13
16
19
20.5
23.5
Other:
Answer:
The median of the data in the table is 19.
Step-by-step explanation:
We are given the following data that shows the number of cars Jing sold each month last year below;
Number of cars Jing sold: 13, 16, 19, 20.5, 23.5
For calculating the median, firstly we have to observe that the number of observations (n) in our data is even or odd because;
Median =
Median =
Here, the number of observations in our data is odd, i.e. n = 5.
So, Median =
=
=
= 3rd obs. = 19
Hence, the median of the data in the table is 19.
B 248, –616, 248
C 216, –648, 1944
D –648, 1944, –5832
Answer: D –648, 1944, –5832
Step-by-step explanation:
Given sequence: –8, 24, –72, 216, . . .
Here we can see that the next term is -3 times the previous term.
Such that
therefore, the term after 216=
Then term after -648 =
Term after 1944=
Thus, D is the right answer. The next three terms of the sequence are –648, 1944, –5832
y = -x+2
Answer:
y = 3x - 6
y = -x+2
To solve the system of equations graphically, graph both equations on a set of axes, then find the intersection point, which is the solution to the system.
To solve the system of equations graphically, we first need to graph each equation on a set of axes.
The first equation, y = 3x - 6, is a straight line with a slope of 3 and a y-intercept (where the line crosses the y-axis) at -6. To graph this, start at point (0, -6) on the y-axis, then move up 3 units and to the right 1 unit to find the next point. Repeat this process to plot several points, then draw a straight line through them.
The second equation, y = -x + 2, is also a line, but with a slope of -1 and a y-intercept at 2. Start at point (0, 2) on the y-axis, then move down 1 unit and to the right 1 unit. Draw a straight line through the points.
The solution to the system of equations is the point where the two lines intersect on the graph. By examining the graph, you can determine this point.
#SPJ3
Answer:
C = 4x + 2000 es la ecuación
El costo de los rodamientos de soporte 950 es de $ 5,800
Step-by-step explanation:
Esperamos una gráfica lineal de costo contra el número de rodamiento de respaldo.
Un punto en este diagrama tendrá una representación como (número de demoras, costo)
Ahora, a partir de la pregunta, podemos identificar dos puntos; (300,3200) y (700,4800)
Generalmente, la ecuación de una línea recta tiene la forma
y = mx + c
donde m es la pendiente y c es la intersección en y
Lo que esto significa en esta línea es que tenemos dos cosas para calcular, que es la pendiente de la línea y la intersección de la línea. Usando los dos puntos podemos calcular estos.
matemáticamente, la pendiente se puede calcular como;
tenemos m = (4800-3200) / (700-300) = 1600/400 = 4
Como conocemos la pendiente, el modelo lineal ahora se convierte en
y = 4x + c
Para obtener el valor de la intersección con el eje y, podemos usar cualquiera de los dos puntos. Digamos que queremos usar el primer punto (300,3200)
3200 = 4 (300) + c
3200 = 1,200 + c
c = 3200-1200
c = 2000
Así la ecuación se convierte
y = 4x + 2000
Ahora usemos los parámetros definidos en la pregunta, tenemos;
C = 4x + 2000
donde C es el costo yx es el número de rodamientos de soporte
Ahora queremos calcular el costo de 950 rodamientos
Simplemente usamos la ecuación que hemos modelado donde en este punto, x = 950
C = 4 (950) + 2000
C = $ 5,800