The table shows the number of boys and girls who have come to the playground. help pleaseOutcome Boys Girls
Frequency 35 40

What is the experimental probability that the next person who comes to the playground will be a girl?

A.8/15


B.1/2


C.7/15


D.2/5

Answers

Answer 1
Answer: The right answer for the question that is being asked and shown above is that: "A.8/15." The table shows the number of boys and girls who have come to the playground. the experimental probability that the next person who comes to the playground will be a girl is A.8/15

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Select all ratios that are in their simplest form.
4:24 28:15 3:13 18:30 12:14

Answers

Answer:

1. 28:15

2. 3:13

Step-by-step explanation:

The ratios above have no common factor.

4:24 .

Common factor : 4

18:30

Common factor : 6

12:14

Common factor : 2

Answer:

28:15

3:13

Step-by-step explanation:

The ratios 28:15 and 3:13 are in their simplest form, meaning that they cannot be simplified any further.

Meanwhile, the other 3 ratios are not in their simplest form and can still be simplified if they are divided by either 2 or 4.

Advantages and disavadtages for paying with checks

Answers

Advantages: when its paying by check you can earn credit history
Disadvantages: Mishandling of account and exceeded expenses can cause a refund check and bad credit

Compute the amount of interest earned in the following simple interest problem.A deposit of $1,600 at 6% for 180 days:

Answers

with 6% is 1,696. for 180 days, $305,280 
I=PRT
I=interest
P=principal
R=rate in decimal
T=time in yaers

365 days per year
t=180/365

given
P=1600
R=6%=0.06
T=180/365

I=1600*0.06*180/365
I=96*180/365
I=47.342

rounds to
Interst=$47.34

Find the polynomial f(x) of degree 3 has the following zeros
9, 0, -7

Answers

Answer:

x³ - 2x² - 63x

Step-by-step explanation:

Zeroes = 9 , 0 , -7

Factors = (x - 9) x (x + 7)

Polynomial = x (x - 9)(x + 7)

Polynomial = x (x² -2x - 63)

= x³ - 2x² - 63x

Final answer:

To find the polynomial f(x) of degree 3 with zeros 9, 0, and -7, we can use the zero-product property. The polynomial can be written as f(x) = (x-9)(x-0)(x+7), which simplifies to f(x) = (x-9)(x)(x+7). Expanding the expression and multiplying the remaining factors, we obtain f(x) = x^3 - 2x^2 - 63x.

Explanation:

To find the polynomial f(x) of degree 3 with the given zeros 9, 0, and -7, we can use the zero-product property. This property states that if a polynomial has a zero a, then (x-a) is a factor of the polynomial. Therefore, the polynomial can be written as:

f(x) = (x-9)(x-0)(x+7)

Simplifying further, we get:

f(x) = (x-9)(x)(x+7)

Expanding this expression, we have:

f(x) = (x^2 - 9x)(x+7)

Finally, multiplying the remaining factors, we obtain the polynomial:

f(x) = x^3 + 7x^2 - 9x^2 - 63x

= x^3 - 2x^2 - 63x

Learn more about Finding Polynomial with Given Zeros here:

brainly.com/question/34347327

#SPJ11

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1

f(x) = 2x2 – x + 1

f(x) = x2 + 2x – 1

f(x) = x2 – 2x + 1

Answers

The graph of which function has an axis of symmetry at x = -1/4 is :

f(x) = 2x² + x – 1

Further explanation

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

D = b² - 4 a c

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

Let us now tackle the problem!

An axis of symmetry of quadratic equation y = ax² + bx + c is :

\large {\boxed {x = (-b)/(2a) } }

Option 1 :

f(x) = 2x² + x – 1 → a = 2 , b = 1 , c = -1

Axis of symmetry → x = (-b)/(2a) = (-1)/(2(2)) = -(1)/(4)

Option 2 :

f(x) = 2x² – x + 1 → a = 2 , b = -1 , c = 1

Axis of symmetry → x = (-b)/(2a) = (-(-1))/(2(2)) = (1)/(4)

Option 3 :

f(x) = x² + 2x – 1 → a = 1 , b = 2 , c = -1

Axis of symmetry → x = (-b)/(2a) = (-2)/(2(1)) = -1

Option 4 :

f(x) = x² – 2x + 1 → a = 1 , b = -2 , c = 1

Axis of symmetry → x = (-b)/(2a) = (-(-2))/(2(1)) = 1

Learn more

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

The graph of function \boxed{f(x)=2x^(2)+x-1} has an axis of symmetry as \boxed{x=-(1)/(4)}.

Further explanation:

The standard form of a quadratic equation is as follows:

\boxed{f(x)=ax^(2)+bx+c}

The vertex form of a quadratic equation is as follows:

\boxed{g(x)=a(x-h)^(2)+k}

Axis of symmetry is the line which divides the graph of the parabola in two perfect halves.

The formula for axis of symmetry of a quadratic function is given as follows:

\boxed{x=-(b)/(2a)}

The first function is given as follows:

f(x)=2x^(2)+x-1

The above function is in standard form with a=2, b=1 and c=-1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(1)/(2*2)\n&=-(1)/(4)\end{aligned}  

The axis of symmetry of first function is x=-(1)/(4).

Express the function f(x)=2x^(2)+x-1 in its vertex form,

\begin{aligned}f(x)&=2x^(2)+x-1\n&=(√(2)x)^(2)+\left(2* √(2)x* (1)/(2√(2))\right)-1+\left((1)/(2√(2))\right)^(2)-\left((1)/(√(2))\right)^(2)\n&=\left(√(2)x+(1)/(2√(2))\right)^(2)-1-(1)/(8)\n&=\left[√(2)\left(x+(1)/(4)\right)\right]^(2)-(9)/(8)\n&=2\left(x-\left(-(1)/(4)\right)\right)^(2)-(9)/(8)\end{aligned}

The above equation is in the vertex form with a=2, h=-(1)/(4) and k=-(9)/(8).

Therefore, its axis of symmetry is given as,

\begin{aligned}x&=h\nx&=-(1)/(4)\end{aligned}  

The graph of function f(x)=2x^(2)+x-1 is shown in Figure 1.

The second function is given as follows:

f(x)=2x^(2)-x+1

The above function is in standard form with a=2, b=-1 and c=1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-((-1))/(2*2)\n&=(1)/(4)\end{aligned}  

The axis of symmetry of second function is x=(1)/(4).

The third function is given as follows:

f(x)=x^(2)+2x-1

The above function is in standard form with a=1, b=2 and c=-1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(2)/(2*1)\n&=-1\end{aligned}  

The axis of symmetry of third function is x=-1.

The fourth function is given as follows:

f(x)=x^(2)-2x+1  

The above function is in standard form with a=1, b=-2 and c=1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(-2)/(2*1)\n&=1\end{aligned}  

The axis of symmetry of fourth function is x=1.

Therefore, the function \boxed{f(x)=2x^(2)+x-1} has an axis of symmetry as \boxed{x=-(1)/(4)}.

Learn more:

1. A problem on graph brainly.com/question/2491745

2. A problem on function brainly.com/question/9590016

3. A problem on axis of symmetry brainly.com/question/1286775

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Functions

Keywords:Graph, function, axis, f(x), 2x^2+x-1, axis of symmetry, symmetry, vertex, perfect halves, graph of a function, x =- 1/4.

At noon, the minute and hour hands overlap. In how many hours will they overlap again?

Answers

24 hours

Because 24 hours equals 1 day or one rotation of the clock

Answer:

1 hour 5  9/20 minutes

Step-by-step explanation: