We are required to calculate the number of days it would take the apprentice working alone
The number of days it takes the apprentice working alone is 6 days
let
Number of days taken for the carpenter to work alone = x
Number of days taken by the apprentice to work alone = 2x
Number of days taken to work together = 2 days
Work done per day Carpenter = 1/x
work done per day apprentice = 1/2x
work done per day together = 1/2
So,
work done per day together = Work done per day Carpenter + work done per day apprentice
1/2 = 1/x + 1/2x
1/2 = (2 + 1) / 2x
1/2 = 3/2x
cross product
1(2x) = 2(3)
2x = 6
x = 6/2
x = 3 days
Therefore,
Number of days taken by the apprentice to work alone = 2x
= 2(3)
= 6 days
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Answer:
6 days
Step-by-step explanation:
Let the time taken by Carpenter working alone = days
Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 days
Time taken working together = 2 days
Work done in one day working together =
Work done in one day by Carpenter working alone =
Work done in one day by apprentice working alone =
Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = + = Work done in one day working together =
Time taken by Carpenter alone to complete the work = 3 days
Time taken by Apprentice alone to complete the work = 3 2= 6 days
Answer:
Step-by-step explanation:
From the information being provided;
We learnt that Becky pays simple interest at an annual interest rate of 8.8% which is calculated quarterly.
i.e.
Since the first payment of $27,000 happened in the first three months, therefore, Becky will be able to have the money in the bank for 3 quarters prior to the lump-sum payment gets started.
Thus, the estimate of the amount Becky would earn as interest during this period of time is as follows:
I = $1,782
Answer:
Domain:
(−∞,∞),{x|x∈R}
Step-by-step explanation:
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