What is the solution to the system of equations? Use the linear combination method.2d+e=8
d-e-4

A. There are an infinite number of solutions
B. There is no solution
C. The solution is (4,0)
D. The solution is (5,-2)

Answers

Answer 1
Answer: If you would like to know what is the solution to the system of equations, you can calculate this using the following steps:

2d + e = 8
d - e - 4 = 0 ... d = e + 4
___________________

2d + e = 8
2 * (e + 4) + e = 8
2e + 8 + e = 8
3e = 0
e = 0

d = e + 4 = 0 + 4 = 4

(d, e) = (4, 0)

The correct result would be: C. The solution is (4, 0).

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Sam gave jen 1/2 of his jujubes .jen ate 1/2 ofthe jujubes and gave rest to kyle.kyle kept 8 of the jujubes and gave the last 10 to kim .how many jujubes did Jen eat?

Answers

The solution is,  jen eat 18  jujubes.

What is division?

Division is the process of splitting a number or an amount into equal parts. Division is one of the four basic operations of arithmetic, the ways that numbers are combined to make new numbers. The other operations are addition, subtraction, and multiplication.

here, we have,

Let x = the  jujubes Sam had

he gave x/2 to jen

jen eats half of it  = 1/2(x/2)

                             =    x/4

the remaining  x/4 he gave to kyle

kyle kept 8 and gave 10 to Kim

so

            x/4 - 8 = 10

            x/4 = 18

            x =72

so, we get,

thus    jen had 36 jujubes

jen eat 18  jujubes

Hence, The solution is,  jen eat 18  jujubes.

To learn more on division click:

brainly.com/question/21416852

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Let x = the # jujubes Sam had
he gave x/2 to jen
jen eats half of it  =    1/2(x/2) =    x/4
the remaining  x/4 he gave to kyle
kyle kept 8 and gave 10 to Kim
so
             x/4 - 8 = 10
             x/4 = 18
             x =72
thus    jen had 36 jujubes
jen eat    18  jujubes

A train covered the distance of 400 km between A and B at a certain speed. On the way back it covered 2/5 of the distance at that same speed and then it decreased its speed by 20 km/hour. Find the speed of the train at the end of its journey from B back to A, if the entire trip took 11 hours.

Answers

Answer:

s - 20 = 60 km/hr

Step-by-step explanation:

The distances are the same going there and coming back.

So

Givens

d = 400

2/5 * d = 2/5 * 400 = 160

The rest of the trip back = 400 - 160 = 240

Equation

400/(s) + 160/s + 240/(s - 20) = 11 hours.

Solution

distance / speed = time or

d/s = time

Multiply through by s*(s - 20)

400*(s - 20) + 160*(s - 20) + 240s = 11*s*(s - 20)       Remove the brackets.

400s - 8000 + 160s - 3200 + 240s= 11(s^2 - 20s)   Collect like terms on the left.

560s - 11200 + 240s = 11(s^2 - 20s)                          Remove the brackets on the rt.

800s - 11200 = 11s^2 - 220s                                   Switch and add 220s

11s^2 - 220s + 220s = 800s +220s - 11200          Combine

11s^2 = 1020s - 11200                                            Put everything on the left.

11s^2 - 1020s + 11200 = 0

this quadratic factors into

(11s - 140 )(s - 80) = 0

You have 2 solutions

11s - 140 = 0

11s = 140

s = 140/11

s = 12.727272... This solution won't work because the speed has no room to drop down 20 km / hour

===========

s - 80 = 0

s = 80 km hour

But that is not the answer

=======

The answer you want is s - 20 which is 60 km/hr.

What is the solution set of {x | x 2} ∪ {x | x ≥ 2}

Answers

the solution to this sets union is:

{x | x = 2} ∪ {x | x ≥ 2}
= { x | x >= 2 }

that is the total solution of the union., the second set is a superset of the first, so the total solution is the second set itself.

Find the value of x.

Answers

Answer:

The value of x is 18°

Step-by-step explanation:

Sum of the angles are 180°

3x+126=180

3x=180-126

3x=54

x=18

Answered by GAUTHMATH

Wendy is paid $12 per hour and plans to work between 30 and 35 hours per week. Identify the independent and dependent quantity in the situation. Find reasonable domain and range values.

Answers

Answer:

Part a) The independent quantity is the variable x (the number of hours) and the dependent quantity is the variable y (total paid)

Part b) Domain 30\leq x\leq 35

Part c) Range \$360\leq y\leq \$420

Step-by-step explanation:

Let

x------> the number of hours

y-----> total paid

The linear equation that represent this situation is

y=12x

so

Part a)

The independent quantity is the variable x (the number of hours)

The dependent quantity is the variable y (total paid)

Part b) Find the domain

The domain is the interval--------> [30,35]

All real numbers greater than or equal to 30 hours and less than or equal to 35 hours

30\leq x\leq 35

Part c) Find the range

For x=30

find the value of y

y=12(30)=\$360

For x=35

find the value of y

y=12(35)=\$420

The range is the interval-------> [\$360,\$420]

All real numbers greater than or equal to \$360 and less than or equal to \$420

\$360\leq y\leq \$420

The independent quantity is her pay and the dependent quantity is the hours she works in a week.
I believe the range would be 30 to 35 hours and the domain would be $360 to $450.

How do I solve 3.2x+0.2x^2-5=0

Answers

3.2x+0.2x^2-5=0\ \ \ \ |both\ sides\ multiply\ by\ 5\n\n16x+x^2-25=0\n\nx^2+16x-25=0\n\na=1;\ b=16;\ c=-25\n\n\Delta=b^2-4ac\to\Delta=16^2-4\cdot1\cdot(-25)=256+100=356\n\nx_1=(-b-\sqrt\Delta)/(2a)\ and\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(356)=√(4\cdot89)=2√(89)\n\nx_1=(-16-2√(89))/(2\cdot1)=-8-√(89);\ x_2=(-16+2√(89))/(2\cdot1)=-8+√(89)