Answer:
eight
Explanation:
In the first stage of DNA replication each DNA molecule replicates into two daughter DNA. In the second stage of DNA replication each of the two daughter DNA molecule replicates into two daughter DNA, thus forming a total of four DNA molecules. In the third stage of DNA replication each of the four daughter DNA molecule replicates into two daughter DNA, thus forming a total of eight DNA molecules.
Answer: A balance is used to determine accurate mass of substances.
Explanation: Electronic balance is used to measure the small to large mass of substance from miligrams to grams to kilograms according to their features. Differnt different Electronic balances are used on the basis of amount to be measure.
In pharmaceuticals , other laboratories , schools , colleges mainly electronic balance is used , as it measure accurate weight of the substances.
express in a chemical formula
The molecular formula of butane is .
Further explanation:
The molecular formula is a chemical formula that depicts the total number and kinds of atoms present in a molecule. For example, molecular formula of carbon dioxide is .
Hydrocarbon is a term for the organic compounds that consist of hydrogen and carbon only.
Types of hydrocarbons:
1. Saturated hydrocarbons
The simplest hydrocarbons that are composed of only single bonds are called saturated hydrocarbons. These hydrocarbons have the general formula of , where n is the number of carbon atoms. These hydrocarbons have suffix “ane” in their names. Examples of such hydrocarbons are methane, hexane, and propane.
2. Unsaturated hydrocarbons
These have one or more multiple bonds in them. These hydrocarbons have suffix “ene” or “yne”, depending on whether there is a double or triple bond between them. Hydrocarbons comprising of double bonds are called alkenes and those having triple bonds are called alkynes.
The name of butane includes the suffix “ane”. This implies it is a saturated hydrocarbon and contains only single bonds in it. The prefix “but” indicates the presence of four carbon atoms in this molecule.
Substitute 4 for n in the general formula of alkane to find out the formula of butane.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Stoichiometry of formulas and equations
Keywords: molecular formula, butane, C4H10, 4, ane, ene, yne, alkane, alkyne, alkene, saturated hydrocarbon, unsaturated hydrocarbon.
the theoretical yield of hydrogen gas is 10 g
calculation
Step 1: write the equation for reaction
Zn + 2 HCl → zncl₂ + H₂
Step 2: use the mole ratio to find the moles of H₂
from equation above Zn : H₂ is 1: 1 therefore the moles of H₂ = 5.00 moles
Step 3: find the theoretical yield(mass) for H₂
mass = moles × molar mass
from periodic table the molar mass of H₂= 1×2 = 2 g/mol
mass = 5 moles × 2 g/mol = 10 grams
Answer:
Explanation:
has stopped?
Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Given data:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Excess reactant's amount left = ?
Solution:
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol
The limiting reactant in the reaction between Ammonia and Oxygen is Ammonia (NH3). All of the Oxygen is used up in the reaction, so no excess reactant remains.
This question involves a concept in chemistry known as limiting reactants and stoichiometry. The balanced chemical reaction between Ammonia (NH3) and Oxygen (O2) is: 4NH3 + 5O2 -> 4NO + 6H2O. This indicates that 4 moles of NH3 react with 5 moles of O2.
To find the limiting reactant, you first need to convert the grams of your reactants to moles. The molar mass of NH3 is approximately 17.0g/mol, and the molar mass of O2 is 32.0g/mol. Therefore, you have 2.00g/17.0g/mol = 0.118 moles of NH3 and 4.00g/32.0g/mol = 0.125 moles of O2.
Since 5 moles of O2 are needed for every 4 moles of NH3, and we have slightly more O2 than NH3, the limiting reactant is NH3. To find the amount of excess reactant, we determine how much O2 actually reacted by multiplying (0.118 moles NH3)*(5 moles O2/4 moles NH3) = 0.1475 moles O2. The original amount of O2 was 0.125 moles, so the amount left over is 0.125 - 0.1475, which is a negative number and thus not possible. This confirms that O2 is the excess reactant, although it entirely reacted. Hence, no excess reactant remains.
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(2) form lighter isotopes from heavier isotopes
(3) convert mass to energy
(4) convert energy to mass
Nuclear fusion differs from nuclear fission because nuclear fusion reactions. Nuclear fusion forms heavier isotopes from lighter isotopes. Nuclear fission forms lighter isotopes from heavier isotopes. therefore, the correct options are option 1,2.
Nuclear fission gets a nuclear process in which the atom's nucleus is divided into smaller nuclei by being blasted with low-energy neutrons. In this process, a large quantity of energy is released. Nuclear fission processes are employed for nuclear power reactors due to their simplicity and high energy output. When multiple atoms unite to produce one heavier nucleus, the process is known as nuclear fusion. In comparison to the energy produced throughout the nuclear fission reaction, a tremendous quantity of energy is released during this process.
To know more about nuclear fusion and nuclear fission, here:
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Answer: industrial smog.
Explanation:
The industrial smog typically exists in the urban industrial areas where the large scale burning of the fossil fuels may lead to generation of huge amount of smoke and sulfur dioxide gas liberated into the atmosphere. These gaseous products gets mixed with the droplets of fog already present in the atmosphere. This lead to the formation of industrial smog. The industrial smog forms a thick blanket of smog or haze nearly close to the ground.
Sulfur dioxide is a primary component of industrial smog and photochemical smog, but it does not directly influence thermal inversion. It is released into the atmosphere predominantly from burning fossil fuels.
Sulfur dioxide is a significant component in the creation of both industrial smog and photochemical smog, two serious urban air pollutants. During industrial activities, fossil fuels such as coal and oil that contain sulfur are burned, releasing sulfur dioxide into the atmosphere. This gas then reacts with water vapor and other compounds to form industrial smog. In the case of photochemical smog, when sulfur dioxide interacts with sunlight, volatile organic compounds, and nitrogen oxides, it contributes to the formation of this harmful type of smog. However, sulfur dioxide does not directly relate to the occurrence of thermal inversion, a weather-related phenomenon that can trap smog and other pollutants close to the ground.
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