A cone has a radius of 5 inches and a height of 18 inches.What is the exact volume of the cone?

A.
150π in3

B.
300π in3

C.
450π in3

D.
540π in3

Answers

Answer 1

Answer: It would be C., because to find the volume, you would have to multiply the radius by itself, to get the diameter. Then, the answer you get will have to be multiplied by the height.: 5 times 5 equals 25, and then 25 times 18 equals 450.

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Please!!! Help!!Let f(x)=x2−4x−32 .

Enter the x-intercepts of the quadratic function in the boxes.

Answers

Answer:

The x-intercepts of the quadratic function are 8 and -4.

Step-by-step explanation:

The given function is

$f(x)=x^2-4x-32$

Equate the function f(x) equal to 0, to find the x-intercepts of the quadratic function.

$f(x)=0$

$x^2-4x-32=0$

The middle term can be written as -8x+4x.

$x^2-8x+4x-32=0$

$x(x-8)+4(x-8)=0$

Take out the common factors.

$(x-8)(x+4)=0$

Using zero product property,

$x-8=0\Rightarrow x=8$

$x+4=0\Rightarrow x=-4$

Therefore the x-intercepts of the quadratic function are 8 and -4.

well the intercepts are (8,0) and (-4,0) its a lot of math so you need to find it i would show you but i have a quiz

im not sure tho soo

a jar contains 65 pennies 27 nickels 30 dimes and 18 quarters a coin is randomly selected from the jar find each probability

Answers

The required probabilities are $P(\text{pennies})=(13)/(28),P(\text{nickels})=(27)/(140),P(\text{dimes})=(3)/(14),P(\text{quarters})=(9)/(70)$ .

Given:

Pennies = 65

Nickels = 27

Dimes = 30

Quarters = 18

To find:

The probability of each.

Solution:

The probability formula:

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcomes}}$

Total number of coins:

$65+27+30+18=140$

The probability of selecting Pennies is:

$P(\text{pennies})=(65)/(140)$

$P(\text{pennies})=(13)/(28)$

The probability of selecting nickels is:

$P(\text{nickels})=(27)/(140)$

The probability of selecting dimes is:

$P(\text{dimes})=(30)/(140)$

$P(\text{dimes})=(3)/(14)$

The probability of selecting quarters is:

$P(\text{quarters})=(18)/(140)$

$P(\text{quarters})=(9)/(70)$

Therefore, the required probabilities are $P(\text{pennies})=(13)/(28),P(\text{nickels})=(27)/(140),P(\text{dimes})=(3)/(14),P(\text{quarters})=(9)/(70)$ .

Learn more:

brainly.com/question/9721191

Simplify this expression: 19 – (–8) – (–14) = ?
A. –7
B. –3
C. 41
D. 25

Answers

The answer is C. 41.

What is the correct order of operations for simplifying the expression (x+3)^2-(x^2+9)/2x^2

Answers

Answer with explanation:

The correct order of simplifying the expression is:

1. Opening the bracket Using Identity

2. Adding and Subtracting Like terms

The given expression is

$=((x+3)^2-(x^2+9))/(2x^2)\n\n=(x^2+6 x+9-x^2-9)/(2x^2)\n\n=(6x)/(2x^2)\n\n=(3)/(x)\n\n \text{Used the identity and law of indices}\n\n(a+b)^2=a^2+2 a b+b^2\n\n (x^a)/(x^b)=x^(a-b)$

$((x+3)^2-(x^2+9))/(2x^2)\n\nuse\ (a+b)^2=a^2+2ab+b^2\n\n=(x^2+2\cdot x\cdot3+3^2-x^2-9)/(2x^2)=(x^2-x^2+6x+9-9)/(2x^2)\n\n=(6x)/(2x^2)=(3)/(x)$

What is the value of p?

Answers

Answer:

the answer is B

Step-by-step explanation:

everything is in the paper

The answer is b because you need to subtract 140-90= 50 P=50 140-90=P

A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 5% real fruit juice and Drink B contains 10% real fruit juice. How many liters of real fruit juice would be needed to produce 250 liters of Drink A and 200 liters of Drink B? How many liters of real fruit juice would be needed to produce aa liters of Drink A and bb liters of Drink B?

Answers

Answer:

a). 12.5 liters of real fruit juice would be needed to produce 250 liters of Drink A, and 20 liters of real fruit juice would be needed to produce 250 liters of Drink B

b). 0.05aa liters of real fruit juice would be needed to produce aa liters of Drink A, and 0.1bb liters of real fruit juice would be needed to produce bb liters of Drink B

Step-by-step explanation:

a). Drinks A(250 liters) and Drink B(200 liters)

Total amount of Drink A=250 liters

Real fruit juice=5% of Drink A=(5/100)×250=12.5 liters

12.5 liters of real fruit juice would be needed to produce 250 liters of Drink A

Total amount of Drink B=200 liters

Real fruit juice=10% of Drink B=(10/100)×200=20 liters

20 liters of real fruit juice would be needed to produce 250 liters of Drink B

b). Drinks aa and bb

Total amount of Drink A=aa liters

Real fruit juice=5% of Drink A=(5/100)×aa=0.05aa liters

0.05aa liters of real fruit juice would be needed to produce aa liters of Drink A

Total amount of Drink B =bb liters

Real fruit juice=10% of Drink 10=(10/100)×bb=0.1bb liters

0.1bb liters of real fruit juice would be needed to produce bb liters of Drink B

Final answer:

To find the amount of real fruit juice needed, multiply the total volume of each drink by the percentage of juice it contains. For 250 liters of Drink A and 200 liters of Drink B, you need 32.5 liters of fruit juice in total. Apply the same method for any quantity of drinks.

Explanation:

We can compute the amount of real fruit juice needed for the drinks by using a similar method as in Chapter 9: multiplying the total volume of each drink by the percentage of real fruit juice it contains.

For Drink A: 250 liters * 5% = 12.5 liters of real fruit juice.

For Drink B: 200 liters * 10% = 20 liters of real fruit juice.

So in total, to produce 250 liters of Drink A and 200 liters of Drink B, you would need 12.5 liters + 20 liters = 32.5 liters of real fruit juice.

For aa liters of Drink A and bb liters of Drink B, you would do the following calculations:

Drink A: aa liters * 5%

Drink B: bb liters * 10%

Add the results from both calculations to get the total liters of real fruit juice needed.

Learn more about Percentage Calculation here:

brainly.com/question/32197511

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A cone has a radius of 5 inches and a height of 18 inches.What is the exact volume of the cone? A. 150π in3 B. 300π in3 C. 450π in3 D. 540π in3

Answers

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Final answer:

Explanation:

Learn more about Percentage Calculation here:

A cone has a radius of 5 inches and a height of 18 inches.What is the exact volume of the cone?

A.
150π in3

B.
300π in3

C.
450π in3

D.
540π in3