Answer:
CA.
Step-by-step explanation:
To find the gradient (slope) of the line 2y - 3x = 6, we need to rewrite the equation in slope-intercept form (y = mx + b), where "m" represents the gradient. Here's how:
2y - 3x = 6
First, isolate "y" on one side of the equation:
2y = 3x + 6
Next, divide both sides by 2 to solve for "y":
y = (3/2)x + 3
Now we can see that the gradient (slope) of the line is (3/2).
Now, let's analyze the three lines AB, BC, and CA, formed by the points A(-5, -12), B(11, -4), and C(7, 6).
The gradient (slope) of the line AB can be calculated using the coordinates of points A and B:
Gradient of AB = (Change in y) / (Change in x) = (-4 - (-12)) / (11 - (-5)) = 8 / 16 = 1/2
The gradient (slope) of the line BC can be calculated using the coordinates of points B and C:
Gradient of BC = (Change in y) / (Change in x) = (6 - (-4)) / (7 - 11) = 10 / (-4) = -5/2
The gradient (slope) of the line CA can be calculated using the coordinates of points C and A:
Gradient of CA = (Change in y) / (Change in x) = (-12 - 6) / (-5 - 7) = -18 / (-12) = 3/2
Now, we compare the gradients of the lines AB, BC, and CA to the gradient of the line 2y - 3x = 6 (which is 3/2). We see that the line CA has the same gradient (3/2) as the line 2y - 3x = 6.
So, the line CA is parallel to the line 2y - 3x = 6.
Answer:
18
Step-by-step explanation:
Answer:
18 because it's asking for the tw
B) Pages in a Book
C)Area of a room
D)Distance
Help ASAP! ): <3
2700=2200(1+r)^5