What is the name of the guy who invented the multiplication tables?

Answers

Answer 1
Answer: Hello,

It seems that multiplication tables were invented by Pythogore .

Later in the middle ages , a abacus has been invented by a guy who where living near my house : Gerbert d'Aurillac who became pape (Sylvestre 2 ,945-1003).





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How do I move 7.03% into a decimal

Answers

its already in decimal formation.

Jack walks 30 miles at 30 degrees north of east, then walks 30 miles at 45 degrees north of east. how many miles east of his starting point will he end up?

Answers

We are given with the distance traveled and the direction
30 miles at 30 degrees north of east
30 miles at 45 degrees north of east
You calculate the horizontal and vertical component using these equations
x = d cos 
θ
y = d cos θ

where d is the distance traveled

Then, you get the distance from the starting point using the formula
D = √[(∑x)² + (∑y)²]

The answer is
59.47 miles
Hello there.

Jack walks 30 miles at 30 degrees north of east, then walks 30 miles at 45 degrees north of east. how many miles east of his starting point will he end up?
59.47 miles

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below are the weights in pounds of 1111 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that​ sport's league? 186 229 240 257 187 221 309 293 257 274 221

Answers

Answer:

(a) Mean =243.0909

(b) Median = 240

In other words it is the middle value of the data arranged in order.

(c) Mode =  221  and 257

(d) Mid Range =   247.5

e)

Variance = 1578.5037

Standard Deviation = 39.730

Range = 309-186= 123

(e)  No the results are not  likely to be representative of all players in that​ sport's league because they are not similar.

Step-by-step explanation:

First arranging the data in ascending order

186 187 221 221 229 240 257 257  274  293    309

(a) Mean = Sum of observations/ No of observations

       = 186 + 187 + 221 +221 + 229 + 240 + 257 + 257 + 274 + 293 + 309 /11

= 2674/11=

= 243.0909

(b) Median for un grouped data is

Here n = 11 and n/2 = 11/2 is not an integer

Median = Results obtained by ([n/2] +1) player

                   = (11/2 +1) = 6th player in ordered data

                = 240

In other words it is the middle value of the data arranged in order.

(c) Mode = Most frequent values.

There are two modes : 221  and 257 . These both values occur repeatedly.

(d) Mid Range = Maximum Value + minimum value/ 2= 186+ 309/2=  247.5

Now we will find the variance and standard deviation

The variance is given by

s² =  (186-243.0909)²+ (187-243.0909)²+ (221-243.0909)²+ (221 -243.0909)²+(229-243.0909)²+ (240-243.0909)²+( 257-243.0909)²+ (257 -243.0909)²+ (274-243.0909)²+ ( 293-243.0909)²+    (309 -243.0909)²/11-1

s²=  3259.370 + 3146.139+ 488.008+ 488.008+ 198.553+ 9.554+ 193.463 + 193.463 + 955.372 +  2509.098 + 4344.009/10

s²= 15,785.037/10= 1578.5037

And Standard Deviation = s= √1578.5037= 39.730

Variance = 1578.5037

Standard Deviation = 39.730

Range = 309-186= 123

(e)  No the results are not  likely to be representative of all players in that​ sport's league because they are not similar.

Write an equation in standard form for a line that passes through (4,1) & (5,7)

Answers

y = mx + b

First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0

Set them equal to each other, 

m(4) + b - 1 = m(5) + b - 7

If you bring the b over to the left hand side it becomes

m(4) + b - b - 1 = m(5) - 7

m(4) - 1 = m(5) - 7

Solve for m

6 = m

Plug m = 6 into either equation from the beginning,

m(4) + b - 1 = 0

6(4) + b - 1 = 0

24 + b - 1 = 0

b = -23

Knowing m and b we can now make an equation

y = mx + b

y = 6x -23 Final answer



7/8 & 4/9 is closest to 0,1,2,3

Answers

7/8 is closest to 1 and 4/9 is closest to 0
7/8 is closest to 1.
4/9 is closest to 0.
Hope that helped!

Hey guys, I'm really stuck with this problem. A dozen golf balls fit inside a box in the shape of a rectangular prism. The golf balls are packed tightly together and they touch the top, bottom and sides of the box. What percentage of the volume within the box is air? Please show work.

Answers

ok so one way of doingit is
split the box into 12 cubes around each golf ball
nnow find the wasted space that each golf ball wastes around itself since the ratio of the total percent must be the same as the total

so lets say the height of the cubes=2 so therefor volume of  each cube=2^3=8

now find the volume of each apere
volume=4/3pir^3
the height=diameter
diameter/2=radius
2/2=1=radius
volumeofsphere=4/3pi1^3
vs=4/3pi1
vs=4/3pi
aprox pi to 3.14
vs=12.56/3
vs=4.18666

so now we have
total space=8
area of ball=4.186666
percent lost=total-areauseed=8-4.18666=3.81333333
so percent lost=lost/total=3.81333/8=0.397/1
percent means parts out of 100
0.397/1 times 100/100=39.7/100=39.7%


so the answer is 39.7% wasted space (aprox 40%)