word that is longest
NOTE I have compared three Strings, comparing two would have been more straigth forward