The mean of a set of data can be determined from a box-and-whisker plot.True
False

Answers

Answer 1

Answer: Your answer is True

It is true that the mean of a set of data can be determined from a box-and-whisker plot.

Hope I Helped You!!! :-)

Have A Good Day!!!

Answer 2

Answer: The mean of a set of data that can be determined from a box and whisker plot is true.

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The rate of 8 pencils for 9 dollars

Answers

I think the answer is 1.125

What effect does the following line have on the poem?the wheat waved and wilted under the wind

a. It creates a sense of being stuck in a box.
b. It imitates the whirring sound of the wind.
c. It compares wind to wheat.
d. It shows the difference between wheat and a flower that wilts.

Answers

I think it would be b. You should double check though

Answer:

it is b

Step-by-step explanation:

i went to study island and got it right

Square root of 512k^2. show work

Answers

we are asked to evaluate the square root of the expression 512 k^2.512 is not a perfect square but is divisible by the perfect square 256. square root of 256 is 16. hence square root of 512 is 16 square root of 2. square root of k2 meanwhile is equal to k. The answer hence is 16k square root of 2

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)

Answers

For this case we have the following functions:
$f (x) = 4 - x ^ 2 g (x) = 6x$
The first thing we must do is subtract both functions.
We have then:
$(g - f) (x) = g (x) - f (x)$
Substituting values we have:
$(g - f) (x) = (6x) - (4 - x ^ 2)$
Rewriting we have:
$(g - f) (x) = x ^ 2 + 6x - 4$
Then, we evaluate the function for x = 3.
We have then:
$(g - f) (3) = 3 ^ 2 + 6 (3) - 4$
Rewriting:
$(g - f) (3) = 9 + 18 - 4 (g - f) (3) = 23$
Answer:
An expression that is equivalent to (g - f) (3) is:
$(g - f) (3) = 23$

Answer:

$(g-f)(3)=23$

Step-by-step explanation:

Given : $f(x) = 4 -x^2$ and $g(x) = 6x$

To find : The value of $(g -f)(3)$

Solution :

First we find the value of (g-f)

$(g-f)(x)= g(x)-f(x)$

$(g-f)(x)=6x-(4-x^2)$

$(g-f)(x)=6x-4+x^2$

Now, put the value of x=3

$(g-f)(3)=6(3)-4+(3)^2$

$(g-f)(3)=18-4+9$

$(g-f)(3)=23$

Therefore, $(g-f)(3)=23$

A Roast is taken from the refrigerator (where it had been for several days) and placed immediately in a preheated oven to cook. The temperature R = R(t) of the roast t minutes after being placed in the oven is given bya. What is the temperature of the refrigerator?

b. Express the temperature of the roast 30 minutes after being put in the oven in functional notation, and then calculate its value.

c. By how much did the temperature of the roast increase during the first 10 minutes of cooking?

d. By how much did the temperature of the roast increase from the first hour to 10 minutes after the first hour of cooking?

Answers

Answer:

Step-by-step explanation:

a. We are not given enough information to determine the temperature of the refrigerator.

b. We can express the temperature of the roast 30 minutes after being put in the oven as R(30). Its value depends on the specific function R(t) given in the problem.

c. To find the increase in temperature during the first 10 minutes of cooking, we need to find the difference between the temperature of the roast after 10 minutes and the temperature of the roast when it was put in the oven. This is given by:

R(10) - R(0)

d. To find the increase in temperature from the first hour to 10 minutes after the first hour of cooking, we need to find the difference between the temperature of the roast at 1 hour and 10 minutes and the temperature of the roast at 1 hour. This is given by:

R(70) - R(60)

Final answer:

The temperature of the refrigerator is the initial temperature of the roast. The temperature of the roast 30 minutes after being put in the oven can be expressed as R(30), but its value cannot be determined without a specific function. The temperature increase during specific time intervals can be calculated by finding the difference between the temperatures at the respective times.

Explanation:

a. To find the temperature of the refrigerator, we need to use the given information. Since the roast was in the refrigerator for several days before being placed in the oven, we can assume that the temperature of the refrigerator matches the temperature of the roast initially, which is denoted as R(0). Therefore, the temperature of the refrigerator is R(0).

b. Expressing the temperature of the roast 30 minutes after being put in the oven in functional notation is R(30). To calculate its value, we need the specific function or equation that relates the temperature to time. Without this information, we cannot determine the exact numerical value of R(30).

c. To determine the temperature increase during the first 10 minutes of cooking, we need the temperature difference between the initial temperature of the roast (R(0)) and the temperature after 10 minutes of cooking (R(10)). The increase is given by R(10) - R(0).

d. To find the temperature increase from the first hour to 10 minutes after the first hour of cooking, we need the temperature at the start of the first hour (R(60)) and the temperature at 10 minutes after the first hour (R(60 + 10)). The increase is given by R(60 + 10) - R(60).

Learn more about temperature of the roast here:

brainly.com/question/37575094

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In a survey, 15 high school students said they could drive and 15 said they could not. Out of 60 college students surveyed, 30 said they could drive. Micah concluded that if someone is in college, that means the person is more likely to drive. Is Micah’s conclusion correct? Explain

Answers

No, Micah is not correct. Since there are equal numbers of people in each group who drive and who do not drive, the relative frequency for each is 50%. Because the relative frequencies are the same, there is no association between the variables.

Based on the survey figures by Micah of the college students who could drive, we can infer that Michah's conclusion is not correct.

Why is Michah not correct?

Out of 60 college students surveyed, only 30 said they could drive. This means that only 50% could drive:

= 30 / 60

= 50%

A 50% relative frequency is not good enough to make the conclusion that one is more likely to drive in college. Rather it means that they are equally likely to drive or not to drive.

Find out more on relative frequency at brainly.com/question/3857836.

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