If polygon ABCD with vertices A (1, 2), B (1,4), C(2,6), and D (5, 4) is dilated by a factor 3, the coordinates of the dilated polygon are A' (3, 6), B' (3, 12), C' (6, 18), and D' (15, 12).
When a polygon is dilated by a scale factor, all the coordinates of its vertices are multiplied by that scale factor. In this case, the scale factor is 3. Thus, we should multiply the x and y coordinates of each vertex by 3.
Let's calculate:
So, the coordinates of the dilated polygon ABCD are A' (3, 6), B' (3, 12), C' (6, 18), and D' (15, 12).
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Sometimes, Always, or Never?
The sectors of a circle graph never add up to 180 degrees. They always add up to 360 degrees.
Hope it helps:)
Answer:
Step-by-step explanation:
Answer:
x = π/2 + πk
Step-by-step explanation:
cot² x csc² x + 2 csc² x − cot² x = 2
Multiply both sides by sin² x:
cot² x + 2 − cos² x = 2 sin² x
Add cos² x to both sides:
cot² x + 2 = 2 sin² x + cos² x
Pythagorean identity:
cot² x + 2 = sin² x + 1
Subtract 1 from both sides:
cot² x + 1 = sin² x
Pythagorean identity:
csc² x = sin² x
Multiply both sides by sin² x:
1 = sin⁴ x
Take the fourth root:
sin x = ±1
Solve for x:
x = π/2 + 2πk, 3π/2 + 2πk
Which simplifies to:
x = π/2 + πk