Answer: The empirical formula of compound is .
Explanation:
Mass of Sample= 0.702 g
Mass of = 1.4 g
Mass of = 0.86 g
Mass of = 0.478 g
First we have to calculate moles of, and formed.
1. Moles of
Now , Moles of carbon == Moles of = 0.032
2. Moles of =0.048mol
Now , Moles of hydrogen = Moles of =
3. Moles of mol
Now , Moles of silicon = Moles of = 0.008 moles
Therefore, the ratio of number of moles of C : H : Si is = 0.032 : 0.096 : 0.008
For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C=
For H =
For Si=
Thus, C: H: Si = 4 : 12 : 1
The simplest ratio represent empirical formula.
Hence, the empirical formula of compound is .
the length of ribbon needed to tie around a vase
B.
the size of a student's waist
C.
the distance from the ground to the top of a ramp
D.
the circumference of an orange
Answer:
C
the distance from the ground to the top of a ramp
Answer:
The most likely reason is that spent fuel bars can infect the community with radiation causing numerous health problems.
Explanation:
A spent fuel is a fuel that has been exposed to irradiation in a nuclear reactor. This fuel expels radiation and this is one of the main reasons why a group of people oppose the storage of spent fuel bars in their community. This is because through this fuel can occur a leak of radiation contaminating the community and generating major health problems.
(b) H NMR: 2.6 ppm (singlet, I = 3H), 3.9 ppm (singlet, I = 3H), 6.9 ppm (doublet, I = 2H), 7.9 ppm (doublet, I = 2H)
(c) 13C NMR: 26.2, 55.4, 113.7, 130.3, 130.5, 163.5, 196.6 ppm ?
Answer:
The answer you are looking for is A
Answer:
Non polar covlant
Explanation:
Answer:
The gases will expand 8.2 L against the constant pressure of 710 torr.
Explanation:
Given that:
the original volume V₁ = 35 cm³ = 35 × 10⁻⁶ m³
Since the combustion of the mixture releases energy then :
the work W = - 775 J
Pressure = 710 torr
Since 1 torr = 133.322 Pa
710 torr = 94658.62 Pa
We all know that:
W = -PdV
-775 = - 94658.62 Pa ( V₂ - V₁ )
-775 = - 94658.62 ( V₂ - 35 × 10⁻⁶)
-775/ - 94658.62 = V₂ - 35 × 10⁻⁶
0.008187 = V₂ - 35 × 10⁻⁶
V₂ = 0.008187 + 35 × 10⁻⁶
V₂ = 0.008222 m³
The change in volume dV = V₂ - V₁
The change in volume dV = 0.008222 m³ - 35 × 10⁻⁶ m³
The change in volume dV = 0.008187 m³
To litres
The change in volume dV = 8.2 L
Thus, the gases will expand 8.2 L against the constant pressure of 710 torr.
CaSO4. It has 6 atoms while Fe2O3 has 5 atoms
Explanation:
Fe2O3 contains 2 atoms of Iron(Fe) and 3 atoms of Oxygen(O) = 2 + 3 = 5 atoms
CaSO4 contains 1 atom of Calcium(Ca), 1 atom of Sulphur(S) and 4 atoms of Oxygen(O) = 1 + 1 + 4 = 6 atoms