MATHEMATICS HIGH SCHOOL

Two equations are given below:a – 3b = 16
a = b – 2

What is the solution to the set of equations in the form (a, b)? (5 points)


(–2, –6)
(–7, –9)
(–11, –9)
(–12, –10)

Answers

Answer 1
Answer: Asking the Math Gods...


a=-11
b=-9
Answer 2
Answer: Since a = b - 2, we can substitute this value into the other equation to find the value of b.  Once we have a value for b, we substitute it back into one of the equations to find the value for a.

a - 3b = 16
b - 2 - 3b = 16
-2 - 2b = 16
-2b = 18
b = -9

Now substitute back into the equation

a = b - 2
a = -9 - 2
a = -11

Solution set in the form (a, b) is...

(-11, -9)

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Simplify 81^1/2
Please simplify and show steps

Answers

a^(n)/(m)=\sqrt[m]{a^n}\n\n\n81^(1)/(2)=√(81)=9\n\n\n81^(1)/(2)=(9^2)^(1)/(2)=9^{2\cdot(1)/(2)}=9

The expression 81⁽¹/²⁾ simplifies to 9.

To simplify the expression 81¹/², we can evaluate the squareroot of 81.

The square root of a number x is a value that, when multiplied by itself, gives x. In this case, we're looking for the number that, when squared, equals 81.

The square root of 81 is 9 since 9 x 9 = 81.

Therefore, 81⁽¹/²⁾ simplifies to 9.

In terms of steps, we can represent the process as follows:

1. Recognize that 81⁽¹/²⁾ represents the square root of 81.

2. Evaluate the squareroot of 81, which is 9.

3. Thus, 81^(1/2) simplifies to 9.

By simplifying the expression, we find that 81⁽¹/²⁾is equal to 9.

To learn more about the expression;

brainly.com/question/24242989  

#SPJ6

Which term is a term in this expression? -3x-7(x+4)​

Answers

-7 is the term in the given expression in this problem

What Is the domain of the function

Answers

Domain is 0 <= x < 4

Could somebody Please help me

Answers

Correct answer is B :)
So first you work out the total Surface area (L x W of every quadrilateral, and [L x W]÷2 for triangles)
and then for the lateral surface area, you minus the area of the vertical sides, which are the 2 triangles :)

I’ll mark brainliest! Pls helpp

Answers

Answer:

60 yds

Step-by-step explanation:

10 + 15 + 4 + (10 - 4) + 20 + (20 - 15) = 60

Answer: 60 Yards

In this model, we have all sides except for two. In order to find the perimeter of this, you would need all sides.

To find the missing sides you can see that the lenght of the side on the left is 10 yards. And the entire right side is equal to that left side. So, to find the missing side x you would need to solve: x+10-4. So, x is 6.

Do the same for the top and bottom to get the other missing side that is perpendicular to the side that is 4 yards is 5 yards.

Now that you have the lengths of all of the sides, you can solve for the perimeter. You would do,

15+4+6+20+10+5=60

Please mark brainliest if correct :)

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours. Assume the population standard deviation is the same. Which of the statement below best describes that there is a 95% confidence interval for the mean hours devoted to social networking in January? A. The 95% confidence interval ranges from 8 to 45 hours. B. The 95% confidence interval ranges from 40.13 to 45.78 hours. C. The 95% confidence interval ranges from 43.87 to 46.13 hours. D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Answers

Answer:

D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Step-by-step explanation:

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours.

Here,

n = sample size = 50,

μ = mean = 45,

σ = standard deviation = 8,

We know that, confidence interval will be,

=\mu\ \pm\ z(\sigma )/(√(n))

For a confidence interval of 95%, we use z = 1.96, putting the values

=45\ \pm\ 1.96(8)/(√(50))

=42.78,47.22
D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

To solve the interval, we used the upper and lower limit formulas wherein:
xbar = 45
z = 1.96
s = 8
n = 50
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